Difference between revisions of "L5E"
(I rewrote this to fix bad grammar and the like.) |
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− | + | '''E15''' and '''E35''' are experimental methods that solve the last six or the last eight [[edges]] of the U and D layers. First one (in E15) or three (in E35) D-layer edges are solved, and then the last five are finished in one step. Of course, corners and E-layer edges are always preserved. | |
− | |||
− | == | + | == Description == |
− | + | E15 and E35 use a combination of intuition and algorithms to solve the last six or eight edges. An advanced user can even include [[ELL]] algorithms to save turns in some cases. It is similar to the last step of [[Roux]], but here the orientation is done after all of the [[center]]s are solved, to make recognition easier. | |
− | E35 | + | Both E15 and E35 consist of two steps. In the first step of E15, E1, the BD edge is placed intuitively along with the B and D centers. In the first step of E35, E3, the solver first pairs up the RD and LD edges and places them along with the R centers (or simply does one at a time by placing a center-edge pair and then using an M'UM-type algorithm), and then places BD and the B center as in E1. |
− | + | In the second step of both methods, E5, there are two main sub-parts. First the edges are oriented using M'UM like in Roux; there are 5 cases for this, and the worst case in Roux (6 edges) is impossible. Then the edges must be permuted; you can place FD during orientation or right after and end with [[EPLL]], or just permute all five edges in one step. | |
− | |||
− | |||
− | |||
− | E35 | + | E35 can be useful for [[Corners First]] if the E-slice is solved after the corners. It is also useful in any method that starts with columns, such as one which does the F2L pairs first and then finishes with [[CxLL|CMLL]]. E15 is an alternative to the last step of [[Roux]]. The E5 part can be used as a standalone method, which can be used (for example) if F2L minus one D edge has been solved and then the LL corners have been finished with [[CLL]] or [[CMLL]]. |
==Intermediate system for E5== | ==Intermediate system for E5== | ||
+ | |||
===Intuitive:=== | ===Intuitive:=== | ||
− | This | + | This style is not completely intuitive, because it is still necessary to know [[EPLL]]. First orient all unoriented edges, then place the FD edge to its correct position and finally end the solve in EPLL. The necessary intuitive steps are: |
* P = M' U2 M | * P = M' U2 M | ||
− | |||
* O = M' U M | * O = M' U M | ||
* O' = M' U' M | * O' = M' U' M | ||
− | |||
− | + | Using that plus some U turns you can solve any case, even all [[ELL]] case. For example, O U P = (M' U M) U (M' U2 M) is a sample algorithm which solves orientation, then places FD. There is a 1 in 12 chance that EPLL is skipped; otherwise there is one algorithm left. | |
− | + | There is another notation which can make it shorter to write algorithms: | |
− | * F() = F2 ( | + | * F(moves) = F2 (moves) F2 |
− | + | It is important here that the moves inside the parentheses keep the corners solved, so that they will still be correct after this algorithm. An example is the [[U-perm]], F(U P U) = F2 (U M' U2 M U) F2. F(O U') is a nice way to solve orientation and place FD all at once if the FD edge is in the middle of three unoriented edges in LL. | |
===Using algorithms:=== | ===Using algorithms:=== | ||
− | The intuitive style lets you find and understand the algorithms | + | The intuitive style lets you find and understand the orientation algorithms yourself. Another approach is to learn the algorithms instead of finding them; the case are: |
{| style="border: 1px solid #808080; color: black; background-color: #FAFAFA;" cellspacing="0" cellpadding="2" | {| style="border: 1px solid #808080; color: black; background-color: #FAFAFA;" cellspacing="0" cellpadding="2" | ||
Line 84: | Line 79: | ||
}} | }} | ||
|--- | |--- | ||
