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This is a bit confusing; Can someone please re-iterate it for me?

Zeroknight

Member
Joined
Apr 28, 2008
Messages
117
For example, consider the turning of one face by 90 degrees:
C1 E1 C2
E4 E2
C4 E3 C3

C4 E4 C1
E3 E1
C3 E2 C2

The new corner state can be obtained via 3 swaps (swap C1/C4, swap C1/C3, swap C1/C3, swap C1/C2).
It looks like four swaps to me...

Thanks in advance

EDIT: Sorry, but somehow the edges got messed up...
 

Johannes91

Member
Joined
Mar 28, 2006
Messages
1,341
(swap C1/C4, swap C1/C3, swap C1/C3, swap C1/C2)
-->
(swap C1/C4, swap C1/C3, swap C1/C2)
 

Zeroknight

Member
Joined
Apr 28, 2008
Messages
117
Sorry, guys (no I wasn't counting the middle ones). What I see is C1 goes to C2, C2 goes to C3, C3 goes to C4, and C4 goes to C1.


tbqh, I don't "see:" (swap C1/C4, swap C1/C3, swap C1/C3, swap C1/C2)
-->
(swap C1/C4, swap C1/C3, swap C1/C2)
 

Johannes91

Member
Joined
Mar 28, 2006
Messages
1,341
tbqh, I don't "see:" (swap C1/C4, swap C1/C3, swap C1/C3, swap C1/C2)
-->
(swap C1/C4, swap C1/C3, swap C1/C2)
It's obviously a mistake in your quote, swapping the same pieces twice in a row would just cancel out.

Maybe this helps:

C1 C2
C4 C3

First swap: C1 and C4.

C4 C2
C1 C3

Second swap: C1 and C3.

C4 C2
C3 C1

Third swap: C1 and C2.

C4 C1
C3 C2
 
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