Difference between revisions of "Lin"
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Generalpask (talk | contribs) (added CP+DF algs) |
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* 3. CP + DF (Corner permutation + DF edge) | * 3. CP + DF (Corner permutation + DF edge) | ||
:* 3a. Insert one of the two remaining D edges. | :* 3a. Insert one of the two remaining D edges. | ||
− | :* 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach | + | :* 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach, first inserting the edge and then permuting the corners, is possible. This approach requires around 2 algs, which are basic [[Vandenbergh]] algs. |
* 4. [[EPLL|Permute edges of last layer]] | * 4. [[EPLL|Permute edges of last layer]] | ||
Revision as of 19:20, 13 March 2017
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The Lin method is a speedsolving/novelty method for the Square-1 puzzle. It is very similar to RouxFOP in terms of steps.
The steps
- 1. Turn the puzzle into a cubic shape.
- 2. Build the first two blocks.
- 2a. Build a 1x1x3 block on the bottom layer of the puzzle, either the left or the right side.
- 2b. Build a second block in the bottom layer, opposite the first one.
- 3. CP + DF (Corner permutation + DF edge)
- 3a. Insert one of the two remaining D edges.
- 3b. Insert the last one in DF (from UL) while simultaneously permuting the top layer corners. This step requires 6 algs, specified below. A two step approach, first inserting the edge and then permuting the corners, is possible. This approach requires around 2 algs, which are basic Vandenbergh algs.
CP + DF algs
OppositeCorners | 1,0 / -4,-3 / -3,0 / -3,-3 / -3,0 / -2,-3 / |
LeftCorners | 1,0 / 3,0 / 3,-3 / -1,2 / 1,-2 / 3,0 / |
RightCorners | 1,0 / 2,-1 / 0,-3 / 3,0 / -3,0 / -2,4 / |
FrontCorners | 0,-1 / 4,-2 / -3,0 / 0,3 / 0,-3 / -1,2 / |
BackCorners | 4,-3 / -3,0 / -1,2 / 1,-2 / -3,3 / -3,0 / |
See also
External links
- Note: No other resources of the method have yet been found, so it is suggested that Jbacboy is the creator.