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5BLD and PandaCuber's Roux tutorial

Scramble: R2 F2 L2 F D2 R2 B' D2 L2 R2 B2 D' L' F' R D' R' D' U' B' D'
do this square: F D' F'

challenge: solve the rest of the first block and one of the (matching) second block squares in under 10 moves.

9 or 10 moves:
r' U r2 U' R' U' R U2 B optional: R
 
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I don't find it hard (dont mean to boast). It just takes a bit o' practice. Here's another very difficult exercise for you to try...:
Also let's liven things up a wittle. Here's a scramble: R2 F2 L2 F D2 R2 B' D2 L2 R2 B2 D' L' F' R D' R' D' U' B' D'

do this square: F D' F'

now here's the challenge: solve the rest of the first block and one of the (matching) second block squares in under 10 moves. Post and let's see who gets it first. inb4 nobody bothers to try.

If you get something like 10 moves do post too.

I spent like 15 minutes trying to finish the first block and the second block in under ten moves. Super frustrated lol.

Here's my (soclose) solution.
R U2 M' B'
r' U r' U F R F'
 
The idea is there but it doesn't work. In fact you used a similar idea to my 7 mover. See if you can find it :)

Oops I messed up the notation. I fixed it and put it in a spoiler in my original post.
 
I don't find it hard (dont mean to boast). It just takes a bit o' practice. Here's another very difficult exercise for you to try...:
Also let's liven things up a wittle. Here's a scramble: R2 F2 L2 F D2 R2 B' D2 L2 R2 B2 D' L' F' R D' R' D' U' B' D'

do this square: F D' F'

now here's the challenge: solve the rest of the first block and one of the (matching) second block squares in under 10 moves. Post and let's see who gets it first. inb4 nobody bothers to try.

If you get something like 10 moves do post too.

I forgot what I was doing partway through. I got 21 for the pair and the entire second block... That's pretty bad, isn't it?
But the good news is that I just learned the CMLL I got and did it correctly!

EDIT: Tried again and got 13 for the pair and SB square.
 
Thom (and cubenovice), the only reason why I counted the moves to the solved position is because last time I figured 9 is the maximum you will ever need to solve to its solved position. (well not really figured out but you know what i mean, you were there when we were investigating)
 
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Thom (and cubenovice), the only reason why I counted the moves to the solved position is because last time I figured 9 is the maximum you will ever need to solve to its solved position. (well not really figured out but you know what i mean, you were there when we were investigating)

I agree in counting the last move in your solution :)
In mine it is still optional :)

Could you explain to me why it's necessary to have all the pieces below the U layer? It seems kinda arbitrary to me.

For me “anywhere in the SB space” as Kirjava eloqently put it :) is a cube state from which you can continue building the block with the typical U M R r moves without messing up the block.
With block pieces still in U you do not have this full range of freedom and the block is not in a good position to add the last pair.

Inb4 exceptions of ending with a cube state that requires something along the lines of L F L’ R2 to finish the 2nd block....
 
I agree in counting the last move in your solution :)
In mine it is still optional :)

Sorry, did you understand what I just said? The maximum number of moves you will ever need optimally is 9 for when you are solving the square to its solved position. You can go on about non matching blocks in FMC (this is for speed-solving though but w/e who cares about rules) if you have 9 moves and need one extra to put it into its solved position you can guarantee that you haven't been optimal when you are not solving NM blocks. Am I misunderstanding you?
 
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5BLD, you are right in counting to solved position.

In my response to your post I got a bit side-tracked cause already thinking about my comment to Jonny.

Can I has a next challenge please?

Edit:
your DR first centric thinking lets you forget that you can leave the FR square floating R' away ZZ style

Why call it ZZ style? Isn't building this square just as much Roux as it is ZZ?
 
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