Pedro
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- Mar 17, 2006
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So, Karthik asked me for some examples of how I'm solving the edges, with no EO step
I'll try to explain briefly how it's done (not that hard at all) and give some examples, and if anyone wants, you can give me a scramble and I'll show how I'd solve
ok, well, what I'm doing is basically cycling stickers, not edge pieces
at the commom used bld method with 3 cycles, you set up the edge pieces, using some restrictions in the setup moves (L2/R2 or F2/B2, usually)
so, you're kinda "tied" to some mechanical setups
this can be good, as you already "know" which setup to use for each edge, but also can be bad, as kinda limits you on some easy cases
so, I just follow the stickers, starting from UF, and set them up so I can use the "normal" edge cycles and some others, like M' U M U2 M' U M and variations
this is much like M2, just you set up and solve 2 pieces at once (most of the time, of course)
so, let me give some examples:
first, I'll number the edge cycles, so I don't have to repeat them all the time
R2 U' R' U' R U R U R U' R -> 1
R' U R' U' R' U' R' U R U R2 -> 2
R U' R U R U R U' R' U' R2 -> 3
R2 U R U R' U' R' U' R' U R' -> 4
1 - scramble: R F2 U' B2 D F2 B L2 F2 R' F2 B U2 F L R' B' U B' D2 R' D B2 R' D'
(I won't show how I solve corners, as I use the "normal" CO, CP style, and that's not the purpose of the thread
)
so, firt cycle: UF -> UR -> BD
B' L (3) L' B
UF -> DR -> LF
R2 U' F y (3) y' F' U R2
UF -> BR -> DL (solves UF)
R' L2 (3) R L2
UL -> FD -> UB
F' R (1) R' F
UL -> FR -> LB (solved!)
R B' (1) B R'
/*----------------------------------------------------*/
2 - scramble: U2 D2 L2 F2 L2 D U R' D2 R' B U' D B' U B L F U' D2 R2 F' D2 U2 R
UF <-> UR (leaves UF flipped)
UL -> FL -> FD
U2 l' (3) l U2
UL -> BR -> UB
R' (1) R
UL -> DR (leaves UL flipped)
here, I'd do D' B2 (Z perm) B2 D
and flip UF and UL: L' B' (M' U M' U M' U2 M U M U M U2) B L
(next unsolved edge) BL -> RF -> LD
(hard one
) F' L B' y (1) y' B L' F
and I'm left with BL <-> DB for parity
I ended with UFR <-> DFL for corners...so...hmm...let me see...
D' B2 (T) B2 D
B2 U' R' (H) R U B2
(probably not the best solution, but I like to keep things simple
)
/*------------------------------------------------*/
3 - scramble: D U2 B' U2 B' R' D' F' B2 R' B2 L2 U' F2 R B' F L2 U R' U2 F U2 F L2
UF <-> FR (UF flipped)
UL -> DR -> FL
R2 U L' y' (4) y L U' R2
UL -> LD -> BU
B' R' D' M (2) M' D R B
UL -> BD -> RU
M R' F' y (2) y' F R M'
UL -> BR -> DF
R' M2(or F2) (1) M2 R
so I'm left with UF -> FR for parity, and LB flipped
I ended with UFL - DFR
so...
D B2 (left T) B2 D'
U R (H) R' U'
B' (flip 2 edges) B
/*--------------------------------------------------*/
so, I hope that helps
as I said, if you want you can give me a scramble and I'll show how I'd solve it
I'll try to explain briefly how it's done (not that hard at all) and give some examples, and if anyone wants, you can give me a scramble and I'll show how I'd solve
ok, well, what I'm doing is basically cycling stickers, not edge pieces
at the commom used bld method with 3 cycles, you set up the edge pieces, using some restrictions in the setup moves (L2/R2 or F2/B2, usually)
so, you're kinda "tied" to some mechanical setups
this can be good, as you already "know" which setup to use for each edge, but also can be bad, as kinda limits you on some easy cases
so, I just follow the stickers, starting from UF, and set them up so I can use the "normal" edge cycles and some others, like M' U M U2 M' U M and variations
this is much like M2, just you set up and solve 2 pieces at once (most of the time, of course)
so, let me give some examples:
first, I'll number the edge cycles, so I don't have to repeat them all the time
R2 U' R' U' R U R U R U' R -> 1
R' U R' U' R' U' R' U R U R2 -> 2
R U' R U R U R U' R' U' R2 -> 3
R2 U R U R' U' R' U' R' U R' -> 4
1 - scramble: R F2 U' B2 D F2 B L2 F2 R' F2 B U2 F L R' B' U B' D2 R' D B2 R' D'
(I won't show how I solve corners, as I use the "normal" CO, CP style, and that's not the purpose of the thread
so, firt cycle: UF -> UR -> BD
B' L (3) L' B
UF -> DR -> LF
R2 U' F y (3) y' F' U R2
UF -> BR -> DL (solves UF)
R' L2 (3) R L2
UL -> FD -> UB
F' R (1) R' F
UL -> FR -> LB (solved!)
R B' (1) B R'
/*----------------------------------------------------*/
2 - scramble: U2 D2 L2 F2 L2 D U R' D2 R' B U' D B' U B L F U' D2 R2 F' D2 U2 R
UF <-> UR (leaves UF flipped)
UL -> FL -> FD
U2 l' (3) l U2
UL -> BR -> UB
R' (1) R
UL -> DR (leaves UL flipped)
here, I'd do D' B2 (Z perm) B2 D
and flip UF and UL: L' B' (M' U M' U M' U2 M U M U M U2) B L
(next unsolved edge) BL -> RF -> LD
(hard one
and I'm left with BL <-> DB for parity
I ended with UFR <-> DFL for corners...so...hmm...let me see...
D' B2 (T) B2 D
B2 U' R' (H) R U B2
(probably not the best solution, but I like to keep things simple
/*------------------------------------------------*/
3 - scramble: D U2 B' U2 B' R' D' F' B2 R' B2 L2 U' F2 R B' F L2 U R' U2 F U2 F L2
UF <-> FR (UF flipped)
UL -> DR -> FL
R2 U L' y' (4) y L U' R2
UL -> LD -> BU
B' R' D' M (2) M' D R B
UL -> BD -> RU
M R' F' y (2) y' F R M'
UL -> BR -> DF
R' M2(or F2) (1) M2 R
so I'm left with UF -> FR for parity, and LB flipped
I ended with UFL - DFR
so...
D B2 (left T) B2 D'
U R (H) R' U'
B' (flip 2 edges) B
/*--------------------------------------------------*/
so, I hope that helps
as I said, if you want you can give me a scramble and I'll show how I'd solve it