I'm not sure if this was proposed or not, but i don't like the usual way of reducing into DR by simply orienting the edges and then the corners. My ideas is to orient the edges and corners simultaneously.
How: just like the edges you can orient the corners by doing F/F'/B/B'.
The goal is to have 4/8 unoriented or all oriented corners, to then solve them. At the same time before you do an F/F'/B/B' you permute the edges (by doing setups or using commutators) to F/B. Then, when everything is oriented, put 2 edges opposite to L/R (one on D and one on U), do L/ R (if edges on L do R, if on R do L), S2 , undo setup.
Tips:
Also, can someone make an example solving for me? I'm not good at those ¯\_(ツ)_/¯
How: just like the edges you can orient the corners by doing F/F'/B/B'.
The goal is to have 4/8 unoriented or all oriented corners, to then solve them. At the same time before you do an F/F'/B/B' you permute the edges (by doing setups or using commutators) to F/B. Then, when everything is oriented, put 2 edges opposite to L/R (one on D and one on U), do L/ R (if edges on L do R, if on R do L), S2 , undo setup.
Tips:
- If you've oriented the corners and still need to orient the edges, every time you do an F/B, complete with U' D R if on F, U D' R' if in B.
- If you've oriented the edges and need to orient the corners, move the corners to L/R, and complete just like on F/B, but with L/R moves
- If corners are facing up/down or left/right, they will get unoriented/oriented, but those facing you won't get oriented
- When you need to make the belt, if you have only one or three in place replace them with 2 equator edges if one, and replace the last edge with any other 2 edges if 3 in place
Also, can someone make an example solving for me? I'm not good at those ¯\_(ツ)_/¯