3 cycles without edge orientation - examples

Pedro

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So, Karthik asked me for some examples of how I'm solving the edges, with no EO step

I'll try to explain briefly how it's done (not that hard at all) and give some examples, and if anyone wants, you can give me a scramble and I'll show how I'd solve


ok, well, what I'm doing is basically cycling stickers, not edge pieces

at the commom used bld method with 3 cycles, you set up the edge pieces, using some restrictions in the setup moves (L2/R2 or F2/B2, usually)

so, you're kinda "tied" to some mechanical setups

this can be good, as you already "know" which setup to use for each edge, but also can be bad, as kinda limits you on some easy cases

so, I just follow the stickers, starting from UF, and set them up so I can use the "normal" edge cycles and some others, like M' U M U2 M' U M and variations

this is much like M2, just you set up and solve 2 pieces at once (most of the time, of course)

so, let me give some examples:

first, I'll number the edge cycles, so I don't have to repeat them all the time :)

R2 U' R' U' R U R U R U' R -> 1
R' U R' U' R' U' R' U R U R2 -> 2
R U' R U R U R U' R' U' R2 -> 3
R2 U R U R' U' R' U' R' U R' -> 4

1 - scramble: R F2 U' B2 D F2 B L2 F2 R' F2 B U2 F L R' B' U B' D2 R' D B2 R' D'

(I won't show how I solve corners, as I use the "normal" CO, CP style, and that's not the purpose of the thread :D)

so, firt cycle: UF -> UR -> BD
B' L (3) L' B

UF -> DR -> LF
R2 U' F y (3) y' F' U R2

UF -> BR -> DL (solves UF)
R' L2 (3) R L2

UL -> FD -> UB
F' R (1) R' F

UL -> FR -> LB (solved!)
R B' (1) B R'

/*----------------------------------------------------*/

2 - scramble: U2 D2 L2 F2 L2 D U R' D2 R' B U' D B' U B L F U' D2 R2 F' D2 U2 R

UF <-> UR (leaves UF flipped)

UL -> FL -> FD
U2 l' (3) l U2

UL -> BR -> UB
R' (1) R

UL -> DR (leaves UL flipped)
here, I'd do D' B2 (Z perm) B2 D
and flip UF and UL: L' B' (M' U M' U M' U2 M U M U M U2) B L

(next unsolved edge) BL -> RF -> LD
(hard one :() F' L B' y (1) y' B L' F

and I'm left with BL <-> DB for parity
I ended with UFR <-> DFL for corners...so...hmm...let me see...

D' B2 (T) B2 D
B2 U' R' (H) R U B2
(probably not the best solution, but I like to keep things simple :))

/*------------------------------------------------*/

3 - scramble: D U2 B' U2 B' R' D' F' B2 R' B2 L2 U' F2 R B' F L2 U R' U2 F U2 F L2

UF <-> FR (UF flipped)

UL -> DR -> FL
R2 U L' y' (4) y L U' R2

UL -> LD -> BU
B' R' D' M (2) M' D R B

UL -> BD -> RU
M R' F' y (2) y' F R M'

UL -> BR -> DF
R' M2(or F2) (1) M2 R

so I'm left with UF -> FR for parity, and LB flipped

I ended with UFL - DFR
so...
D B2 (left T) B2 D'
U R (H) R' U'
B' (flip 2 edges) B

/*--------------------------------------------------*/

so, I hope that helps

as I said, if you want you can give me a scramble and I'll show how I'd solve it
 
oh nice, that's the method i'm looking for. i'm trying to shift from piece by piece (without edge orientation) to 3-cycle (also without the edge orientation) coz it's an additional burden during the memorization.
 
If you had a cycle like UF -> LF -> RF, do you ever see. during your solve, that by lookng at the opposite stickers (FU, FL, FR), they are all on the same face and can be cycled with no setup, or do you always cycle the stickers you've memorized (in this case maybe the setup could be U F' U F2)
 
If you had a cycle like UF -> LF -> RF, do you ever see. during your solve, that by lookng at the opposite stickers (FU, FL, FR), they are all on the same face and can be cycled with no setup, or do you always cycle the stickers you've memorized (in this case maybe the setup could be U F' U F2)

well, in cases like that, I "see" that the 3 stickers are at the "outside" part of the F layer, so, yes, I cycle them on F face

I actually do it a lot, like if I have UF, LF, DR or DB, DL
 
Ugh somebody asked how to do this yesterday in Mackys Cbox and I didnt think of this :( I've never put much thought into 3 cycle without orientation.
 
Something else you can do is set them up onto the same face, and then apply M, R' F', or L F to turn it into a standard 3 cycle. Its like normal 3 cycle, but with 2 setup phases
 
1 - scramble: R F2 U' B2 D F2 B L2 F2 R' F2 B U2 F L R' B' U B' D2 R' D B2 R' D'

Cycling from UR
UR -> RB -> LU: L'B2L S' L'B2L S
UR -> DF -> BU: D R2 DM'D' R2 DMD2
UR -> RF -> FL: E' L'U2L E L'U2L
UR -> BD -> FL: U2L'U M U'LU M' U
UF -> BL -> DL: L' D'M2D L D'M2D
Orient DL and DR: x2y M'UM'UM'U2MUMUMU2 x2y
 
Scramble 2: U2 D2 L2 F2 L2 D U R' D2 R' B U' D B' U B L F U' D2 R2 F' D2 U2 R

UL -> FL -> FD: F' D'S'D F D'SD
UL -> BR -> UB: U' LE2L' U LE2L'
UL -> DR -> DL: S'R2S L2 S'R2S L2
Weird trick: The next cycle from the buffer is ugly. So I'm turning (12345) into (234)(125)
BD -> LB -> FR: F2EF' D2 FEF' D2 F'
UL -> BD -> DL: L2 UMU' L2 UM'U'
Orient Edges: UM'UM'UM'U2MUMUMU

Parity fix at the end ^_^

Ugh that was bad actually :P
 
does anyone just set them up with normal 3 cycle restrictions and have 3 algorithms and their mirrors for all 3 cycles with edge flips.
 
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