interesting solve method for 7x7x7

panyan

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we solve the 7x7x7 by equating it to the 3x3x3 in the following way:



but would it also be possible to solve it in the way depicted below?



if we took this even further, could it be solved with the following method?



the way the numbers work is like this (in relation to the images above):



I AM IN NOW WAY LOOKING FOR A FLAMING, THIS IS PURELY FOR DISCUSSION
 
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Yes, it could, but the nature of the pieces makes reducing it to such groups very difficult.
 
Yea, it's kind of like trying to solve a 4x4 like a 2x2. It sounds nice, but it usually isn't a good speedsolving method. I don't own a 7x7 though...
 
For the 4x4, use slice turns to match up the centers, then 3 cycle the edges untill a 2x2. I've never tried it, but I might be able to get sub-10.
 
I suspect a "reason" why this kind of reduction is hard is that you're building 3-dimensional blocks. Note that the normal reduction only builds 2-dimensional blocks. Each 3-dimensional one is harder to build and harder to maintain, especially the last ones.
 
Building a 3x4 block is a bit difficult.

i agree, thats why this is posted in "puzzle theory", not the speedsolving bit :)
But it's not really puzzle theory, not even because of that. I'm actually moving this thread.

Anyhow, the overwhelming consensus on this among people who have some idea about methods is that it's highly impractical if you try it.
 
Building a 3x4 block is a bit difficult.

i agree, thats why this is posted in "puzzle theory", not the speedsolving bit :)
But it's not really puzzle theory, not even because of that. I'm actually moving this thread.

Anyhow, the overwhelming consensus on this among people who have some idea about methods is that it's highly impractical if you try it.

the whole point of this thread is that it is something interesting and not to be taken as an actual method for solving (because of its immense impracticality), which is why i didnt post it in the speedsolving section, but, seeing as your a super mod, do as you see fit.
 
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