Difference between revisions of "Lin"
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Generalpask (talk | contribs) (added CP+DF algs) |
RedstoneTim (talk | contribs) m (Added link to Roux on other puzzles) |
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|name=Lin | |name=Lin | ||
|image= | |image= | ||
− | |proposers= | + | |proposers=[[Tse-Kan Lin]] |
− | |year= | + | |year=2010 |
− | |anames= | + | |anames=TKL |
|variants= | |variants= | ||
|steps=5 | |steps=5 | ||
+ | |algs=3-14 | ||
|moves= | |moves= | ||
|purpose=<sup></sup> | |purpose=<sup></sup> | ||
* [[Speedsolving]] | * [[Speedsolving]] | ||
}} | }} | ||
− | The '''Lin method''' is a speedsolving/novelty method for the [[Square-1]] puzzle | + | The '''Lin method''' is a speedsolving/novelty method for the [[Square-1]] puzzle. |
== The steps == | == The steps == | ||
Line 20: | Line 21: | ||
* 3. CP + DF (Corner permutation + DF edge) | * 3. CP + DF (Corner permutation + DF edge) | ||
:* 3a. Insert one of the two remaining D edges. | :* 3a. Insert one of the two remaining D edges. | ||
− | :* 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach | + | :* 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach, first inserting the edge and then permuting the corners, is possible. This approach requires around 2 algs, which are basic [[Vandenbergh]] algs. |
− | * 4. [ | + | * 4. [http://ranzha.cubing.net/square-1/pll.html EPLL] (excluding corners) |
== CP + DF algs == | == CP + DF algs == | ||
− | + | Diagonal swap: (1,0) / (-4,-3) / (-3,0) / (-3,-3) / (-3,0) / (-2,-3) / | |
− | + | ||
− | + | Adjacent swap L: (1,0) / (3,0) / (3,-3) / (-1,2) / (1,-2) / (3,0) / | |
− | + | ||
− | + | Adjacent swap R: (1,0) / (2,-1) / (0,-3) / (3,0) / (-3,0) / (-2,4) / | |
+ | |||
+ | Adjacent swap F: (0,-1) / (4,-2) / (-3,0) / (0,3) / (0,-3) / (-1,2) / | ||
+ | |||
+ | Adjacent swap B: (4,-3) / (-3,0) / (-1,2) / (1,-2) / (-3,3) / (-3,0) / | ||
== See also == | == See also == | ||
Line 34: | Line 39: | ||
* [[Roux n Skrew]] | * [[Roux n Skrew]] | ||
* [[Vandenbergh]] | * [[Vandenbergh]] | ||
+ | * [[Roux on other puzzles]] | ||
== External links == | == External links == | ||
* [https://www.youtube.com/watch?v=OLrFbXhIyj8 ''Jbacboy'''s tutorial on the method] | * [https://www.youtube.com/watch?v=OLrFbXhIyj8 ''Jbacboy'''s tutorial on the method] | ||
− | : | + | |
+ | [[Category:Square-1 methods]] |
Revision as of 12:48, 27 June 2020
|
The Lin method is a speedsolving/novelty method for the Square-1 puzzle.
The steps
- 1. Turn the puzzle into a cubic shape.
- 2. Build the first two blocks.
- 2a. Build a 1x1x3 block on the bottom layer of the puzzle, either the left or the right side.
- 2b. Build a second block in the bottom layer, opposite the first one.
- 3. CP + DF (Corner permutation + DF edge)
- 3a. Insert one of the two remaining D edges.
- 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach, first inserting the edge and then permuting the corners, is possible. This approach requires around 2 algs, which are basic Vandenbergh algs.
- 4. EPLL (excluding corners)
CP + DF algs
Diagonal swap: (1,0) / (-4,-3) / (-3,0) / (-3,-3) / (-3,0) / (-2,-3) /
Adjacent swap L: (1,0) / (3,0) / (3,-3) / (-1,2) / (1,-2) / (3,0) /
Adjacent swap R: (1,0) / (2,-1) / (0,-3) / (3,0) / (-3,0) / (-2,4) /
Adjacent swap F: (0,-1) / (4,-2) / (-3,0) / (0,3) / (0,-3) / (-1,2) /
Adjacent swap B: (4,-3) / (-3,0) / (-1,2) / (1,-2) / (-3,3) / (-3,0) /