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The CEOR Example Solve Thread

tsmosher

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EDIT: All methods following the general steps of CEOR are welcome in this thread. This includes (but is not limited to) Noah's CP Block 2.0, Briggs, YruRU, and any similar CP 1st solving methods beginning with CPEO223.

I have trouble with CP recognition and maintenance, so I figured a thread of example solves would help me.
Maybe they'll help someone else too.

I'll start. I tried to heavily comment my thinking process throughout.

SCRAMBLE: F2 L' B' L2 D L2 D L B D2 F' R2 D2 B' L2 F' U2 F2 L2 D2

Advanced tracing
Beginner's 2GLL
[58 STM]

x' // inspection
// DFL and DLM solved
B // DBL solved
E // to make tracing easier
// #5 in corner #1 & #6 in corner #2
// tracing from corner #2 -> #3 -> #6 -> #4 (Diamond - CW)
// 1-4-2-3
U2 F' U' F // CP-line
// CP-line: 6 (counting the E move)
E u' R E R E // extension to FB
r2 // pEO - orienting DF & DB
// pEO extension: 7
// DR, BR, and all U edges are bad
R r U2 r U' r' U' r2 U r // fix edges
r U2 r // solve DB & DF
// EOBF: 12
U R2 // solve BR pair
U' S' U2 S // solve DRM
U' R U2 R' U R U' R' // LS
// F2L: 14
U' R U2 R' U' R U' R' // OCLL: Anti-Sune
R' U R' U' R' U' R' U R U R2 // EPLL: U
U2 // AUF
// 2GLL: 19

NEXT:
R B2 D R2 U2 R2 F2 U' B2 R2 U' R2 U F' L B F' D' F2 U
 
Last edited:

WoowyBaby

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NEXT: L U2 F2 R' D R L2 U F' U2 F L2 B R2 L2 F2 D2 B' D2 R

YruRU sounds like a really good OH method honestly.

Here's that scramble, solved with YruRU, hopefully good:

D R D2 U2 R U x z' // CP-Line
r' U2 R' u R2 U' R u2 // pEO Ext
r U r R' U' R U r U' r U' R2 U r2 // EOBF
U' R2 U2 R U R2 U' R' U R U' R' U R // F2L
U2 R' U' R2 U R2 U R2 U2 R' U R' U R U' // 2GLL

Next: L2 F2 U L2 D' U' B2 L2 D' B2 U' B2 L B U F2 R' F L' B2 F
 

tsmosher

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Next: L2 F2 U L2 D' U' B2 L2 D' B2 U' B2 L B U F2 R' F L' B2 F

So, here is one place I get confused with how to proceed.

Let's say I start:
z' y B

#5 in #1. #6 in #6. #4 in #2. Lightning bolt tracelet going 2-4-3-5. Tracing it out, I get a CP of 4-3-2-1, i.e. 3-2.

Now, what is the best way to do a diagonal swap on the U face?

By corollary, what is the best way to do a diagonal swap on the R face?

Thanks...
 

Cuberstache

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So, here is one place I get confused with how to proceed.

Let's say I start:
z' y B

#5 in #1. #6 in #6. #4 in #2. Lightning bolt tracelet going 2-4-3-5. Tracing it out, I get a CP of 4-3-2-1, i.e. 3-2.

Now, what is the best way to do a diagonal swap on the U face?

By corollary, what is the best way to do a diagonal swap on the R face?

Thanks...
You don't need to do a diagonal swap on the U face in this case. Simply F R F' after your moves. But in the event that you do, you can do R F R F', R' F' U' F, or R2 F' U F depending on which one affects the DL edge more favorably. A diagonal swap on the R face means there's a swap pair in UFL and UBL, so do a U move to set it up to any one of the standard triggers.
 

tsmosher

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NEXT: L2 D2 L2 F2 D F2 U' R2 U' F2 L2 R' D' B R F D L F R'

I am trying to contribute to this thread but I am stuck here too.

x2 y' //inspection
//#5 in #1. (Odd.)
//#6 in #2.
//(Already friends.)
//Trace circlet: #3 > #4 > #5 > #6
//Yielding: 4-2-1-3
//Case 2-1: Swap #1 & #2

U' // moving #1 & #2 to #1 & #4
F' U' F // swap #1 & #4

// CP is not solved!
 
