...A long time ago, I used my own method for solving the Rubik's cube, the Fridrus method (2x2x3 block, 2 edges, 3 c/e pairs, 5 piece LL).
Then Qqwref (Michael Gottlieb) gave me a lot of useful insight. He recommended that I use pure block building, and so I learned the Tripod method (2x2x2 block, 3 2x2x1 blocks, 1 c/e pair, 5 piece LL). (He also persuaded me to make my first block like a normal person... It was like I was living in a cave before!)
And so I worked and worked on this nice little method. I like it a lot, because you don't have to memorize many algorithms, and it relies more on intuitive thinking. The last layer (which contains 3 corner pieces and 2 edge pieces) can be solved in 2 steps with 6 memorized algorithms.
You can see the method specifics on my site:
http://web.mac.com/teisenmann/Tripod/main.html
Recently, I have been wondering what the essential differences between the Tripod method and Fridrich method are. The cross and first 3 c/e pairs can be used in both the Fridrich method and Tripod method for the first few steps (although I like block building better!). After the cross and 3 c/e pairs, the methods differ:
With Fridrich, you solve the last c/e pair, then solve the 8 pieces in the last layer using algorithms.
With Tripod, you solve a 2x2x1 block in the last layer, THEN the last c/e pair, and finally the 5 remaining pieces w/ algorithms.
...So now I have a couple questions.
If you want to memorize a SMALL number of algorithms, is it faster to use the Tripod method? In other words, is intuitively solving a block faster than algorithmically solving the entire LL? (Keep in mind that solving the last c/e pair in Tripod is more restricted.)
And alternatively, if you want to memorize a LARGE number of algorithms, is Fridrich faster? A 1 step LL in Tripod and 2 step LL in Fridrich require about the same amount of memorization (I haven't found the actual amount, because I don't want to memorize a lot!
)
Comments are welcome!
Then Qqwref (Michael Gottlieb) gave me a lot of useful insight. He recommended that I use pure block building, and so I learned the Tripod method (2x2x2 block, 3 2x2x1 blocks, 1 c/e pair, 5 piece LL). (He also persuaded me to make my first block like a normal person... It was like I was living in a cave before!)
And so I worked and worked on this nice little method. I like it a lot, because you don't have to memorize many algorithms, and it relies more on intuitive thinking. The last layer (which contains 3 corner pieces and 2 edge pieces) can be solved in 2 steps with 6 memorized algorithms.
You can see the method specifics on my site:
http://web.mac.com/teisenmann/Tripod/main.html
Recently, I have been wondering what the essential differences between the Tripod method and Fridrich method are. The cross and first 3 c/e pairs can be used in both the Fridrich method and Tripod method for the first few steps (although I like block building better!). After the cross and 3 c/e pairs, the methods differ:
With Fridrich, you solve the last c/e pair, then solve the 8 pieces in the last layer using algorithms.
With Tripod, you solve a 2x2x1 block in the last layer, THEN the last c/e pair, and finally the 5 remaining pieces w/ algorithms.
...So now I have a couple questions.
If you want to memorize a SMALL number of algorithms, is it faster to use the Tripod method? In other words, is intuitively solving a block faster than algorithmically solving the entire LL? (Keep in mind that solving the last c/e pair in Tripod is more restricted.)
And alternatively, if you want to memorize a LARGE number of algorithms, is Fridrich faster? A 1 step LL in Tripod and 2 step LL in Fridrich require about the same amount of memorization (I haven't found the actual amount, because I don't want to memorize a lot!
)Comments are welcome!
