# rubik blindfold solve with single algo

Discussion in 'Blindsolving Discussion' started by sankarbhatta, Mar 1, 2012.

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1. ### sankarbhattaMember

3
0
Mar 1, 2012
hi guys,

i am trying to learn blind solve of 3X3. trying to do it by old pochmann method. i saw in pochmann website that we can solve the cube by using a single algo that is T permutation( i know there are J and Y perm we can use to make it faster, but i am not worried abt time right now). i would like to know abt parity cases. there is no mention of parity cases or parity algo in this method. what are the case i will have parity and what algo do i need to use to solve them?

here is the method i am talking about

http://www.stefan-pochmann.info/spocc/blindsolving/3x3_single_alg/old_index.php

thanks
sankar

Last edited: Mar 1, 2012
2. ### aronpmMember

Sep 9, 2009
When you have to solve an odd number of corners, do another T perm which fixes edges and leaves UBR and URF swapped. Solve edges as normal and parity will be solved when you solve the last edge.

Aug 12, 2010
Aberdeen, Scotland
Godmil
EDIT: Darn sorry, I was thinking of the more popular version of Old Pochmann... didn't know there was a one alg version.

[There are actually 3 algs. T perm for edges, Y perm for Corners, and R perm for parity. The idea is when doing T perm edges you're also swapping back and forth two corners, and when doing Y-perm corners, you're also swapping two edges. If there are an uneven number of swaps then the two edges and two corners will need to be corrected (which is done with the R-perm). Badmephisto has a youtube video showing this technique... although his memo system is not recommended.]

Last edited: Mar 1, 2012
4. ### StefanMember

May 7, 2006
WCA:
2003POCH01
StefanPochmann
Makes (the setups) not only faster but also easier.

5. ### sankarbhattaMember

3
0
Mar 1, 2012
hi,

lets take a case i need to do 9 steps for corners and 14 for edges

when i complete 9 steps for corners the edges are swaped , so i do another T perm to set them right but then my corners are swapped

when i execute the 14 steps for edges, which is an even number the corners will remain in swapped position. am i missing something here ?

thanks
sankar

6. ### aronpmMember

Sep 9, 2009
Both numbers have to be even or both numbers have to be odd. You can't get 9 corner targets and 14 edge targets.

7. ### sankarbhattaMember

3
0
Mar 1, 2012
ok so its always both even or both odd irrespective how you scramble the cube.. am i right?