I Became A Sub 10 Cuber (Not Really Tho)

[JDAW6]

Ther is a big difference betwren an u perm anf a f perm

 

[Kaedenthecuber]

ive seen faking even worse than this

 

[JDAW6]

ive seen faking even worse than this

Its not i got 5 lucky scambles and did them

 

[Kaedenthecuber]

no worries people are just suspicious thats all
just do another sub 10 ao5 with video proof
it cant be that hard for you since you are already sub 10

 

[JDAW6]

no worries people are just suspicious thats all
just do another sub 10 ao5 with video proof
it cant be that hard for you since you are already sub 10

My pb ao5 is 9.944 wtf

 

[Discomantis]

Huh, im sorryy. But my brain doesnt understand

Here are the times needed for each step for a sub 10:

Cross: 1
F2L: 5
OLL: 1.75
PLL: 2


If you can consistently output that, then you are considered a sub 10 solver.


Now, in a competition where you solved your last F2L pair as well as OLL and PLL, you averaged 8.5.


However, in order for you to get a sub 10, you need to average this for last slot + last layer.

(F2L time * 0.25) + OLL time + PLL time = 5 seconds




In other words: You need to shave off 3.5 seconds off your last layer for a sub 10, assuming everything else is sub 10. That means you need a PLL or an OLL skip and be at a better than sub 10 pace for the ENTIRE rest of the solve for a sub 10 solve.

And for an average that is sub 10, you need that four times.

 

[Kaedenthecuber]

My pb ao5 is 9.944 wtf

pb is not average

 

[JDAW6]

Here are the times needed for each step for a sub 10:

Cross: 1
F2L: 5
OLL: 1.75
PLL: 2


If you can consistently output that, then you are considered a sub 10 solver.


Now, in a competition where you solved your last F2L pair as well as OLL and PLL, you averaged 8.5.


However, in order for you to get a sub 10, you need to average this for last slot + last layer.

(F2L time * 0.25) + OLL time + PLL time = 5 seconds




In other words: You need to shave off 3.5 seconds off your last layer for a sub 10, assuming everything else is sub 10. That means you need a PLL or an OLL skip and be at a better than sub 10 pace for the ENTIRE rest of the solve for a sub 10 solve.

And for an average that is sub 10, you need that four times.

In that comp i got an aberage last layer in ny sub 10 pb average i got u perms and easy f2l

 

[Kaedenthecuber]

@JDAW6 just because your pb average is sub 10 doesnt mean you are already sub 10
theres a difference yk

 

[JDAW6]

@JDAW6 just because your pb average is sub 10 doesnt mean you are already sub 10
theres a difference yk

Ik if u saw the third post in the thread u would know why i said this

 

[cubenerd74]

In that comp i got an aberage last layer in ny sub 10 pb average pli got u perms and easy f2l

How many uperms did you exactly get?

 

[JDAW6]

I ate dessert i went to sleep i woke up i went to the toilet and i am wtaching tv i cant remember that long

 

[JDAW6]

But ik solve 5 was u perm and solve 3 was a y perm and solve 4 was a Rb perm i think

 

[Discomantis]

That means you need a PLL or an OLL skip and be at a better than sub 10 pace for the ENTIRE rest of the solve for a sub 10 solve.

Adding on to this post, here is the math behind the odds of that occurring:

1/216 (odds of OLL skip) + 1/72 (odds of PLL skip) + 1/15552 (odds of LL skip) = About a 1/54 chance of getting a skip


Using a binomial distribution calculator, the odds of getting a skip more than 3 times over the course of 5 solves is a one in 57 million chance.

Yes, a one in 57 million chance.

Oh and did I mention that you also have to be around sub 10 pace for the entire rest of the 4 solves?

 

[JDAW6]

Adding on to this post, here is the math behind the odds of that occurring:

1/216 (odds of OLL skip) + 1/72 (odds of PLL skip) + 1/15552 (odds of LL skip) = About a 1/54 chance of getting a skip


Using a binomial distribution calculator, the odds of getting a skip more than 3 times over the course of 5 solves is a one in 57 million chance.

Yes, a one in 57 million chance.

Oh and did I mention that you also have to be around sub 10 pace for the entire rest of the 4 solves?

I got a 11 and then 10 then a low 9 then an 8 then a high 9 good enought?

 

[NebraskanSpeedsolver]

idk what to say
a little sus ig

 

[Discomantis]

I got a 11 and then 10 then a low 9 then an 8 then a high 9 good enought?

That could be possible too.

Adding on to this post, here is the math behind the odds of that occurring:

1/216 (odds of OLL skip) + 1/72 (odds of PLL skip) + 1/15552 (odds of LL skip) = About a 1/54 chance of getting a skip


Using a binomial distribution calculator, the odds of getting a skip more than 3 times over the course of 5 solves is a one in 57 million chance.

Yes, a one in 57 million chance.

Oh and did I mention that you also have to be around sub 10 pace for the entire rest of the 4 solves?

Also you could (most likely would) make up for times in other areas if you actually got a sub 10 average

 

[JDAW6]

Also you could (most likely would) make up for times in other areas if you actually got a sub 10 average

Proofread this actually it is so hard to read

 

[NebraskanSpeedsolver]

Proofread this actually it is so hard to read

he means that if you actually do the ao5 correctly you wont waste time you could be using to do other events (if I am wrong plz correct me)

 

[cubenerd74]

Adding on to this post, here is the math behind the odds of that occurring:

1/216 (odds of OLL skip) + 1/72 (odds of PLL skip) + 1/15552 (odds of LL skip) = About a 1/54 chance of getting a skip


Using a binomial distribution calculator, the odds of getting a skip more than 3 times over the course of 5 solves is a one in 57 million chance.

Yes, a one in 57 million chance.

Oh and did I mention that you also have to be around sub 10 pace for the entire rest of the 4 solves?

Are you sure you did your math right? Because I got 1 in 167K(still very low)

Ther is a big difference betwren an u perm anf a f perm

That's true, but I don't think that difference would be more than 3 seconds.