SpeedSolving Puzzles Community

And how would you qualify for next round? Everyone that gets a success passes?
And pls do it, it sounds fun

Cool idea, maybe a time limit would be good to make sure it doesn't get too long(like 30 mins to make sure everybody has a fair chance)

@CubeLite yeah, everybody who gets a success passes.

@bldcuber314 30 minutes sounds good, even though I don’t think somebody is willing to spend more than half an our on a forum comp

Btw, 1x1 won’t count as a usable cube for this comp (sorry @1x1 wr holder!)

Nice, but I have 2 more questions
1. We can only choose one of the 11 WCA puzzles?
2. Wdym tie? How could we tie if the advancement req is to get a success

And if you want to host it, I would gladly help you with it

@CubeLite if nobody makes the next round then there's a tie

Wait but then what times would you use as a tiebreaker if nobody got a success

If neither of them would have had a shared success in an event, that would just be a tie.

(1/2) I’ll give you an example of the system I thought of:
Competitior A:
R1: 2x2 (14.9)
R2: Pyra (27.8)
R3: Skewb (34.6)
R4: 3x3 (1:54.3)
R5: 4x4 (DNF)

Competitor B:
R1: 2x2 (15.8)
R2: 3x3 (56.2)
R3: Pyra (1:23.1)
R4: 4x4 (4:37.6)
R5: 5x5 (DNF)

(2/2) They don’t both have successes in 4x4 and Skewb, therefore these events won’t be counted.
Competitor B was faster at 3BLD, for that they get one point. Competitor A was faster at Pyra and 2x2, they get 2 points and therefore win the tie.
This system does give big cubes a little disadvantage, but it’s the best I could do.

@CubeLite as for your second question, I guess it’s the 11 official cubes + some unofficial events I’ll announce that are usable for this comp (like redi cube, mirror cube,…)

I think just wca events is the best option. Also bc of the big cube disadvantage maybe a tiebreaker can just be repeating the round until somebody gets a success(up until a certain point, then you can just declare joint winners)