|Information about the method
||Few to many
||More than 20, that's for sure
- Solve 2 1X1X3 lines opposite of each other on d layer
- Solve LL corners using CMLL (step1/2 can be together as solving all the corners plus two opposite edges in the D layer)
- Solve Equator edges that would make up the edges in the roux blocks in pairs of two using the B and F layers
- Align the roux block edges to their spots
- If LL corners oriented only, after LSE perform a PLL.
- Solve two 1x1x3 blocks on the D layer opposite from each other (also referred to as "lines")
- Orient the last layer corners
- Alternatively, completely solve the last layer corners by using CMLL in order to skip step 6
- Since the lines are completed, now the solver doesn't have to use the D Layer. Now pair up two E Layer edges along with its corresponding center to create a line in the U Layer. Place this in the B layer, pointing up and down.
- The line created is recommended to be the front sticker color of the two corners on the D layer facing the solver
- continued: The E Layer Edges line (Which is in the B layer) is facing up and down. If an M2 move is performed, then the E Layer Edges line should be in the F Layer. Check the bottom edge of that line in the back and observe the color of it. Using that scenario, find one of the two corners facing the solver with that orange color on the right or left side and perform an F move to turn that corner to the U layer, so that that corner has orange facing up and its opposite corner has red facing down. Next, perform an M2, so that the edges line lines up with the corners (orange matches orange and so on). Then undo that F move to have placed the line in the E Layer and matched them with their corners (to make two pseudo F2L Pairs).
- Perform an E2 or fat U2 to put the solved edges line to the back, leaving the front of the E Layer open. While doing so, match the red and orange centers to the sides of the line. Then Perform step 3 (not continued) to make another line with the opposite color of the original placed line, which would now be a green line instead of a blue line. Don't worry about the blue center anymore and allow for the green line to go in the B layer like the original blue line did before entering the E Layer.
- Instead of using the M2 move aligning the E Layer Edges line to the F Layer corners, this step will match the Edges line to the side colors of the pairs already placed that are in the B Layer. When turning the F layer to put in the green line, the undo of the F Layer turn will determine if the edges are lined up properly, so if the side color of the back left edge is red, and the bottom back color of the green line edge is orange then an F' move should be used to do the M2 move so that when the orange green edge of the line comes to the top, the Undo move which is an F will push the orange to the other side and the red edge will line up with the red edge of the blue line in the back.
- Perform an E move or a fat U move to finally line up all of the E Layer edges to their spots. After the alignment, the M Layer should still be free to turn.
- Solve the LSE (Last Six Edges) by using M and U moves.
- If the solver chose to also permute the Last Layer corners along with the orientation in step 2, then after using LSE in step 6, the cube will be solved.
- If the solver chose not to permute the Last Layer corners, then after using LSE or a form of it, the solver will have to perform a PLL or a specific CPLL, depending on the permutation of the last layer edges, and finally solve the cube.
||This page is under construction!|
One or more of our members are currently working on this page.
Come back in a few days and it will hopefully be completed by then.
There are algs currently being worked on by me (Alex) for steps 3 and 4 to fix the E-Layer Edges that are more convenient.