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// This is a tough scramble for me, and I will be using a color-neutral FB as a result.

y2 z // In this orientation, I see that F' will join together a corner/edge pair in DfL.
S // But I can do better! Instead of bringing down the corner, I can bring up the edge in DLS!
r' // this completes a cute little square, which we can then put back on our L layer with...
f' // dfR complete.

// we just need the back pair. I notice that my D center and B center are also aligned at this point. (dumb luck)
// The other corner is misoriented in UBL. It's gonna take me ~3 moves to insert it into the triplet.
// Since it will take a lot of moves, I'd like to join the corner with its matching edge while I am preparing it for insertion.

// The matching edge is in DFM, so pairing is pretty easy with:
U M2 // pair formed in UBr. But it's not oriented correctly, so I will have to mess up some centers to get it in quickly.
r B' // inserted into FB. FB is complete!

// without verbose comments:
y2 z S r' f' U M2 r B' // Total moves: 7 (Roux FB)

NEXT:
D2 R' F2 D2 L F2 D2 R D2 R B2 D U' R' D2 L' U2 F U2 B2 R

// This is a tough scramble for me, and I will be using a color-neutral FB as a result.

y2 z // In this orientation, I see that F' will join together a corner/edge pair in DfL.
S // But I can do better! Instead of bringing down the corner, I can bring up the edge in DLS!
r' // this completes a cute little square, which we can then put back on our L layer with...
f' // dfR complete.

// we just need the back pair. I notice that my D center and B center are also aligned at this point. (dumb luck)
// The other corner is misoriented in UBL. It's gonna take me ~3 moves to insert it into the triplet.
// Since it will take a lot of moves, I'd like to join the corner with its matching edge while I am preparing it for insertion.

// The matching edge is in DFM, so pairing is pretty easy with:
U M2 // pair formed in UBr. But it's not oriented correctly, so I will have to mess up some centers to get it in quickly.
r B' // inserted into FB. FB is complete!

// without verbose comments:
y2 z S r' f' U M2 r B' // Total moves: 7 (Roux FB)

NEXT:
D2 R' F2 D2 L F2 D2 R D2 R B2 D U' R' D2 L' U2 F U2 B2 R

x' // At this angle, I see that B will form a corner/edge pair in DbL.
// Let's pair up the corner with its matching edge before inserting it.
R E // This pairs them up. This also dictates that I will be forming Mehta FB (Dl).
r // Influencing the D center just makes things easier for us later. This move puts the D center on the D layer.
B // Dbl square has been formed. Time for FBLS (DFl).
R2 // R prepares the corner for insertion into the Mehta FB. But the matching edge is in UBM. So better to go one quarter turn further and pair up corner and edge.
U R' F // inserts the misoriented pair into the front of the Mehta FB.

// total moves: 8

NEXT:
D' U2 R' U2 L' D2 F2 D2 B2 R2 U2 R D2 U R' B2 U L2 F' D' B'

x // seeking to take advantage of the pre-formed corner-edge pair in DbL
M // this aligns the D center and solves DBM (thus solving a square in Dbl)
F // move the orange yellow edge up to be joined with DFL
R' // joins DFL with orange yellow edge (i.e., DFM)
F2 // completes Mehta FB (Dl)

// 4 STM, x2/y neutral Mehta FB

NEXT:
L2 U L' U2 F' D R U' F' L2 D2 F2 R2 U2 F U2 F L2 B D2

So I see the blue red edge is connected to the blue center and I can pair the DLS edge with the DFL corner by doing z y' D'. Then I do an R' to bring the DfL pair to the D layer.
Now, I'd I just did a D2 to solve the square, it would leave the last pair in a difficult spot, so instead, I will do a D R2 to move the BLE edge to a better spot. Then I do another D to solve the square and it happens to pair the last pair together. So then I finish with an R2 B2.

