• Welcome to the Speedsolving.com, home of the web's largest puzzle community!
    You are currently viewing our forum as a guest which gives you limited access to join discussions and access our other features.

    Registration is fast, simple and absolutely free so please, join our community of 40,000+ people from around the world today!

    If you are already a member, simply login to hide this message and begin participating in the community!

FB 1x2x3 Example Solve Thread

tsmosher

Member
Joined
Aug 30, 2020
Messages
734
z2 y' // this places the DLS edge in position and gives an easy corner edge pair.

M2 F' // this pairs the corner edge pair and solves it to make a 1x2x2 square in dfL.

R // this places the DBL corner in position to be solved in the back with the BLE edge.

U' M2 B' // this moves the DLE edge to be paired with the DBL corner and then that corner edge pair is inserted with a B'.

6 moves.

Next: D F' L2 F' R2 D' F2 U R F' L2 U2 F' R2 B R2 D2 R2 F' U2

// This is a tough scramble for me, and I will be using a color-neutral FB as a result.

y2 z // In this orientation, I see that F' will join together a corner/edge pair in DfL.
S // But I can do better! Instead of bringing down the corner, I can bring up the edge in DLS!
r' // this completes a cute little square, which we can then put back on our L layer with...
f' // dfR complete.

// we just need the back pair. I notice that my D center and B center are also aligned at this point. (dumb luck)
// The other corner is misoriented in UBL. It's gonna take me ~3 moves to insert it into the triplet.
// Since it will take a lot of moves, I'd like to join the corner with its matching edge while I am preparing it for insertion.

// The matching edge is in DFM, so pairing is pretty easy with:
U M2 // pair formed in UBr. But it's not oriented correctly, so I will have to mess up some centers to get it in quickly.
r B' // inserted into FB. FB is complete!

// without verbose comments:
y2 z S r' f' U M2 r B' // Total moves: 7 (Roux FB)

NEXT:
D2 R' F2 D2 L F2 D2 R D2 R B2 D U' R' D2 L' U2 F U2 B2 R
 
Last edited:

voidrx

Member
Joined
Apr 1, 2020
Messages
154
// This is a tough scramble for me, and I will be using a color-neutral FB as a result.

y2 z // In this orientation, I see that F' will join together a corner/edge pair in DfL.
S // But I can do better! Instead of bringing down the corner, I can bring up the edge in DLS!
r' // this completes a cute little square, which we can then put back on our L layer with...
f' // dfR complete.

// we just need the back pair. I notice that my D center and B center are also aligned at this point. (dumb luck)
// The other corner is misoriented in UBL. It's gonna take me ~3 moves to insert it into the triplet.
// Since it will take a lot of moves, I'd like to join the corner with its matching edge while I am preparing it for insertion.

// The matching edge is in DFM, so pairing is pretty easy with:
U M2 // pair formed in UBr. But it's not oriented correctly, so I will have to mess up some centers to get it in quickly.
r B' // inserted into FB. FB is complete!

// without verbose comments:
y2 z S r' f' U M2 r B' // Total moves: 7 (Roux FB)

NEXT:
D2 R' F2 D2 L F2 D2 R D2 R B2 D U' R' D2 L' U2 F U2 B2 R

You missed a very good FB in that scramble.

z y M' (B' F2) R F
Technically four moves.
Now to the current scramble.

y2 // I see that the FLE edge is paired with its center so I decide to go with that.

(U' D') // these two moves are done at the same time, so it is one move. This pairs the dBL pair and gets the DfL pair in position to be solved.

M U2 R2' // this pairs the DfL pair and moves the dBL pair to uFR.

D' // this solves the dfL square.

R U' B // this solves the remaining pair and finishs the FB.

8 moves.

Next: F' R L' B L2 U' B2 D' R B2 D R2 L2 D' F2 D B2 D F2 D
 

voidrx

Member
Joined
Apr 1, 2020
Messages
154
You missed a very good FB in that scramble.

z y M' (B' F2) R F
Technically four moves.
Now to the current scramble.

y2 // I see that the FLE edge is paired with its center so I decide to go with that.

(U' D') // these two moves are done at the same time, so it is one move. This pairs the dBL pair and gets the DfL pair in position to be solved.

M U2 R2' // this pairs the DfL pair and moves the dBL pair to uFR.

D' // this solves the dfL square.

R U' B // this solves the remaining pair and finishs the FB.

8 moves.

Next: F' R L' B L2 U' B2 D' R B2 D R2 L2 D' F2 D B2 D F2 D

I like doing these and I don't like to wait for the next person, so imma do this one too.

y' x' // there is a non-matching centers square so I position it in dbL.