Last edited:

Cuberstache

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I am trying to contribute to this thread but I am stuck here too.

x2 y' //inspection
//#5 in #1. (Odd.)
//#6 in #2.
//(Already friends.)
//Trace circlet: #3 > #4 > #5 > #6
//Yielding: 4-2-1-3
//Case 2-1: Swap #1 & #2

U' // moving #1 & #2 to #1 & #4
F' U' F // swap #1 & #4

// CP is not solved!
You have the direction correct and everything but you should end up with 2-3. I think you just misnumbered the corners.

Edit: What I originally wrote is incorrect; 2-1 is the correct tracing but the corners that need to be swapped are the ones that belong in 1 and 2, not the ones there now.
 
Last edited:

tsmosher

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So I've come up with a slightly better way of recognizing CP if you are color neutral:

Look at the side and back colors of DBL first.

Next, find the 2 corners which have neither of these colors.
(These will be #4 and #5.)

Next, find the other bottom corner (by looking for the other corner containing your triplet's bottom color).
(This will be #6.)

From here, figure out your tracelet, and trace your corners.
(The one matching DBL's side color only is #1.)
(The one matching both of DBL's colors is #2.)
(The one matching DBL's back color only is #3.)

I have some more ideas on simplifying the tracelet concept, but they are not fully fleshed out yet.

NEXT: L2 D2 L2 F2 D F2 U' R2 U' F2 L2 R' D' B R F D L F R'

x2 y' //inspection
//#5 in #1. (Odd.)
//#6 in #2.
//(Already friends.)
//Trace circlet: #3 > #4 > #5 > #6
//Yielding: 4-2-1-3
//Case 2-1: Swap corners #4 & #6 (positions #2 and #3)

// YRUru-c

// 45 STM
F R F' // CP-line (3)
u' r' u U2 // pEO extension (4)
M U' M U' R2 U' r2 // EO+pseudo-BF (7)
U' R' U R U2 R' U R2 // pair 1 (8)
U' R' U2 R U' R' // pair 2 (6)
U2 R U2 R2 U' R2 U' R2 U2 R // OCLL (10)
U' M2 U M' U2 M' U2 // 4c (7)

Next: R F2 L U2 L' D2 F2 D2 B2 U2 R' D' B' U' L U2 B2 R2 F2 U'
 
Last edited:

Cuberstache

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Next: R F2 L U2 L' D2 F2 D2 B2 U2 R' D' B' U' L U2 B2 R2 F2 U'
y' x // yellow/red corners are one move away
F2 // Imagine this move done to solve the corners. After that we have 5 in 6 and 6 in 1, lightning bolt circlet backwards
// Trace positions 5-3-4-2, results in 2-1
// 5 can swap with 3. This swap pair is in locations 5 + 6 so the other swap pairs are in 1 + 3 and 2 + 4
// The edge is in a pretty bad position but we can solve it with CP at the same time by using an inefficient swap pair, see actual solution

y' x // Inspection
F2 r2 U f' U' F // CPLine (6/6)
u2 r2 R' U r u2 // pEO Ext. (6/12)
R U M' U' M' // EO (5/17)
U' R U' M2 // BF (4/21)
U2 R' U2 R // Square (4/25)
U2 R U' R' U2 R U' R' // F2L (7/32)
U R U R' U' R U R2 U' R2 U' R' U R U' R' U R' U R U2 // 2GLL (21/53)


