Difference between revisions of "Talk:Last Four Corners"

From Speedsolving.com Wiki
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The following four cases are mirror + inverses of the first so you only need '1 alg' for all.
+
For the following cases mirror and inverse are the same.
 
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Mirror to the side and inverse in diagonal.
+
Mirror/inverse to the side.
  
 
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|
 
|
  
=== Ha (+) ===
+
=== ! ===
[[File:L4C 1CW Ha.jpg]]
+
[[File:!.jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
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|
 
|
  
=== Hb (-) ===
+
=== ! ===
[[File:L4C 1CCW Hb.jpg]]
+
[[File:!.jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
 +
 +
|}
 +
 +
----
 +
*****
 +
----
 +
16 cases, two are [[E-PLL]], leaving 14.
 +
 +
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=== U E (a) ===
=== pia (T+) ===
+
[[File:L4C UE (a).jpg]]
[[File:L4C 1CW pi2a.jpg]]
 
  
 
{{Alg|!}}
 
{{Alg|!}}
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|
 
|
  
=== pib (T-) ===
+
=== U E (b) ===
[[File:L4C 1CCW pi2b.jpg]]
+
[[File:L4C UE (b).jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
  
 
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|-valign="top"
| bgcolor="f0f4f8" |
+
|
The following four cases are mirror + inverses of the first so you only need '1 alg' for all.
+
=== T E (a) ===
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+
[[File:L4C TE (a).jpg]]
Mirror to the side and inverse in diagonal.
+
 
 +
{{Alg|!}}
 +
 
 +
|
 +
 
 +
=== T E (b) ===
 +
[[File:L4C TE (b).jpg]]
 +
 
 +
{{Alg|!}}
  
 
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|-valign="top"
 
|
 
|
 
+
=== L E (a) ===
=== Ha (-) ===
+
[[File:L4C LE (a).jpg]]
[[File:L4C 1CCW Ha.jpg]]
 
  
 
{{Alg|!}}
 
{{Alg|!}}
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|
 
|
  
=== Hb (+) ===
+
=== L E (b) ===
[[File:L4C 1CW Hb.jpg]]
+
[[File:L4C LE (b).jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
  
 
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|-valign="top"
 +
|
 +
=== S E (a) ===
 +
[[File:L4C SE (a).jpg]]
 +
 +
{{Alg|!}}
  
 
|
 
|
  
=== pia (U-) ===
+
=== S E (b) ===
[[File:L4C 1CCW pi1a.jpg]]
+
[[File:L4C SE (b).jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
  
 +
|-valign="top"
 
|
 
|
 +
=== -S E (a) ===
 +
[[File:L4C aSE (b).jpg]]
  
=== pib (U+) ===
+
{{Alg|!}}
[[File:L4C 1CW pi1b.jpg]]
+
 
 +
|
 +
 
 +
=== -S E (b) ===
 +
[[File:L4C aSE (a).jpg]]
  
 
{{Alg|!}}
 
{{Alg|!}}
 
|-valign="top"
 
| bgcolor="f0f4f8" |
 
For the following cases mirror and inverse are the same.
 
| bgcolor="f0f4f8" |
 
Mirror/inverse to the side.
 
  
 
|-valign="top"
 
|-valign="top"
 
|
 
|
 +
=== H E (a) ===
 +
This case can be solved optimally by simply doing [[OLL#.22T.22_shapes|OLL 45]] three times (triple fruruf).
  
=== pia (U+) ===
+
[[File:L4C HE (a).jpg]]
[[File:L4C 1CW pi1a.jpg]]
 
  
{{Alg|U2 F U2 F' U2 F' L F' R' F' R F' L'}}
+
{{Alg|F(RUR'U')3F'}}
  
 
|
 
|
  
=== pib (U-) ===
+
=== H E (b) ===
[[File:L4C 1CCW pi1b.jpg]]
+
[[File:L4C HE (b).jpg]]
  
{{Alg|L F R' F R F L' F U2 F U2 F' U2}}
+
{{Alg|!}}
  
 
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|-valign="top"
 
|
 
|
 +
=== pi E (a) ===
 +
[[File:L4C piE (b).jpg]]
  
=== pia (T-) ===
+
{{Alg|!}}
[[File:L4C 1CCW pi2a.jpg]]
 
 
 
{{Alg|R2 U R2 B' D R2 D' R2 B D' F2 D F2 U'}}
 
  
 
|
 
|
  
=== pib (T+) ===
+
=== pi E (b) ===
[[File:L4C 1CW pi2b.jpg]]
+
[[File:L4C piE (a).jpg]]
  
{{Alg|U F2 D' F2 D B' R2 D R2 D' B R2 U' R2}}
+
{{Alg|!}}
  
 
|}
 
|}

Revision as of 23:42, 20 August 2010

This will be running a bit slower than what has been the later weeks, the rains has gone again so I'm outside daytime now and tired at nights :)

// Kenneth 18:59, 12 August 2010 (UTC)


I think we make a separate page for L3C, it is a stand alone method and it will make this page a little smaller. // Kenneth 06:51, 14 August 2010 (UTC)


I don't know if it is a good order for the 1-twist cases as is, better to group them like I did with the 3-cycles at L3C in quads where 'the same' alg can be used for each group of 4.

I do that later, first I fix the rest of the images... done. // Kenneth 09:37, 18 August 2010 (UTC)


Work area

The names for the cases are first orientation (H or pi) folled by the direction for the permutation cycle (a or b) and in the parentesis is the orientation for the placed corner (+ or -) and for the pi cases also if this corner is on the U ot the T side of the pi (For H it is only one situation).


For the following cases mirror and inverse are the same.

Mirror/inverse to the side.

!

File:!.jpg

Speedsolving Logo tiny.gif Alg !


!

File:!.jpg

Speedsolving Logo tiny.gif Alg !




16 cases, two are E-PLL, leaving 14.

U E (a)

L4C UE (a).jpg

Speedsolving Logo tiny.gif Alg !


U E (b)

L4C UE (b).jpg

Speedsolving Logo tiny.gif Alg !


T E (a)

L4C TE (a).jpg

Speedsolving Logo tiny.gif Alg !


T E (b)

L4C TE (b).jpg

Speedsolving Logo tiny.gif Alg !


L E (a)

L4C LE (a).jpg

Speedsolving Logo tiny.gif Alg !


L E (b)

L4C LE (b).jpg

Speedsolving Logo tiny.gif Alg !


S E (a)

L4C SE (a).jpg

Speedsolving Logo tiny.gif Alg !


S E (b)

L4C SE (b).jpg

Speedsolving Logo tiny.gif Alg !


-S E (a)

L4C aSE (b).jpg

Speedsolving Logo tiny.gif Alg !


-S E (b)

L4C aSE (a).jpg

Speedsolving Logo tiny.gif Alg !


H E (a)

This case can be solved optimally by simply doing OLL 45 three times (triple fruruf).

L4C HE (a).jpg

Speedsolving Logo tiny.gif Alg F(RUR'U')3F'


H E (b)

L4C HE (b).jpg

Speedsolving Logo tiny.gif Alg !


pi E (a)

L4C piE (b).jpg

Speedsolving Logo tiny.gif Alg !


pi E (b)

L4C piE (a).jpg

Speedsolving Logo tiny.gif Alg !