Alg counting during 3blind solving

[abunickabhi]

I want to know how much skill and practice does it take to immediately know the number of 3-style algs executed just after we finish our solve.

For my skill level, I generally do the scramble again on a solved cube and trace again to check the number of algs I executed.
I know a few top solvers can immediately guess the number of algs they executed or have a strong intuition based on the exec flow and exec time.

Is it possible to do instant alg counting during a 4blind solve as well?

 

[Renslay]

I'm confused. Isn't the number of algs coming directly from the number of letters of the memorization? For example, if I know I have 10 letters for the edges, I know it will be 5 algorithms to solve the edges. That also means I know the number of algs before the solve.

 

[abunickabhi]

I'm confused. Isn't the number of algs coming directly from the number of letters of the memorization? For example, if I know I have 10 letters for the edges, I know it will be 5 algorithms to solve the edges. That also means I know the number of algs before the solve.

Yes the algs can be counted from the letter pairs.

My point is that do we count the letter pairs consciously during a solve, or do we have to check the scramble again to count the number of algs.

Top solvers can instinctively tell the number of algs by the fancy stuff they did to avoid extra algs, and also by gauging the flow of their 3s exec.

 

[Renslay]

I mean, don't you have to count anyway? Otherwise it's quite hard to tell if you missed one or two pieces... And it's even more true for big cubes.
I'm counting, and following the 7/11 rule:
corner letters to memo = 7 + cycle break - solved cases
edge letters to memo = 11 + cycle break - solved cases

 

[Jorian Meeuse]

I mean, don't you have to count anyway? Otherwise it's quite hard to tell if you missed one or two pieces... And it's even more true for big cubes.
I'm counting, and following the 7/11 rule:
corner letters to memo = 7 + cycle break - solved cases
edge letters to memo = 11 + cycle break - solved cases

When you get faster it's quite easy to know you've had everything without counting, and often even without looking at all pieces consciously.

I personally don't know alg count after a solve, but I'm sure it's not hard to figure out based on edge audio rhythm