R' U' // this pairs the other pair.

R' U F' // this solves the non matching center FB.

5 STM

Next: R' F' D2 L' U' B' D' L' F R F2 R2 D2 R F2 U2 R D2 L' B2
 

tsmosher

Member
Joined
Aug 30, 2020
Messages
734
I like doing these and I don't like to wait for the next person, so imma do this one too.

y' x' // there is a non-matching centers square so I position it in dbL.

R' U' // this pairs the other pair.

R' U F' // this solves the non matching center FB.

5 STM

Next: R' F' D2 L' U' B' D' L' F R F2 R2 D2 R F2 U2 R D2 L' B2
Back with another terrible FB :)

x' // At this angle, I see that B will form a corner/edge pair in DbL.
// Let's pair up the corner with its matching edge before inserting it.
R E // This pairs them up. This also dictates that I will be forming Mehta FB (Dl).
r // Influencing the D center just makes things easier for us later. This move puts the D center on the D layer.
B // Dbl square has been formed. Time for FBLS (DFl).
R2 // R prepares the corner for insertion into the Mehta FB. But the matching edge is in UBM. So better to go one quarter turn further and pair up corner and edge.
U R' F // inserts the misoriented pair into the front of the Mehta FB.

// total moves: 8

NEXT:
D' U2 R' U2 L' D2 F2 D2 B2 R2 U2 R D2 U R' B2 U L2 F' D' B'
 

ray5

Member
Joined
Oct 10, 2020
Messages
37
y' x'

R' D'
L' U'
R U R'
L2


(8h)

Next: U' R2 F2 D F2 U B2 U' B2 U2 L2 B2 R' B F D B2 R' D2 F L'
 

tsmosher

Member
Joined
Aug 30, 2020
Messages
734
y' x'

R' D'
L' U'
R U R'
L2


(8h)

Next: U' R2 F2 D F2 U B2 U' B2 U2 L2 B2 R' B F D B2 R' D2 F L'

x // seeking to take advantage of the pre-formed corner-edge pair in DbL
M // this aligns the D center and solves DBM (thus solving a square in Dbl)
F // move the orange yellow edge up to be joined with DFL
R' // joins DFL with orange yellow edge (i.e., DFM)
F2 // completes Mehta FB (Dl)

// 4 STM, x2/y neutral Mehta FB

NEXT:
L2 U L' U2 F' D R U' F' L2 D2 F2 R2 U2 F U2 F L2 B D2
 

ray5

Member
Joined
Oct 10, 2020
Messages
37
y' // orange
B2 // pair up
D F' // align on bottom
U D M // connect

(7h)

Next: U2 B2 U' F2 L F' U D B' R2 D F2 D' L2 D' B2 L2 U2 F2 L2
 

ray5

Member
Joined
Oct 10, 2020
Messages
37
[R':U'] L
B2
U L2
L' F2 L F'

(11h)

I really struggled with this one. I could not find a good solution.

Next: L2 R2 B' L2 D2 R2 U2 B2 F2 R2 U2 F D' F2 R F D' F' U B R'
 

voidrx

Member
Joined
Apr 1, 2020
Messages
154
[R':U'] L
B2
U L2
L' F2 L F'

(11h)

I really struggled with this one. I could not find a good solution.

Next: L2 R2 B' L2 D2 R2 U2 B2 F2 R2 U2 F D' F2 R F D' F' U B R'


So I see the blue red edge is connected to the blue center and I can pair the DLS edge with the DFL corner by doing z y' D'. Then I do an R' to bring the DfL pair to the D layer.
Now, I'd I just did a D2 to solve the square, it would leave the last pair in a difficult spot, so instead, I will do a D R2 to move the BLE edge to a better spot. Then I do another D to solve the square and it happens to pair the last pair together. So then I finish with an R2 B2.

Full Solution:
z y'
D' R' D R2 D R2 B2

7 STM

Next: L2 F' U L' U2 L2 D R U D2 F R2 F2 U2 D2 L2 D2 L2 B L2 F
 

tsmosher

Member
Joined
Aug 30, 2020
Messages
734
So I see the blue red edge is connected to the blue center and I can pair the DLS edge with the DFL corner by doing z y' D'. Then I do an R' to bring the DfL pair to the D layer.
Now, I'd I just did a D2 to solve the square, it would leave the last pair in a difficult spot, so instead, I will do a D R2 to move the BLE edge to a better spot. Then I do another D to solve the square and it happens to pair the last pair together. So then I finish with an R2 B2.

