# Ground-breaking ZZ variant: ZIF (ZZ-Final) [LS alg subset that reduces ZBLLs case + AUF LL]

#### Lazy Einstein

##### Alg Ninja
Similarly, to how phasing reduces ZBLL to ZZLL in ZZ-b, ZiF(ZZ-F):
- reduces ZBLL to my LL subset of ZBLL called LEZB [Lazy Einstein's ZBLL (and can be said as LEZBaLLs. ...hmm. Maybe Lezbos? ...I'll work on this later.]; and,
- does so using my LS subset BHLS [(Brant Holbein Last Slot) Take that, James! Muhahaha. (BLS is used already =/.)]

BHLS (Brant Holbein's Last Slot)
- For beginner BHLS (FR slot only. looking at all 4 LS later), a ZZF2L setup algs used to place the last pair to UL/UBL, then inserted uses R U2 R' and U' R U' R'.
- Incredibly, I have found the algs in BHLS are almost completely the intuitive ways to set up the pair UL/UBL(a few exceptions).
- The final thing that makes BHLS its own LS subset is the control of the LL that using UFR/UBR CO recognition to insert the last pair, via R U2 R' and U' R U' R', gives.
- Due to unavoidable phasing in ZZF2L set up algs, adj CO ZBLLs (U/T) are both reduced below 72 cases.

LEZB (Lazy Einstein's Last Layer)
- After LS, we have only 72 L ZBLLs to and only 42 for U/T ZBLLs.
72 + 42 + 42 = 156 ZBLLs for LEZB (More math, reasons, etc below summary)
All LEZB ZBLLs include AUF

The fact that the cons are virtually removed due to the intuitive nature of BHLS. Makes Zif extremely likely to be better than CFOP, ZZ-a, and Roux for TH/OH.
And, if a version of ZBLS can be made with BHLS, this could contend for the best method for big cubes as well.

Let me know what you think.

APRIL FOOLS!

APRIL FOOLS!

APRIL FOOLS!

APRIL FOOLS!

#### PapaSmurf

##### Member
Like actually seriously, reducing to TULO ZBLL is not a bad idea if you really want a 1LLL and don't like S/As/Pi/H.

#### N's-cvt

##### Member
This post put a smile on my face, good job!

#### Lazy Einstein

##### Alg Ninja
Like actually seriously, reducing to TULO ZBLL is not a bad idea if you really want a 1LLL and don't like S/As/Pi/H.
Honestly, there is probably a smart way to actually do this. Perhaps at least a way to learn LS to force it with some level of worthwhile control.

#### Cubing Forever

##### Member
Whoa you got me there for a while lol.
Btw ZZ-Blah exists but it reduces to H/Pi. This april fools joke is actually useful if implemented if someone gens algs for the LS.

#### carcass

##### Member
but TUL>H+PI
It would be kind of strange to force a TUL. Their most obvious feature is that they all have two corners oriented. This would, of course, include PLL. I suppose you could just make ZZ-C but the algs would be more friendly since you are taking TUL+PLL instead of just PLL. I think this would be around 700-800 algs, which is basically full ZB, but the edges are oriented because ZZ, and the algs are epiccer because TUL. Overall, the algs probably wouldn't even be that long, maybe to the extent that it would be difficult to call them an algorithm as apposed to just a trigger. I think this could work, if somebody had the time. I wonder how this would do compared to ZZ-A and ZZ-C.
As a result, the steps would be:
ZZ-F2L minus FR pair(to avoid thousands of cases)
Last Pair+Orient 2 LL corners
do the TUL or PLL