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Zane's TuRBo Edge Tutorial

Zane_C

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Need some help with TuRBo.
Scramble: F2 L2 F2 U2 F2 L2 F2 D F' D2 R' F' L D B2 L B' F2 (Only edge scramble)
Do (x2 y). (I scramble with white top green front and solve with yellow top red front.)

I did the first cycle as DL-RB.
The buffer piece was now in place with wrong orientation.
So I broke into a new cycle with BL-RU.
Next cycle: UB-DB.

Now the buffer piece is in 2nd slot, flipped. and the second slot piece is in the buffer's place, with correct orientation.

What is the best way to proceed now?
Just break into a new cycle. You don't need to keep track of what orientation the buffer is in when breaking into a new cycle.

So you could solve the scramble something like this, the bolded letters are where a new cycle is made.

UF>DL>RB
UF>UL>RU
UF>UB>DB
UF>UL>DR
UF>RF>LB
UF>RD>FL
UF>FD>FL
How do you memo edges?
For the first two, I just look where they are and memorise them visually. The remaining edges are memorised by pairing 2 letters and forming a string of one syllable words/sounds.
 

ssb150388

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Huh? I don't understand your question. What do you mean your buffer piece is in 2nd slot? From what I see the next cycle is UL > RU, then DR > RF then you'll have two 2 cycle of edges. Are you asking what should you do now?

If I understand you correctly, then using TuRBo you should just proceed with UF > LB > FL > FD > FL to solve the cube. However if you could also be more freestyle and do x D2 R2 (Z perm) R2 D2

You mean after
I did the first cycle as DL-RB.
The buffer piece was now in place with wrong orientation.
So I broke into a new cycle with BL-RU.
Next cycle: UB-DB.
its UL > RU?
 

ssb150388

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Yes, how did you get BL-RU? If you broke into a new cycle with BL, it would be BL-DR.
My bad.
I tried it now and its UL > RU.
The position was same when I had tried it.. I wrote it incorrectly.
Thanks for your help.
:)

Bdw
UF>DL>RB
UF>UL>RU
UF>UB>DB
UF>UL>DR
UF>RF>LB
UF>RD>FL
UF>FD>FL
Any particular reason for choosing DR?
 
Last edited:

Zane_C

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Parity example solves:

Here are two example solves with parity, both using the same scramble.
-Example 1 will be executing the corners first.
-Example 2 will be executing the edges first.

The solving methods will be TuRBo edges and Old Pochmann corners. (No matter how easy the cases are to freestyle)

Bolded stickers represent breaking into a new cycle. (When the buffer has become solved and there are still unsolved pieces).

Example 1: (corners first)

Scramble in preferred solving orientation: B U' F' U2 B2 F D' F U' F B2 U L D' U2 R L2 B L' R2 D B2 F R2 U'

Corners:
ULB > FUL: - F' D (R U' R' U' R U R' F' R U R' U' R' F R) D' F
ULB > FDR: - R F (R U' R' U' R U R' F' R U R' U' R' F R) F' R'

The buffer is now solved, but this scramble has parity, so ULB and URB need to end up swapped:

ULB > URB: - U (R' U2 R U R' U2' L U' R U L') U'
ULB > DLB: - D F' (R U' R' U' R U R' F' R U R' U' R' F R) F D'
ULB > UFR: - F (R U' R' U' R U R' F' R U R' U' R' F R) F'
ULB > DBR: - R2 F (R U' R' U' R U R' F' R U R' U' R' F R) F' R2
ULB > LFD: - D2 R (R U' R' U' R U R' F' R U R' U' R' F R) R' D2
ULB > DBR: - R2 F (R U' R' U' R U R' F' R U R' U' R' F R) F' R2

UBL and URB are now swapped. If they were NOT swapped, UB and UL would be swapped instead.
This means your edges would be different from how you memorised them!