Full Solution:
z y'
D' R' D R2 D R2 B2

7 STM

Next: L2 F' U L' U2 L2 D R U D2 F R2 F2 U2 D2 L2 D2 L2 B L2 F

z2 // taking advantage of corner/edge pair in DfL
S' // displace orange center (and temporarily DLS)
E S // move flipped FLE edge over and attach to orange center (orienting it)
R2 // correctly permute FLE
u2 // E2 completes the square in dfL -- doing U2 at the same time sets up DBR to be joined with BLE after M'
M' // joins DBR and BLE (inadvertently solves DFM as well)
U2 B // inserts back pair, completing FB

z2 S' E S R2 u2 M' U2 B // Roux FB, 8 STM, also solves DFM (inadvertent)

NEXT:
U2 B2 D R2 U2 R2 B2 D R2 D' L2 B2 R B U' F2 U' L B' L D2
 

voidrx

Member
Joined
Apr 1, 2020
Messages
154
L D' B2 // setting up LF and LB edges
R' L2 // Build a line
D' // Finish FB

Next :
U' R2 F' U2 B' D2 L2 D2 F D2 U2 B2 R' B' D F' R2 F D2 U2
So first I see the orange green yellow pair and the orange green edge can be solved into a square by doing U' r' u. But i want to put the last pair in a better position, so I do an R' first. so it would be R' U' r'. Now if I did a u, it would move the last pair edge into a worse spot, so I am going to do an E'. then to finish it off, I do R U2 B
Full Solution:
z
R' U' r' E' R U2 B

Next: U2 F2 D L2 F2 L2 B2 U2 R2 D F2 U' F' L' U2 B' D R2 B2 L' U' R
 

tsmosher

Member
Joined
Aug 30, 2020
Messages
734
So first I see the orange green yellow pair and the orange green edge can be solved into a square by doing U' r' u. But i want to put the last pair in a better position, so I do an R' first. so it would be R' U' r'. Now if I did a u, it would move the last pair edge into a worse spot, so I am going to do an E'. then to finish it off, I do R U2 B
Full Solution:
z
R' U' r' E' R U2 B

Next: U2 F2 D L2 F2 L2 B2 U2 R2 D F2 U' F' L' U2 B' D R2 B2 L' U' R

EDIT: Improvement suggested by @voidrx .

z2 y
F' // forming pair in DfR
R F2 // inserting pair and forming square in dfL
R // forming pair in DBr
B' // inserting pair to finish FB

z2 y F' R F2 R B' // Roux FB, 5 STM

R2 S' b // forms triplet in DL
U // moves the white/green edge out of the way
M' // attach white center to white/blue edge
u2 R // attach white/green edge
u' // align FB

R2 S' b U M' u2 R u' // Roux FB, 8 STM

NEXT:
B R U2 R F' D' R F' L F2 D2 F' D2 L2 D2 F2 D2 F' R2 U2
 
Last edited:

voidrx

Member
Joined
Apr 1, 2020
Messages
154
R2 S' b // forms triplet in DL
U // moves the white/green edge out of the way
M' // attach white center to white/blue edge
u2 R // attach white/green edge
u' // align FB

R2 S' b U M' u2 R u' // Roux FB, 8 STM

NEXT:
B R U2 R F' D' R F' L F2 D2 F' D2 L2 D2 F2 D2 F' R2 U2

So I see the red blue yellow pair can be paired with the red blue edge by doing y2 x E2 R E2. However. I want to influence the last pair which is already made by doing a u2 in place of the last E2. So it would be y2 x E2 R u2. Then I finish the FB with r B'.

Full Solution
y2 x
E2 R u2 r B'

5 STM

Next: L2 U B2 U' R2 B2 D F2 D' U2 B2 F2 L' B2 R' F D R2 B2 L D
 

voidrx

Member
Joined
Apr 1, 2020
Messages
154
z' y
D [R:U']
L' U B'

(7h, 7q, 7s, 9e)

Next: L R2 D' L2 R2 D U2 F2 U' F2 R2 U' L2 F D R' B2 D' U' F2 U2

I see that I can make a square with the premade pair by doing y2 D' r B'.
Then I can make the other pair by doing U' R' and solving the pair with U2 F'

Full Solution:
y2
D' r B' U' R U2 F'

7 STM

Next: R2 D' R2 U L2 B2 R2 F2 D' R2 D2 U2 B U2 R2 F' D B2 L U R2 D2
 
Top