Recent content by Rouxster

hi everyone, I have made a recon video of the solve, you can check it out:).

Actually the standard alg without a regrip is awkward too because of the 2 pinch U's, so I think its mirror from the back is better. R' U2 R U (R' U' R U )x2 R' U R. But the RUD one is waaaay faster for me, so I'm gonna stick with it. and it's 4 moves shorter too.

It goes like this: R' D R' D R' U' R D' R D' R sorry for the bad video quality. Hope you like the alg!

Here are cll algs for the cx variant. These algs preserve EO and ignore the FR and FD edge.CXCOLL

Yeah I completely agree. Tcmll and Acmll are definitely more useful.Plus LSE move count can easily be reduced by using MC, UFUB and EOLR.

Mine is also broken in , I've used it for 10 months. I think it's all about personal preference. Mine pops a lot when it's looser and becomes really slow for me. when it's tighter

I personally don't recommend the 4×4 , especially if you have a light turning style. Magnets are very strong and it pops very often.

I just started learning CSP using Cale's tracing method. (-5,6)/ (2,5)/ (3,0)/ (1,-2)/ (-4,-1)/ (3,0)/ (-5,-2)/ (2,-3)/ (-3,-3)/ (0,-1)/ (-4,0)/ (2,0) I end up with odd parity on this scramble but solving the case with scallop/scallop, which is the odd alg still gives parity at the end. Is the...

z2 F' L F// face U F R U' R2 F' R U R' F' R //EG- 1 Next:F R U R' U R2 U F' U'

I think that's the one I've written.

Real name -it's Aditya Pathak

That would be nice! Here are the algs for the most basic subset- where the front two "f2l" pairs are in swapped positions.

R U R' U R U' R U2 R' //co, separation skipped. Next:R' U' R' U2 R' U2 R2 U2 R' U R2 U2 R U2

Yeah it is sort of like that, but it is an easier version cause the algorithm count is less and recognition is exactly like cmll.

EG 1 ON 3 by 3 on the wiki, it says that EG 1 is particularly useful for LMCF and and some other method but I think it could be REALLY useful for roux. keeping the front two pairs swapped can save many moves during blockbuilding, especially if there are many free pairs. Then we can solve the...