Sep 27, 2009 #1 ben1996123 Banned Joined May 17, 2009 Messages 4,972 Location Ponyville WCA ID 2009WHIT01 YouTube Visit Channel Last edited by a moderator: Apr 7, 2016
Sep 27, 2009 #2 riffz Veteran Joined Oct 3, 2008 Messages 2,068 Location Toronto (Canada) WCA ID 2009HOLT01 YouTube Visit Channel If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less.
If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less.
Sep 27, 2009 #3 ben1996123 Banned Joined May 17, 2009 Messages 4,972 Location Ponyville WCA ID 2009WHIT01 YouTube Visit Channel riffz said: If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less. Click to expand... I already know ortega, and I average 12 seconds with it.
riffz said: If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less. Click to expand... I already know ortega, and I average 12 seconds with it.
Sep 27, 2009 #4 E Escher Babby Joined Jul 23, 2008 Messages 3,373 WCA ID 2008KINN01 YouTube Visit Channel ben1996123 said: riffz said: If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less. Click to expand... I already know ortega, and I average 12 seconds with it. Click to expand... Lol, if you practiced it then you'd be sub 5, no problem.
ben1996123 said: riffz said: If you're already that fast, why don't you learn 2 extra algs and learn ortega? Impressive, none the less. Click to expand... I already know ortega, and I average 12 seconds with it. Click to expand... Lol, if you practiced it then you'd be sub 5, no problem.
Sep 27, 2009 #5 MTGjumper Veteran Joined Jun 21, 2008 Messages 2,212 Location Bath/Notts WCA ID 2008CRAW01 YouTube Visit Channel How can you average so much slower with Ortega. It is no more difficult than a normal "Fridrich" based method.
How can you average so much slower with Ortega. It is no more difficult than a normal "Fridrich" based method.