Inspecting CP in inspection allows us to solve the

Many cubers, notably

If you find it game-changing, or otherwise, let me know. I'll be putting this up along with the numbering system on some facebook groups, and on youtube.

On an overall level, it has an average move count of 45-50, and is similar to Roux in execution, except we have 2GLL instead of CMLL, and there is no MU turning necessary.

Scramble: D2 R2 D2 R2 F’ R2 B’ D2 B F’ D F D’ U2 B D’ U B’ L R

R U x’ // 113

It takes 2-3 moves to make a 1x1x3 with white or yellow on one of the sides with 3 pieces (there are 8 such bars possible). This has to be placed in bottom left.

U2 F’ U F // CP

This takes 3-4 moves, and I have developed a numbering system to figure out how to do CP. Since all this is seen in inspection, there is no question of recognition time; and this step is extremely flexible (my numbering system gives 12 solutions that are 4 moves or less) so influencing the next step is very easy.

This is as far as needs to be seen in inspection, however, seeing much farther is possible (for reference, doing this with my numbering system is far easier than making an EO line in inspection)..

Now the cube is reduced to RUru.

U r u R’ U2 R’ u2 // 123

The cube is now reduced to RUr.

The previous step was quite simple and almost always ends with u2, so it is a great opportunity to look ahead.

r U2 r’ U’ R r U’ r’ // EO

R’ U’ r2 // 223

The above two can in advanced solves be combined like EOLR in Roux.

Now, the cube is solvable 2gen, we know how quick that can be.

1/6 of the time we get a CP skip. That’s 4 less moves, two of which are F or D; and allows us to see further into the solve during inspection.

These by no means are perfectly done solves, but they do show the method's general idea; and the high probability of lucky solves adds to it as evident in solve 5.

Scramble 1: R2 U’ B2 R2 D’ F2 D B2 R2 D2 B F2 U L2 R U L’ R’ F2 D

Solution 1: z // inspection

R S // 113

R2 F’ U’ F // CP

u’ R u’ R U R u2 // 123

R2 U R’ r U’ r // EO

R U2 R U r2 // 2-gen reduction

Scramble 2: F U2 B’ U2 L2 R2 F2 R2 F D’ U’ B R D’ R2 D’ L R2 D’ U

Solution 2: x2 // inspection

R’ F // 113

R F’ U’ F // CP

u R u R’ U2 R u2 // 123

R U R U r U’ r’ // EO

R’ U R U’ r2 // 2-gen reduction

Scramble 3: D2 R2 D2 R2 F’ R2 B’ D2 B F’ D F D’ U2 B D’ U B’ L R

Solution 3: x’ // inspection

R F // 113

U2 F’ U F // CP

U r u R’ U2 R’ u2 // 123

r U2 r’ U’ R r U’ r’ // EO

R’ U’ r2 // 2-gen reduction

Scramble 4: D2 F2 R B2 D2 B2 R’ F2 L’ B2 F2 U F D L’ F’ D B’ U L2

Solution 4: z y // inspection

F U’ f’ U F // 113 + CP

U r U r’ R’ U’ R’ u2 // 123

r U’ R2 U r U’ r // EO

U R’ U’ r2 // 2-gen reduction

Scramble 5: D’ B2 U B2 U’ F2 L2 U2 B2 U’ F L2 B U’ R F2 D R’ B2 L2

Solution 5: z2 y // inspection

S2 U’ F2 // 113

CP Skip!

U R’ u’ r’ R2 U R’ u2 // 123

U’ r U R U r U’ r’ // EO (+ block)

U r’ U2 r’ // 2-gen reduction (+ block)

R U2 R U2 R’ U’ R U R’ // F2L

U’ // 2-GLL Skip!

1/6 chance of CP skip, 1/324 chance of LL skip (1/108 if you do phasing, 1/12 if you do WV) Plus extremely high TPS for most of the solve, which would be under 50 moves long.

I’ll put up the numbering system.

If the method looks promising, let me (and others) know!

The method is called

EDIT: Here is the website for the method if you’re interested in having a look at the updated version (as of late June 2020).

**entire cube 2-gen**.Many cubers, notably

**Jayden**and**Bhargav**are particularly excited by this idea; and this can potentially**beat Roux for One-handed**solving.If you find it game-changing, or otherwise, let me know. I'll be putting this up along with the numbering system on some facebook groups, and on youtube.

