Crazy Domino guide

[Sakarie]

http://twistypuzzles.com/forum/viewtopic.php?f=15&t=16022

I'm calling this my method, since I use it. If some one else have invented the same, then we share it. But if you want to take credit for inventing the method, sure it's probably your first.. I found it on the first half of my 5 hour way home, so it's guaranteed not perfect.If you have a better algorithm, please share it.

It's good if you know how to solve a regular Domino cube. If you don't, its not that hard. And the only thing you actually have to learn is threecycle of edges, and solving the corners, but that's like Ortega on 2x2, so not that hard either.

Before you start solving, you have to find out which corners that controls the centers. For me it's the white-orange-blue one. It's definitely a corner, but I don't know if it's the same for everyone.

1. Solve corners
How you do it doesn't matter. I think the most advanced method is L5E http://sites.google.com/site/rectangularcuboids/3x3x2-domino/cp-force, and another one is solving one layer and then the other one using R2 U R2 U' R2 F2 U' F2 U F2 (a T-perm).

From now on, have your center-controlling corner in DBL position as standard. That way, we barely move it at all, and we won't get confused about the centers spinning.

2. Solve X-centers
X-centers is the "corner-centers". There are just a few possible cases. With the algorithm R2 U2 R2 U2 R2 you move the URF and UBR down to DFR and DRB. If you have to do a U2 move, to setup the corners to this position, you can't use the actuall U2, since that doesn't move the centers. (and if it does, it also moves the D-centers) Instead, we use a very special algorithm M' U2 M. You can actually do an M quarter turn, if it's followed by U2, D2 or another quarter M-turn. You may also use F2 U2 F2 U2 F2 to exchange the centers in F. (I'll write most of the algorithms in this standard position, but you may of course make a cube rotation to get <RU> or something). If you get two diagonal centers unsolved, R2 U2 R2 U2 R2 M' U2 M F2 U2 F2 U2 F2 should do the trick. But that is very unusual.

3. Solve +-centers
Fairly easy. If there is an unsolved center above an unsolved center in the D-layer, just do M' U2 M. And here you could cube rotate as much as you like (but only y, not z2 or x2). If there is two unsolved centers, neither above an unsolved center, you do M' U2 M', anywhere, and you can continue with the usual way. If you have 1 unsolved center NOT above an unsolved, there is an algorithm. Do R2 F2 R2 F2 R2 F2 starting in the standard position, and then you should be able to solve the last two with just two M' U2 M:s.

4. Solve first layer edges
If you've done a couple of solves, you could do all or parts of this in step 4, but it's not difficult at all to do by itself, without touching centers or corners. the algorithm is simply M' U2 M U2 M' U2 M, which moves the UB edge to DF (UB>DF>UF). Some times you have to use the algortihm to put a D-layer edge inte the U-layer, if you have swapped edges in D-layer. You can use M2 U2 M2 as well.

5. Solve last layer edges
Last and the most hard, sometimes. If you haven't parity (which means you've got an U, H or Z-perm), you can probably use your usual method. I use the algorithm R2 U R2 U R2 U2 R2 U2 R2 U R2 U R2 U2 R2, but you can use setup to UB>DF>UF, or R2 U2 R2 U2 R2 U2 with setups. Just make sure you DON'T move you center-controlling corner, since that may screw things up a bit.
If you don't recognize the PLL, you have parity. The usual way on domino is R2 U2 R2 U2 R2 U2, but that would unsolve the centers. The best algorithm I've found so far is R2 U2 R2 U2 R2 F2 U2 F2 U2 F2 R2 U2 R2 U2 R2 M' U2 M U2 M' U2 M U2 M' U2 M. It's NOT that good, but I haven't really searched for it.

---

If you can't understand, please explain the situation, and I'll try to explain better.

 

[iSpinz]

I thought of this method a long time ago, a little more efficient though. Your guide is pretty nice though.

Basically I would do everything the same until step 4. On step 4 I would use pair a inner and outer edge together and then use M' U2 M to put them in the right slot. After all 4 bottom edge pair thing on D were solved, I would just use U perms and parity algs to solve the rest.

I've gotten a sub-30 single and 35s average on it. What's your fastest time?

 

[Sakarie]

I thought of this method a long time ago, a little more efficient though. Your guide is pretty nice though.

Basically I would do everything the same until step 4. On step 4 I would use pair a inner and outer edge together and then use M' U2 M to put them in the right slot. After all 4 bottom edge pair thing on D were solved, I would just use U perms and parity algs to solve the rest.

I've gotten a sub-30 single and 35s average on it. What's your fastest time?

I haven't taken any time, so I just did an ao12:
Average of 12: 56.38

Spoiler

1. (21.58) R2 F2 B2 U R2 L2 F2 B2 U R2 L2 F2 U2 F2 B2 U' B2 L2 B2 U' F2 B2 R2 L2 U2 L2 U2 R2 B2 U B2 R2 L2
2. 1:01.28[p] F2 B2 R2 F2 U2 F2 U' F2 U' B2 R2 L2 B2 U2 L2 U2 R2 L2 F2 L2 F2 U2 F2 U2 L2 F2 U F2 B2
3. 1:12.70 U' F2 R2 L2 F2 U F2 B2 U' L2 U' L2 F2 R2 U2 L2 B2 U F2 L2 U F2 R2 L2 U R2 L2 U2 F2
4. 38.19 R2 L2 F2 B2 U2 R2 F2 B2 R2 L2 B2 R2 F2 U2 R2 B2 U B2 L2 F2 B2 U2 L2 F2 U R2 L2 U' F2 B2 L2 F2 B2
5. 56.42[p] F2 B2 R2 U F2 B2 R2 L2 F2 L2 U2 R2 L2 U2 F2 U L2 B2 U' B2 R2 B2 R2 U F2 U' F2 R2 U
6. 40.18 L2 F2 B2 U2 R2 U L2 U' R2 F2 B2 U2 R2 L2 F2 R2 L2 F2 B2 R2 L2 F2 B2 R2 B2 U' L2 B2 L2 U2 R2 L2 F2
7. 42.62 R2 L2 F2 B2 L2 F2 U R2 L2 U F2 B2 U L2 U' R2 L2 U F2 L2 U2 B2 R2 U' L2 U2 R2 B2 R2 U'
8. 1:06.04+[p] U' R2 L2 F2 B2 R2 L2 U R2 U' F2 U' L2 U' B2 U R2 L2 U2 B2 U B2 U F2 B2 L2 F2 B2 U B2 R2
9. (DNF) L2 U L2 U' R2 U2 B2 R2 L2 B2 R2 L2 U F2 B2 U' R2 L2 U R2 U' R2 L2 F2 B2 L2 U F2 R2 U B2
10. 1:08.71[p] R2 L2 U R2 F2 U2 F2 U R2 L2 F2 B2 U' R2 F2 U' R2 U' R2 U R2 U' L2 U' L2 B2 U' F2
11. 1:10.98[p] B2 U2 F2 R2 L2 F2 U2 R2 L2 U2 F2 L2 F2 U' B2 R2 L2 F2 L2 F2 U' F2 B2 U2 B2 U2 L2 B2 U2
12. 46.69[p] U F2 B2 R2 F2 U R2 U B2 U F2 B2 R2 U2 R2 L2 U R2 L2 U' R2 L2 B2 R2 L2 U L2 B2 L2 U R2

p means PLL-parity in the last step, and that usually takes a lot of time to fix.