NEXT: D B' R' B2 U2 L2 R' F2 R2 B2 R' U2 L' D2 B' R2 U L U2 B2 R
 

tsmosher

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NEXT: U2 F2 D2 L B' D2 L' F U' F2 D2 B U2 F' U2 L2 F' U2 R2 B2

YruRU-c
(56 STM)

z'
// #5 and #6 almost friends in positions #3 and #6.
// tracelet (with corner #5 in position #6 after R): 5421
// corner #4 in position #1.
// 32 case
// corner #1 in DFL (have to swap #1/#3)
// corner #3 in position #5. DFL in position #2.
U' R U' // corner #3 in position #3. DFL in position #4. (F2 away from being solved)
F2 // CP-line! (4)
u' r' M2 u R // 3QB (5/9) - to make EO easy to spot: 3rd belt edge in BR - last belt edge in UF
M U r U M' U r' // EO (7/16): M U M' --> R U R' --> r U r'
U2 R U // BR pair (3/19)
R2 U' R' U2 R U' R' // FR pair (7/26)
U M' U2 M // insert UF edge into DF (4/30) - finishes pseudo-BF
R U2 R' U' R U' R2 U2 R U R' U R // OCLL (13/43)
U S' U2 S // solve DR edge (4/47)
U' M2 U M' U2 M U2 M2 U' // L6EP (9/56)

Next: R' F' B2 R' D2 U2 B2 L' D2 B2 D2 B2 R D' R' D2 U2 L' B' L U'
 

tsmosher

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NEXT: B' U D B2 L' D R' B2 U' F2 R2 F2 D R2 D L2 B2 D F'

This scramble feels a bit like cheating.

y2 x' // F solves DFL in this orientation
F // #5 and #6 almost friends in positions #5 and #4 respectively.
R' // After R'-- making #5 and #6 friends-- #5 in position #6.
// (So the tracelet is reversed.) Tracelet: 4321.
// #4 in position #1.
// 12 case. CP solved! (First time I've gotten this case.)

u R2 U2 R' u2 R // 3QB (8)

// BR belt edge in BR
// FR belt edge in UB
// 2 bad edges: DR UL

U' r U R U r // EO (6/14)
R U2 R' U R2 // dFR (5/19)
r' U2 r // finish pseudo-BF (3/22)
U' L E2 L' U2 L E2 L' // solve BR edge/pair (8/30)
U R U2 R2 U' R2 U' R2 U2 R // OCLL (10/40)
M2 U' M U2 M2 U2 M' U // L6EP (8/48)

NEXT: D' B2 D2 B2 U R2 U' L2 F2 L2 B2 U' L D R F U B2 D' B' R'
 

tsmosher

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When CP is solved but DFL is unsolved, you must position corner #X (i.e., the actual DFL) in position #4 and execute FUF or F'R'F'. (The other triggers that set up an F/F' away do not work btw.)

I used this as an opportunity to test out my new tracelet system which is much simpler. So don't pay too much attention to those comments in my solution below.

My solution

Hope this helps. Message me with any questions.

ninja edit: in your comments, 6 is in 2, and 5 is in 3
 
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NEXT: D' B2 D2 B2 U R2 U' L2 F2 L2 B2 U' L D R F U B2 D' B' R'
First proper successful YruRU attempt(thanks @tsmosher for telling me that I traced the circlet in the wrong direction): 62 STM
y //inspection
//6 in 2, 5 in 3, 4 in UFL so I mentally swap 4 and UFL
//reading the circlet cw, I get 1-2 tracing
R' U R U F U f //CPLine
r U u' R2 U2 r' u2 //pEO Extension
R' r' U' r2 U r' R r U R' U' r' //EOBF
U' R U' R2 U2 R' //Square
U' R' U' R U R' U2 R //LS
U R U R' U R U' R' U R U2 R2 U R' U' R' U' R' U R U R2 //LL


Next: R2 U B2 U2 R2 F2 L2 F2 U2 F2 U F2 R D B' F' L' U' B2 R U2 L
 
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