− | | colspan="2" | <center>''All images | + | | colspan="2" | <center>''All images show white on top (U) and green in front (F).''</center> |
|} | |} | ||
− | Sometimes | + | Sometimes this will also solve the FD edge; the images show where the FD edge must be for the algorithm to solve it, but otherwise you should simply treat the yellow sticker as white. If you learn these positions, it can also be useful to learn the mirror algorithm for the case where FD is on the opposite side from the image. The easiest example is to use O' instead of O for the case with three flipped edges on U. Just like the intuitive step, if FD is not solved use P, and either way finish with [[EPLL]]. |
− | ==Semi advanced system for E5== | + | ==Semi-advanced system for E5== |
− | |||
− | |||
− | + | ===Orientation + FD placement=== | |
+ | In many cases you can orient the edges and solve FD at the same time without using any more moves. However, for most cases the length of the algorithm is as long as the two-step process, so learning a separate algorithm would not help. Some good cases are: | ||
− | * | + | * ''algorithm'' ... possibly optimized moves ... ''pieces to orient'', ''location of FD'' |
− | |||
− | * | + | * M U F(U' M') ... M d R2 d' M' d R2 ... orients RU and FU, FD at UF. |
+ | * M U' F(U M') ... M d' L2 d M' d' L2 ... orients LU and FU, FD at UF. | ||
− | * M U | + | * O U' O' ... (M' U M) U' (M' U' M) ... orients FU and BU, FD at UB |
− | ' | + | * M U 3x(M' U) M2 ... orients UF, UL, UB and DF without moving any pieces. |
− | + | ''More algorithms will be added later.'' | |
− | ''' | ||
− | Another | + | ===FD placement + EPLL (EP5)=== |
+ | Another possibility for improving Intermediate E5 is to permutate the last five edges in one step. This only requires 16 algorithms in total, so counting the 5 orientations creates a system that solves E5 in two short steps. Even if you know this, it is still useful to place FD without extra moves if possible, since EPLL recognition is very fast. | ||
− | + | We will introduce the following function: | |
− | + | * f(moves) = f2 (moves) [U] f2 ... This is the same as the F() function above, but with double layer f turns. Note that sometimes the adjusting U turns are not mentioned. | |
− | |||
− | * f() = f2 ( | ||
+ | Here are the algorithms for permutation of all 5 edges; make sure to use AUF to place teh FD edge at the position it has in the image. | ||
{| style="border: 1px solid #808080; color: black; background-color: #FAFAFA;" cellspacing="0" cellpadding="2" | {| style="border: 1px solid #808080; color: black; background-color: #FAFAFA;" cellspacing="0" cellpadding="2" | ||
Line 163: | Line 156: | ||
}} | }} | ||
|--- | |--- | ||
− | | colspan="2" | <center>''' | + | | colspan="2" | <center>'''3-cycle permutations'''</center> |
|--- | |--- | ||
| | | | ||
Line 170: | Line 163: | ||
|NAME=P | |NAME=P | ||
|ALGO= (M' U2 M) | |ALGO= (M' U2 M) | ||
− | |INFO=Cycles UF->DF->UB | + | |INFO=Cycles UF->DF->UB |
}} | }} | ||
| | | | ||
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|NAME=f(d' P) | |NAME=f(d' P) | ||
|ALGO=(y') r2 U' (M' U2 M) U' r2 | |ALGO=(y') r2 U' (M' U2 M) U' r2 | ||
− | |INFO=Cycles UL->UB-DF | + | |INFO=Cycles UL->UB->DF |
}} | }} | ||
|--- | |--- | ||
Line 185: | Line 178: | ||
|NAME=f(d P) | |NAME=f(d P) | ||
|ALGO=(y') r2 U (M U2 M') U r2 | |ALGO=(y') r2 U (M U2 M') U r2 | ||
− | |INFO=Cycles UR->UB->DF | + | |INFO=Cycles UR->UB->DF |
}} | }} | ||
| | | | ||
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|NAME=[[PLL#U_Permutation_:_b|U-PLL]] | |NAME=[[PLL#U_Permutation_:_b|U-PLL]] | ||
|ALGO=F2 U (M' U2 M) U F2 | |ALGO=F2 U (M' U2 M) U F2 | ||
− | |INFO=Cycles UF->UL-UR | + | |INFO=Cycles UF->UL->UR |
}} | }} | ||
|--- | |--- | ||
Line 200: | Line 193: | ||
|NAME=[[PLL#U_Permutation_:_a|U-PLL']] | |NAME=[[PLL#U_Permutation_:_a|U-PLL']] | ||
|ALGO=F2 U' (M' U2 M) U' F2 | |ALGO=F2 U' (M' U2 M) U' F2 | ||
− | |INFO=Cycles UF->UR-UL | + | |INFO=Cycles UF->UR->UL |
}} | }} | ||
− | |<center | + | |<center> </center> |
|--- | |--- | ||
