• Welcome to the Speedsolving.com, home of the web's largest puzzle community!
    You are currently viewing our forum as a guest which gives you limited access to join discussions and access our other features.

    Registration is fast, simple and absolutely free so please, join our community of 35,000+ people from around the world today!

    If you are already a member, simply login to hide this message and begin participating in the community!

[Help Thread] 4x4 Supercube: Swapping two center cubies diagonally

Joined
May 14, 2019
Messages
2
Likes
0
Thread starter #1
Hello everyone, this is my first post here.

I have encountered the following situation in the image while solving a 4x4 axis cube, but let's just treat it as a super cube.
I would like to ask whether anyone knows of an algorithm that swaps two diagonally opposite cubies on the last center of a 4x4 super cube.
I know the following ones already:
\[ f'\;U'\;(r\;f\;r')\;U'\;(r\;f'\;r')\;U2\;f\;U' \] (Which swaps 2 cubies on the Front face: Bottom Right to Top Right and reversed)
\[ (r\;f'\;r'\;f)\;F\;(f'\;r\;f\;r')\;F\;(r\;f'\;r'\;f)\;F2\;(f'\;r\;f\;r') \] (Which swaps 3 cubies on the Top face: Bottom Right to Top Right, Top Right to Top Left and
Top Left to Bottom Right)

I know one could also use both of these algorithms after eachother, but if there is one to do it directly, I would be very thankful.

Thank you very much
Roman
 

Attachments

Joined
Sep 17, 2009
Messages
901
Likes
45
Location
New Orleans, LA
YouTube
4EverTrying
#2
Hi Roman, welcome to the forum!

First of all I think you meant to write the second algorithm as:
\[ (r\;f'\;r'\;f)\;U\;(f'\;r\;f\;r')\;U\;(r\;f'\;r'\;f)\;U2\;(f'\;r\;f\;r') \]

Second, I'm not sure what the moveset constraint is, as you are applying these algorithms to a puzzle other than the 4x4x4 supercube.

It's very easy to come up with a short algorithm which solves/generates your case directly.
\[f'\;L'\;f\;r2\;f'\;L\;f\;D\;f2\;D'\;f2\;D'\;r2 \]
= Fw' L' Fw Rw2 Fw' L Fw D Fw2 D' Fw2 D' Rw2

or its mirror,
\[f\;R\;f'\;l2\;f\;R'\;f'\;D'\;f2\;D\;f2\;D\;l2 \]
= Fw R Fw' Lw2 Fw R' Fw' D' Fw2 D Fw2 D Lw2



But is there a constraint that we can only have moves <U,r,f>, where r and f must be quarter turns?

Because if not, if you don't like the above, then just a 3 move conjugation of my 12 move adjacent algorithm that you are using is:

\[f\;U\;f'\;f'\;U'\;r\;f\;r'\;U'\;r\;f'\;r'\;U2\;f\;U'\;f\;U'\;f'\]
= Fw U Fw' Fw' U' Rw Fw Rw' U' Rw Fw' Rw' U2 Fw U' Fw U' Fw'

But the bold moves become Fw2, which may violate a constraint that may be in place.

So, are:
  • Half turns (other than U2) allowed?
  • Other turns such as D and L allowed?

EDIT:

Alternatively, I guess the following four move conjugation of the adjacent algorithm you are using will fit the above constraints. So never mind. But I'm still curious to know if there are any constraints.

Rw' U' Rw U'
Fw' U' Rw Fw Rw' U' Rw Fw' Rw' U2 Fw U'
U Rw' U Rw

= Rw' U' Rw U' Fw' U' Rw Fw Rw' U' Rw Fw' Rw' U2 Fw Rw' U Rw

=
\[r'\;U'\;r\;U'\;f'\;U'\;r\;f\;r'\;U'\;r\;f'\;r'\;U2\;f\;r'\;U\;r\]
 
Last edited:
Joined
May 14, 2019
Messages
2
Likes
0
Thread starter #3
Thank you very much Christopher, those were exactly the algorithms I was looking for, they work great.
The 4x4 axis cube has no constraints at all, it is basically just a shape mod of a 4x4 with oriented centerpieces, so Half turns (other than U2) are allowed, as well as other turns such as D and L.
 
Top