Edges:
UF > DF > RU: - D' L2 (U L' U' L U M' U' L' U Lw U') L2 D
UF > DL > RD: - L2 R2 (U L' U' L U M' U' L' U Lw U') R2 L2
UF > DB > UB: - B R' L (M U' M' U2 M U' M') L' R B'
UF > RF > LU: - R (M U' M' U2 M U' M') R'
UF > BR > BL: - L (U' R U R U R U' R' U' R') L'

RB is the last edge target. We must set it up to a PLL case, then swap the two edges and corners simultaneously.
An R-perm would be the easiest to set up:

L' E L (L U2 L' U2 L F' L' U' L U L F L2 U) L' E' L

FL is flipped.
Only an even amount of edges can be flipped. So if we have only memorised one flipped edge, the buffer must also be flipped.

Flip FL and UF however you want, one way would be: L' y' R' U2 R2 U R' U' R' U2 r U R U' r' F

----------------------------------------------------------------

Example 2: (edges first)

Scramble in prefered orientation: B U' F' U2 B2 F D' F U' F B2 U L D' U2 R L2 B L' R2 D B2 F R2 U'

Edges:
UF > DF > RU: - D' L2 (U L' U' L U M' U' L' U Lw U') L2 D
UF > DL > RD: - L2 R2 (U L' U' L U M' U' L' U Lw U') R2 L2
UF > DB > UB: - B R' L (M U' M' U2 M U' M') L' R B'
UF > RF > LU: - R (M U' M' U2 M U' M') R'
UF > BR > BL: - L (U' R U R U R U' R' U' R') L'

RB is the last edge target.
As you know, this solve has parity. And this can be fixed similar to the corners:
The edges need to be finished off with UB and UL swapped. (As it's impossible to solve all the edges while keeping the corners is the same permutation).

We will now solve RB, while also swapping UB and UL, by setting up to a Z-perm.

Dw' R (U R' U' R U' R U R U' R' U R U R2 U' R' U) R' Dw

Flip FL and UF however you want, one way would be: L' y' R' U2 R2 U R' U' R' U2 r U R U' r' F

Corners:
ULB > FUL: - F' D (R U' R' U' R U R' F' R U R' U' R' F R) D' F
ULB > FDR: - R F (R U' R' U' R U R' F' R U R' U' R' F R) F' R'
ULB > URB: - U (R' U2 R U R' U2' L U' R U L') U'
ULB > DLB: - D F' (R U' R' U' R U R' F' R U R' U' R' F R) F D'
ULB > UFR: - F (R U' R' U' R U R' F' R U R' U' R' F R) F'
ULB > URB: - U (R' U2 R U R' U2' L U' R U L') U'
ULB > DBR: - R2 F (R U' R' U' R U R' F' R U R' U' R' F R) F' R2
ULB > LFD: - D2 R (R U' R' U' R U R' F' R U R' U' R' F R) R' D2
ULB > DBR: - R2 F (R U' R' U' R U R' F' R U R' U' R' F R) F' R2
 
Last edited:

Zane_C

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I just gave two examples above.
Not trying to promote full freestyle here but the idea of strict TuRBo is very inefficient. TuRBo should only be used for someone transitioning into freestyle as you slowly change your algs to better ones.
I agree that strict TuRBo without any advancements is can be inefficient for a lot of cases, that's why I go through the ways to step up its efficiency.

If you were to put strict TuRBo as "very inefficient", just about any other other restricted method besides freestyle/comms is also very inefficient.
 

amostay2004

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I agree that strict TuRBo without any advancements is can be inefficient for a lot of cases, that's why I go through the ways to step up its efficiency.

If you were to put strict TuRBo as "very inefficient", just about any other other restricted method besides freestyle/comms is also very inefficient.

Yes exactly. Every other method (especially M2) are popular because of their restrictions, so it requires less thinking and is easier to execute braindead. I wouldn't say restricted TuRBo is any better (or even worse) than M2, so if someone would go to the trouble to learn TuRBo, it should be to eventually go into freestyle/comms. There's no reason to go from one restricted method to another if not for this.
 

Zane_C

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Yes exactly. Every other method (especially M2) are popular because of their restrictions, so it requires less thinking and is easier to execute braindead. I wouldn't say restricted TuRBo is any better (or even worse) than M2, so if someone would go to the trouble to learn TuRBo, it should be to eventually go into freestyle/comms. There's no reason to go from one restricted method to another if not for this.

This is my favourite thing about TuRBo, the steady transition into "freestyle". (Unless one chooses to stop at plain old TuRBo).
 
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