Difference between revisions of "Lin"
From Speedsolving.com Wiki
m |
|||
Line 12: | Line 12: | ||
* [[Speedsolving]] | * [[Speedsolving]] | ||
}} | }} | ||
− | The '''Lin method''' is a speedsolving/novelty method for the [[Square-1]] puzzle. | + | The '''Lin method''' is a speedsolving/novelty method for the [[Square-1]] puzzle. It was brought into common knowledge by a tutorial from Jbacboy and John Lewis's promotion of the method. |
== The steps == | == The steps == |
Revision as of 18:18, 28 March 2017
|
The Lin method is a speedsolving/novelty method for the Square-1 puzzle. It was brought into common knowledge by a tutorial from Jbacboy and John Lewis's promotion of the method.
The steps
- 1. Turn the puzzle into a cubic shape.
- 2. Build the first two blocks.
- 2a. Build a 1x1x3 block on the bottom layer of the puzzle, either the left or the right side.
- 2b. Build a second block in the bottom layer, opposite the first one.
- 3. CP + DF (Corner permutation + DF edge)
- 3a. Insert one of the two remaining D edges.
- 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach, first inserting the edge and then permuting the corners, is possible. This approach requires around 2 algs, which are basic Vandenbergh algs.
- 4. EPLL (excluding corners)
CP + DF algs
OppositeCorners | 1,0 / -4,-3 / -3,0 / -3,-3 / -3,0 / -2,-3 / |
LeftCorners | 1,0 / 3,0 / 3,-3 / -1,2 / 1,-2 / 3,0 / |
RightCorners | 1,0 / 2,-1 / 0,-3 / 3,0 / -3,0 / -2,4 / |
FrontCorners | 0,-1 / 4,-2 / -3,0 / 0,3 / 0,-3 / -1,2 / |
BackCorners | 4,-3 / -3,0 / -1,2 / 1,-2 / -3,3 / -3,0 / |