# What is BH for corners?

#### Julian

##### Member
Hi, I've heard from some people that it takes ~25 seconds to memo the corners using "BH" and ~10 seconds to solve them. What exactly is BH, and hoe does it work? Search function yields no results.

Thanks

#### aronpm

##### Member
~25 seconds to memo the corners using "BH" and ~10 seconds to solve them.
Lol that memo is really slow

#### riffz

##### Member
BH is just a solving method, not a memory method.

#### cmhardw

##### Premium Member
BH has a page in the Wiki.

#### Shortey

##### Premium Member
Why are people so ****ing bad at searching? It's not that hard.

#### cmhardw

##### Premium Member
http://www.speedcubing.com/chris/bhcorners.html

Do we have to learn all these 378 algorithms for BH corners or only some of them?
From the site you linked:

The following are all algorithms necessary to use the Beyer-Hardwick method for corners. Please bear in mind that there are often multiple algorithms you could use for a certain case. The case name is more important for each algorithm than the given algorithm. In later pages to follow you will see how to use the case name for a certain cycle to construct the correct algorithm when solving. We include one algorithm for each case merely for completeness.
No, you do not need to learn more than about 10-15 cases, or types of commutators. Read the tutorials linked to in this thread for a further explanation. Sadly, Daniel nor I have had enough to time put together the explanation page we talked about on that site. Byu's tutorial does a very good job of explaining this, and would be a good resource to follow up with.

#### QCcuber4

##### Member
Not too sure but i've been self teaching myself how to permute and oriente (simultaniously) corners aswell as edges using commutators... like, not too sure if I use actual ''pure'' commutators, but i sure and doing XYX'Y' stuff, it's pretty intuitive. I was told it sounded lie BH at some point, but this is much more advanced stuff...

#### riffz

##### Member
How is it more advanced? BH is commutators.

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