CxLL L R
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L R
The four cases, T R, T L, L R and L B are mirrors and inverses of each other so the same algorithm (8 move commutator) can be used to solve them all.
The two stickers in the U-face has got opposite colours, find the other two. The case L B looks the same but mirrored. |
COLL
- (x') U' R U L' U' R' U r
CLL
- ...
CMLL
- R U R U' L' U R' U'
- U2 F' L F L' U' L' U L
CF / 2x2x2 (Waterman)
- ...
EG
EG 2 --> 2x2x2
EG 1
- ...
EG 0
- ...
CxLL edit |
U |
D |
R |
L |
F |
B |
U |
U U |
U D |
U R |
U L |
U F |
U B |
T |
T U |
T D |
T R |
T L |
T F |
T B |
L |
L U |
L D |
L R |
L L |
L F |
L B |
S |
S U |
S D |
S R |
S L |
S F |
S B |
-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |
Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |
H |
H U |
H D |
H R |
H L |
H F |
H B |
Hyper CLL edit |
U |
D |
R |
L |
F |
B |
U |
U U |
U D |
U R |
U L |
U F |
U B |
T |
T U |
T D |
T R |
T L |
T F |
T B |
L |
L U |
L D |
L R |
L L |
L F |
L B |
S |
S U |
S D |
S R |
S L |
S F |
S B |
-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |
Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |
H |
H U |
H D |
H R |
H L |
H F |
H B |