2 and 1/2 look LL

[Lotsofsloths]

Ok, I was wondering if I could use this, well, I know I CAN, but is this a good idea when transitting from 3 look to 2 look LL.

For those of you that don't know, 3 looks is solving the LL in 3 parts, OLL edges, OLL corners, PLL.

2 look is OLL, PLL.

2 and 1/2 look is 3 steps also, but heres how it works:

Ok, you just finish F2L, you look on the top if you see 4 edges, goto corners, if you see 2 edges, do the edge alg, then one of the corner OLLs, if you see no edges, this is the important part, then you preform a OLL and Orient the whole LL Because when doing 3 look, if you have no edges oriented, then you have to preform 3 algorithms, which can be very timely, so forth, learn the 7 OLLs where there are no edges oriented already.


Sorry if you don't understand it, just post what you don't understand and I'll try to explain as best as possible.

 

[joey]

learn the 7 OLLs where there are no edges oriented already.

So you will miss out one of the OLL's with no-edges oriented for some reason?

I don't understand why you are posting this, no offence. You don't need advice or anything. Just learn all edges, then no-edges, and then learn the rest.

 

[Jason]

that's how and where I started learning pure Fridrich

 

[amateurguy]

That actually sounds like a good idea. I'm currently doing a 3-look LL too and I'm always irritated when I get a no-edge last layer. But normally, during my last F2L move, I would try to predict whether it would end up with a no-edge layer. If it does, I try to do an edge control. That is...if I'm quick enough to react to it.

Still, it should work for those who want to transit from 3LLL to 2LLL!

 

[Lt-UnReaL]

I'm pretty sure everyone has done it this way when they went from 3LLL to 2LLL. :/

 

[AvGalen]

learn the 7 OLLs where there are no edges oriented already.

And then learn number 8

 

[masterofthebass]

Now what case would that be Arnaud?

 

[Johannes91]

The are one or two cases with 3 mis-oriented corners, depending on how you count.

 

[AvGalen]

For OLL there are 7 cases with 4 edges correctly oriented that are unsolved. The "OLL-solved" case would be number 8.

Those same 7 cases are there with 4 edges unsolved. But case number 8 would be there too.