− | | colspan="2" | <center>''' | + | | colspan="2" | <center>'''5-cycle permutations'''</center> |
|--- | |--- | ||
| | | | ||
Line 211: | Line 204: | ||
|NAME=P U P | |NAME=P U P | ||
|ALGO=(M' U2 M) U (M' U2 M) | |ALGO=(M' U2 M) U (M' U2 M) | ||
− | |INFO=Cycles UF->UL->UR-DF->UB | + | |INFO=Cycles UF->UL->UR->DF->UB |
}} | }} | ||
| | | | ||
Line 218: | Line 211: | ||
|NAME=P U' P | |NAME=P U' P | ||
|ALGO=(M' U2 M) U' (M' U2 M) | |ALGO=(M' U2 M) U' (M' U2 M) | ||
− | |INFO=Cycles UF-UR-UL-DF-UB | + | |INFO=Cycles UF->UR->UL->DF->UB |
}} | }} | ||
|--- | |--- | ||
Line 226: | Line 219: | ||
|NAME=P Z-PLL | |NAME=P Z-PLL | ||
|ALGO=2x(M2 U) (M U2 M') | |ALGO=2x(M2 U) (M U2 M') | ||
− | |INFO=Cycles UF->UR->UB->UL->FD | + | |INFO=Cycles UF->UR->UB->UL->FD |
}} | }} | ||
| | | | ||
Line 233: | Line 226: | ||
|NAME=P Z-PLL' | |NAME=P Z-PLL' | ||
|ALGO=2x(M2 U') (M U2 M') | |ALGO=2x(M2 U') (M U2 M') | ||
− | |INFO=Cycles UF->UL->UB->UR->DF | + | |INFO=Cycles UF->UL->UB->UR->DF |
}} | }} | ||
|--- | |--- | ||
Line 241: | Line 234: | ||
|NAME=P U-PLL | |NAME=P U-PLL | ||
|ALGO=(M' U2 M') U' (M' U2 M) U' M2 | |ALGO=(M' U2 M') U' (M' U2 M) U' M2 | ||
− | |INFO=Cycles UF->DF->UB->UL->UR | + | |INFO=Cycles UF->DF->UB->UL->UR |
}} | }} | ||
| | | | ||
Line 248: | Line 241: | ||
|NAME=P U-PLL' | |NAME=P U-PLL' | ||
|ALGO=(M' U2 M') U (M' U2 M) U M2 | |ALGO=(M' U2 M') U (M' U2 M) U M2 | ||
− | |INFO=Cycles UF->DF->UB->UR->UL | + | |INFO=Cycles UF->DF->UB->UR->UL |
}} | }} | ||
| | | | ||
|--- | |--- | ||
− | | colspan="2" | <center>'' | + | | colspan="2" | <center>''These images have white on top (U) and green in front (F). Darker pieces changes positions.''</center> |
|} | |} | ||
==Advanced system for E5== | ==Advanced system for E5== | ||
− | The advanced | + | The most advanced system would be to simply solve E5 in one step. Nobody has generated the algorithms for this yet, but it may not be a good idea because of the large number of cases and bad recognition. For the worst ones the algorithm will probably just be the same as in the 2-step solution, so the benefit will be small at best. |
− | + | One case where this is useful (and doable) is to solve cases where at least one of the edges is solved at the start. Using setup turns and [[ELL]] this can be done in one step, although the recognition and setup moves might mean that this is not worth doing. | |
− | |||
− | |||
==Examples== | ==Examples== | ||
Line 267: | Line 258: | ||
'''Scramble:''' | '''Scramble:''' | ||
{{E15 Scramble 01}} | {{E15 Scramble 01}} | ||
− | '' | + | ''Note that the centers are solved here, but they will not always be.'' |
'''Intermediate:''' | '''Intermediate:''' | ||
Line 284: | Line 275: | ||
Do: U2 M U2 M' ... U2 (M' U M) ... (y') U' R U2 R2 U2 R2 U2 R | Do: U2 M U2 M' ... U2 (M' U M) ... (y') U' R U2 R2 U2 R2 U2 R | ||
− | == | + | ==See also== |
− | + | * [http://athefre.110mb.com/Step5.html Permutation of last 5 edges by Athefre] | |
− |
Revision as of 06:04, 2 December 2008
E15 and E35 are experimental methods that solve the last six or the last eight edges of the U and D layers. First one (in E15) or three (in E35) D-layer edges are solved, and then the last five are finished in one step. Of course, corners and E-layer edges are always preserved.
Contents
Description
E15 and E35 use a combination of intuition and algorithms to solve the last six or eight edges. An advanced user can even include ELL algorithms to save turns in some cases. It is similar to the last step of Roux, but here the orientation is done after all of the centers are solved, to make recognition easier.
Both E15 and E35 consist of two steps. In the first step of E15, E1, the BD edge is placed intuitively along with the B and D centers. In the first step of E35, E3, the solver first pairs up the RD and LD edges and places them along with the R centers (or simply does one at a time by placing a center-edge pair and then using an M'UM-type algorithm), and then places BD and the B center as in E1.