Full Solution:
z y'
D' R' D R2 D R2 B2

7 STM

Next: L2 F' U L' U2 L2 D R U D2 F R2 F2 U2 D2 L2 D2 L2 B L2 F

So I see the blue red edge is connected to the blue center and I can pair the DLS edge with the DFL corner by doing z y' D'. Then I do an R' to bring the DfL pair to the D layer.
Now, I'd I just did a D2 to solve the square, it would leave the last pair in a difficult spot, so instead, I will do a D R2 to move the BLE edge to a better spot. Then I do another D to solve the square and it happens to pair the last pair together. So then I finish with an R2 B2.

Full Solution:
z y'
D' R' D R2 D R2 B2

7 STM

Next: L2 F' U L' U2 L2 D R U D2 F R2 F2 U2 D2 L2 D2 L2 B L2 F

z2 // taking advantage of corner/edge pair in DfL
S' // displace orange center (and temporarily DLS)
E S // move flipped FLE edge over and attach to orange center (orienting it)
R2 // correctly permute FLE
u2 // E2 completes the square in dfL -- doing U2 at the same time sets up DBR to be joined with BLE after M'
M' // joins DBR and BLE (inadvertently solves DFM as well)
U2 B // inserts back pair, completing FB

z2 S' E S R2 u2 M' U2 B // Roux FB, 8 STM, also solves DFM (inadvertent)

NEXT:
U2 B2 D R2 U2 R2 B2 D R2 D' L2 B2 R B U' F2 U' L B' L D2

So first I see the orange green yellow pair and the orange green edge can be solved into a square by doing U' r' u. But i want to put the last pair in a better position, so I do an R' first. so it would be R' U' r'. Now if I did a u, it would move the last pair edge into a worse spot, so I am going to do an E'. then to finish it off, I do R U2 B
Full Solution:
z
R' U' r' E' R U2 B

Next: U2 F2 D L2 F2 L2 B2 U2 R2 D F2 U' F' L' U2 B' D R2 B2 L' U' R

So first I see the orange green yellow pair and the orange green edge can be solved into a square by doing U' r' u. But i want to put the last pair in a better position, so I do an R' first. so it would be R' U' r'. Now if I did a u, it would move the last pair edge into a worse spot, so I am going to do an E'. then to finish it off, I do R U2 B
Full Solution:
z
R' U' r' E' R U2 B

Next: U2 F2 D L2 F2 L2 B2 U2 R2 D F2 U' F' L' U2 B' D R2 B2 L' U' R

z2 y
F' // forming pair in DfR
R F2 // inserting pair and forming square in dfL
R // forming pair in DBr
B' // inserting pair to finish FB

z2 y F' R F2 R B' // Roux FB, 5 STM

Spoiler: old solution

R2 S' b // forms triplet in DL
U // moves the white/green edge out of the way
M' // attach white center to white/blue edge
u2 R // attach white/green edge
u' // align FB

R2 S' b U M' u2 R u' // Roux FB, 8 STM

NEXT:
B R U2 R F' D' R F' L F2 D2 F' D2 L2 D2 F2 D2 F' R2 U2

R2 S' b // forms triplet in DL
U // moves the white/green edge out of the way
M' // attach white center to white/blue edge
u2 R // attach white/green edge
u' // align FB

R2 S' b U M' u2 R u' // Roux FB, 8 STM

NEXT:
B R U2 R F' D' R F' L F2 D2 F' D2 L2 D2 F2 D2 F' R2 U2

So I see the red blue yellow pair can be paired with the red blue edge by doing y2 x E2 R E2. However. I want to influence the last pair which is already made by doing a u2 in place of the last E2. So it would be y2 x E2 R u2. Then I finish the FB with r B'.

Full Solution
y2 x
E2 R u2 r B'

5 STM

Next: L2 U B2 U' R2 B2 D F2 D' U2 B2 F2 L' B2 R' F D R2 B2 L D

I see that I can make a square with the premade pair by doing y2 D' r B'.
Then I can make the other pair by doing U' R' and solving the pair with U2 F'

Full Solution:
y2
D' r B' U' R U2 F'

7 STM

Next: R2 D' R2 U L2 B2 R2 F2 D' R2 D2 U2 B U2 R2 F' D B2 L U R2 D2