On an overall level, it has an average move count of 45-50, and is similar to Roux in execution, except we have 2GLL instead of CMLL, and there is no MU turning necessary.

**The idea is simple: Reduce the cube to be solvable using**

(First) u, r, U, R

(Then) r, U, R

(And finally) U, R(First) u, r, U, R

(Then) r, U, R

(And finally) U, R

Scramble: D2 R2 D2 R2 F’ R2 B’ D2 B F’ D F D’ U2 B D’ U B’ L R

R U x’ // 113

It takes 2-3 moves to make a 1x1x3 with white or yellow on one of the sides with 3 pieces (there are 8 such bars possible). This has to be placed in bottom left.

U2 F’ U F // CP

This takes 3-4 moves, and I have developed a numbering system to figure out how to do CP. Since all this is seen in inspection, there is no question of recognition time; and this step is extremely flexible (my numbering system gives 12 solutions that are 4 moves or less) so influencing the next step is very easy.

This is as far as needs to be seen in inspection, however, seeing much farther is possible (for reference, doing this with my numbering system is far easier than making an EO line in inspection)..

Now the cube is reduced to RUru.

U r u R’ U2 R’ u2 // 123

The cube is now reduced to RUr.

The previous step was quite simple and almost always ends with u2, so it is a great opportunity to look ahead.

r U2 r’ U’ R r U’ r’ // EO

R’ U’ r2 // 223

The above two can in advanced solves be combined like EOLR in Roux.

Now, the cube is solvable 2gen, we know how quick that can be.

1/6 of the time we get a CP skip. That’s 4 less moves, two of which are F or D; and allows us to see further into the solve during inspection.

**Here are some example solves**.These by no means are perfectly done solves, but they do show the method's general idea; and the high probability of lucky solves adds to it as evident in solve 5.

Scramble 1: R2 U’ B2 R2 D’ F2 D B2 R2 D2 B F2 U L2 R U L’ R’ F2 D

Solution 1: z // inspection

R S // 113

R2 F’ U’ F // CP

u’ R u’ R U R u2 // 123

R2 U R’ r U’ r // EO

R U2 R U r2 // 2-gen reduction

Scramble 2: F U2 B’ U2 L2 R2 F2 R2 F D’ U’ B R D’ R2 D’ L R2 D’ U

Solution 2: x2 // inspection

R’ F // 113

R F’ U’ F // CP

u R u R’ U2 R u2 // 123

R U R U r U’ r’ // EO

R’ U R U’ r2 // 2-gen reduction

Scramble 3: D2 R2 D2 R2 F’ R2 B’ D2 B F’ D F D’ U2 B D’ U B’ L R

Solution 3: x’ // inspection

R F // 113

U2 F’ U F // CP

U r u R’ U2 R’ u2 // 123

r U2 r’ U’ R r U’ r’ // EO

R’ U’ r2 // 2-gen reduction

Scramble 4: D2 F2 R B2 D2 B2 R’ F2 L’ B2 F2 U F D L’ F’ D B’ U L2

Solution 4: z y // inspection

F U’ f’ U F // 113 + CP

U r U r’ R’ U’ R’ u2 // 123

r U’ R2 U r U’ r // EO

U R’ U’ r2 // 2-gen reduction

Scramble 5: D’ B2 U B2 U’ F2 L2 U2 B2 U’ F L2 B U’ R F2 D R’ B2 L2

Solution 5: z2 y // inspection

S2 U’ F2 // 113

CP Skip!

U R’ u’ r’ R2 U R’ u2 // 123

U’ r U R U r U’ r’ // EO (+ block)

U r’ U2 r’ // 2-gen reduction (+ block)

R U2 R U2 R’ U’ R U R’ // F2L

U’ // 2-GLL Skip!

1/6 chance of CP skip, 1/324 chance of LL skip (1/108 if you do phasing, 1/12 if you do WV) Plus extremely high TPS for most of the solve, which would be under 50 moves long.

I’ll put up the numbering system.

If the method looks promising, let me (and others) know!

The method is called

**YruRU**(Vaay-roo-roo).EDIT: Here is the website for the method if you’re interested in having a look at the updated version (as of late June 2020).

Last edited: Jul 5, 2020