In the second step of both methods, E5, there are two main sub-parts. First the edges are oriented using M'UM like in Roux; there are 5 cases for this, and the worst case in Roux (6 edges) is impossible. Then the edges must be permuted; you can place FD during orientation or right after and end with EPLL, or just permute all five edges in one step.
E35 can be useful for Corners First if the E-slice is solved after the corners. It is also useful in any method that starts with columns, such as one which does the F2L pairs first and then finishes with CMLL. E15 is an alternative to the last step of Roux. The E5 part can be used as a standalone method, which can be used (for example) if F2L minus one D edge has been solved and then the LL corners have been finished with CLL or CMLL.
Intermediate system for E5
Intuitive:
This style is not completely intuitive, because it is still necessary to know EPLL. First orient all unoriented edges, then place the FD edge to its correct position and finally end the solve in EPLL. The necessary intuitive steps are:
- P = M' U2 M
- O = M' U M
- O' = M' U' M
Using that plus some U turns you can solve any case, even all ELL case. For example, O U P = (M' U M) U (M' U2 M) is a sample algorithm which solves orientation, then places FD. There is a 1 in 12 chance that EPLL is skipped; otherwise there is one algorithm left.
There is another notation which can make it shorter to write algorithms:
- F(moves) = F2 (moves) F2
It is important here that the moves inside the parentheses keep the corners solved, so that they will still be correct after this algorithm. An example is the U-perm, F(U P U) = F2 (U M' U2 M U) F2. F(O U') is a nice way to solve orientation and place FD all at once if the FD edge is in the middle of three unoriented edges in LL.
Using algorithms:
The intuitive style lets you find and understand the orientation algorithms yourself. Another approach is to learn the algorithms instead of finding them; the case are:
Sometimes this will also solve the FD edge; the images show where the FD edge must be for the algorithm to solve it, but otherwise you should simply treat the yellow sticker as white. If you learn these positions, it can also be useful to learn the mirror algorithm for the case where FD is on the opposite side from the image. The easiest example is to use O' instead of O for the case with three flipped edges on U. Just like the intuitive step, if FD is not solved use P, and either way finish with EPLL.
Semi-advanced system for E5
Orientation + FD placement
In many cases you can orient the edges and solve FD at the same time without using any more moves. However, for most cases the length of the algorithm is as long as the two-step process, so learning a separate algorithm would not help. Some good cases are:
- algorithm ... possibly optimized moves ... pieces to orient, location of FD
- M U F(U' M') ... M d R2 d' M' d R2 ... orients RU and FU, FD at UF.
- M U' F(U M') ... M d' L2 d M' d' L2 ... orients LU and FU, FD at UF.
- O U' O' ... (M' U M) U' (M' U' M) ... orients FU and BU, FD at UB
- M U 3x(M' U) M2 ... orients UF, UL, UB and DF without moving any pieces.
More algorithms will be added later.
FD placement + EPLL (EP5)
Another possibility for improving Intermediate E5 is to permutate the last five edges in one step. This only requires 16 algorithms in total, so counting the 5 orientations creates a system that solves E5 in two short steps. Even if you know this, it is still useful to place FD without extra moves if possible, since EPLL recognition is very fast.
We will introduce the following function:
- f(moves) = f2 (moves) [U] f2 ... This is the same as the F() function above, but with double layer f turns. Note that sometimes the adjusting U turns are not mentioned.
Here are the algorithms for permutation of all 5 edges; make sure to use AUF to place teh FD edge at the position it has in the image.
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Advanced system for E5
The most advanced system would be to simply solve E5 in one step. Nobody has generated the algorithms for this yet, but it may not be a good idea because of the large number of cases and bad recognition. For the worst ones the algorithm will probably just be the same as in the 2-step solution, so the benefit will be small at best.
One case where this is useful (and doable) is to solve cases where at least one of the edges is solved at the start. Using setup turns and ELL this can be done in one step, although the recognition and setup moves might mean that this is not worth doing.
Examples
E15 example
Scramble:
1.
L2 R2 U2 L2 R2 F2 U' L2 R2 D2 L R' B' U2 F2 L R' |
Note that the centers are solved here, but they will not always be.
Intermediate:
- E1: U2 M U2 M'
- EO5: U2 O
- PFD: U' P
- EPLL: H-PLL
Do: U2 M U2 M' ... U2 (M' U M) ... U (M' U2 M) ... Ra U2 Ra' (y) Ra' U2 Ra
2-step E5:
- E1: U2 M U2 M'
- EO5: U2 O
- EP5: U' F(H-PLL)
Do: U2 M U2 M' ... U2 (M' U M) ... (y') U' R U2 R2 U2 R2 U2 R