My World

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Revision as of 12:43, 9 May 2017 by LSLL (talk | contribs) (→‎Cons)

- Is a speedsolving method proposed by a reddit user named VentoAureoGoldenWind as to solve both Last Slot and Last Layer in one step. It's also proposed as a 5-Look Solve method. It has less algs than full 1LLL but it still has 3835 algs making it long to master.


1. EOLine or 3/4 EOCross
Nothing new in this step but the 3/4 Cross sets up into a Adj Slot R/L F2L-2 if the user opts to make a first block.

2. F2L-2
F2L is the same but you must leave out 2 slots. It doesn't matter which slots are open as long there's 2 slots open.

3. My Last Slot/ My 3rd Slot (F2L-EP)

This step is 2-gen. You can solve any of the remaining pair but you must solve EP. The other F2L doesn't necessarily need to be solved only 3 LL edges must be solved relative to each other.

Solve both LS and LL with 1 algorithm.

# of My 3rd Slot algs

Assuming you mirror/inverse/mirror-inverse 1 alg to solve 1 slot, you can solve all 4 slots. Like how TSLE has 108 cases.

Due to y2 symmetry there's only 3 meaningful F2L-2 cases:

1. Diag Slots
2. Adj Slot R/L
3. Adj Slot F/B

There are 60 F2L cases possible w/ this slots in total. You only need 6 algorithms to solve EP if the F2L edge is in one of the slots. Also 6 algorithms when it's out but the edge has 4 meaningful. places to go so you need 24 algorithms in total. 36 of the F2L cases have the edge in.

((24 x 24) + (36 x 6)) - 1 = 791

# of 1LLSLL cases

PLL = PLSLL. It means they both have the same # of permutation both LL and LSLL and both have their own version of a PLL. LL has 8 U PLLs in reality so does a F2L when the corner is out have 8 edge cycles. You can think of it like these; during LL the F2L pieces don't move and only LL pieces do. Now take this cases when the corner is out. AUF it always to UBL and only move the LL pieces. See the F2L pieces don't move but the LL pieces do.

With edges solves there's only 6 CP cases and there are 7 F2L permutations. There are 24 unique CO cases. 3 of which are symmetrical and another 3 that are half symmetrical.

(18 x 4) + (3 x 2) + (3 x 1)= 81 CO cases

The solved F2L permutation have symmetry reducing the CO cases to 24. If the CO cases is symmetrical then there are 3 CP cases, 4 when half symmetrical.

((3x3) + (3x4) + (18 x 6)) -1 = 128

The remaining 6 cases don't have anymore symmetry so 36 x 81 = 2916

2916 + 128 = 3044


Relatively low alg count for LSLL and it even has less algs than full 1LLL. Beating M-CELL in terms of alg usage per step. Only using 1 alg for LSLL not 2.

It's a ZZ Variant that barely changed F2L as it is still free and no setups to the last 2 steps. You can solve any slot/square so efficiency is preserved.

My 3rd Slot is 2-gen making slot neutral much easier. It's also just F2L algs done differently making learning easier.

It only requires 5-Looks(1-alg and 1-look). Assuming you've gotten good with making squares that you don't need to 2-look it. A typical solve will go like this:

1. EOLine/ EO 3/4 Cross
2-3. ZZF2L
4. My Third Slot


Huge alg count. Recall at first will be hard but just like with words you'll get use to it.

Being slot neutral wil take a while for LSLL but for My 3rd Slot it will just be mirroring/inversing F2L algs making slot neutral a bit easier.