Plus X-perm(H perm + U2)
X-perm(H perm + U2)
If he's just solving corners then why would he need the X-perm?
Um, did you try it? it does indeed permute all the corners while leaving the edges solved.
Um, did you try it? it does indeed permute all the corners while leaving the edges solved.
Do an H perm on a 2x2; tell me what happens.
That's why you have to add in a U2. X isn't really a permutation but with the U2, it switches diagonal corners.
That's why you have to add in a U2. X isn't really a permutation but with the U2, it switches diagonal corners.
Why do the H perm in the first place?
what?Do an H perm on a 2x2; tell me what happens.
Because she asked if there were any algorithms that permuted all the correctly oriented corners, and thats one of them. I thought it was somewhat of a joke, because its probably not what she's really looking for, but it does answer the question.Why do the H perm in the first place?
So when you do the U2 afterwards, the corners will be swapped.
So when you do the U2 afterwards, the corners will be swapped.
But if you are solving only corners then you do U2.
Duh. Any other obvious facts you would like to state?
@jtjogobonito, I was going to mention also recommend the U2 + H-perm for the original poster too. Sometimes a beginner does not notice that swapping diagonally opposite corners is like swapping opposite edges, so the poster would want to know H-perm too.
Hi,
are there any algorithms that can solve all 4 corners of the 3x3 cube (3rd layer) once they are oriented correctly?
Thanks
I think the thread has lost its focus abit, anyway,
In the last layer the edges are oriented correctly, and the corners are in a good place but twisted.
in the OLL link I saw these algorithms:
l2 U' R D2 R' U R D2 R
R2 D' R U2 R' D R U2 R
R' U2 R F U' R' U' R U F'
y2 R' F2 R U2 R U2 R' F2 R U2 R'
y2 R2 D R' U2 R D' R' U2 R'
I did one of them and I stayed in the same place
Thanks