CxLL T L

T L

The four cases, T R, T L, L R and L B are mirrors and inverses of each other so the same algorithm (8 move commutator) can be used to solve them all.

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As for all T cases you look at two "bars" of stickers, one at Fur-Ful and one at Urb-Ulb, perpendicular to the bars there are two stickers of the same colour and the other two has got opposite colours.

COLL

• (y) l U L' U' R' U L U' (x')

CLL

• ...

CMLL

• ...

CF / 2x2x2 (Waterman)

• ...

EG

EG 2 --> 2x2x2

EG 1

• ...

EG 0

• ...