2180161
Veteran
Hi I think i have discovered a new method for 2x2. It is sort of like an ortega/petrus hybrid. First you solve a 1x2 block, and then using R and U face turn only, you can solve the first and second face, always bringing you to an ortega case with a bar.
If i am incorrect, or do not have this fully yet, please direct me to where it is.
Thank you!
If i am incorrect, or do not have this fully yet, please direct me to where it is.
Thank you!