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Yeah, it isnt worth to do roux when you can get a easy xcross

Hey , DG! First , thanks for the suggestions, you really are right about the problems in this method , and we will start rearanging the method as you proposed (i really like the idea) . We will just have to work on the idea of l5c as it will likely have 500 algs this way (but i have some ideas...

join the discord server , it has everything explained well :)

ok , right now i dont have access to a cube , but ill send it to you asap also everyone , the subset will be called COP+ and we still accept people to help us make it

yeah , thats with full f2l right(i count that as a subset)? if you use intuitive you get about 60-70 ( or im just bad) . I did 100 solves of each method and the difference was about 5 moves (look at this as cfop-1 pair)

Ok , i understand all your alrguments , but let me tell you my perspective on the "not so good" things (i)i completely agree with that, but thats not always possible. When i do end up putting the edge in aswell (X cross) i do continue on with cfop. (ii) I already answered that (look up)...

thanks for the support. Roux and zz are maybe better than C3CE , but there arent as many tutorials on the net for them, and as C3CE is similar to cfop, there are lots of tutors to help you improve 48 isnt the movecount, it is the algorithm count xD but this method does actually have a lower...

if thats the case (which is kinda rare) we use edge control which takes about 3 moves (sorta keyhole) which is still more efficient than making a full f2l pair. the algs are mostly short and fingertrickable (other than 2 5-cycles which are like g perms ) i used a solver to solve the cross + 1...

Hello, My name is Luka and i'm the official founder of the C3CE method.This is a method developed by me and 5 of my friends which may potentially be faster than CFOP. The method has 4 steps (that ill further explain later in the thread). If you do VHLS intuitively the alg count is lower than...

Hey, i just logged on to the forum for the first time and figured i should introduce myself :) My name is Luka Jankovic and my wca id is 2018JANK01. I have only been to one competetion but i average about 18 seconds. I also have yt channel that i spend a lot of time and effort into (not last 2...