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Probability Thread

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Feb 10, 2019
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Hello

Today this CRAZY thing happened. I first got a green cross skip and the next solve was just a 1 move cross.
I really need the answer to what the odds for this to happen is.
So if your good at math please give me the answer.
Heres the scrambles. btw the scrambles were generated on cstimer so OMG!!!!!!!!!!!!!!!!!!!!!!!!!!!


4. 9.87 L2 D2 R2 D B2 F2 R2 D' F2 D L' R B L' U' F2 L B2 L
5. (8.16) F2 B2 D2 F2 L' F2 R2 U' L' F2 U2 L2 F' U2 L2 B2 U2 B R2 D2
 
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Today this CRAZY thing happened. I first got a green cross skip and the next solve was just a 1 move cross.
I really need the answer to what the odds for this to happen is.
So if your good at math please give me the answer.
The probability of getting two ≤1-move crosses in two specific solves is about (0.05%)^2 ~ 0.000025% ~ 1/4000000.

(Source: CubeZone cross study.)
 
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Hmm......
Thinking thinking thinking.....

If you get two of a specific VLS case in a row in two specific solves, chance is 1/46656

If you get any two VLS case in a row in two specific solves, chance is 1/216

If you get any two VLS case in a row within a session of 216 solves, chance is about (may not be exactly) 1/2

You get widely different numbers even though all of them are the chance of getting a VLS case in two consecutive solves.
1/46656 vs. 1/216 vs. ~1/2
(it doesn’t have to be VLS, I just picked a set where each human case is equally likely)
 
Last edited:
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So i was doing a solve, and when i got to LSE it was all correctly permuted but the UL and BD edges were misoriented. I calculated that the chance of 2 edges being misoriented but permuted and the rest solved to be about 1/940 including aufs. Correct me if im wrong.:p
 
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So i was doing a solve, and when i got to LSE it was all correctly permuted but the UL and BD edges were misoriented. I calculated that the chance of 2 edges being misoriented but permuted and the rest solved to be about 1/940 including aufs. Correct me if im wrong.:p
1/360 chance of correct permutation
15/32 chance of exactly 2 flipped edges
1/768 total.
 
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What are the odds of a single, Ao5 and Ao12 all being the same time? I was just doing a little 3x3 and trying to practice it again, and I got a 15.56 single which helped lead to the Ao5 and Ao12 being the same.

Generated By csTimer on 2019-4-12
avg of 5: 15.56

Time List:
1. 15.18 F' L2 R2 U R2 U' L2 U' F2 D' B2 D' L B2 D2 B F' U2 L' R2 D'
2. (14.62) R' F L2 F U' L' U2 F D' F2 U' R2 B2 L2 U2 L2 D' L
3. 15.93 D2 F2 L2 R U2 L2 F2 L B2 R' U2 D' R' D F' L B L B D2
4. (17.28) L F2 L2 U B2 U' F2 U' R2 B2 L2 D R F L D' R B D F' U'
5. 15.56 D F2 L' B' U F2 D2 R2 L B D L2 D' F2 U F2 L2 F2 R2 D' F2


Generated By csTimer on 2019-4-12
avg of 12: 15.56

Time List:
1. 15.52 F2 L2 F2 R2 D2 F2 R2 D' L2 F2 U2 R' B2 F' L F' D F2 D2 U'
2. (19.56) U' L2 D2 U' L2 U F2 U' F2 L2 U' R' U' B2 L F2 U B' D' U2
3. 17.51 U2 R2 D2 R2 B D2 U2 L' U' B U R B D' L' U' F'
4. 16.58 L2 D2 R' D2 U2 L' R D2 R' D B2 F2 D B2 R F D' B' U'
5. (13.28) L2 F' L2 D2 B2 F' D2 F L2 D2 L' B D F2 R U B' F' L
6. 13.62 U' L2 D' F2 D' B2 R D F' B2 U2 R2 D' F2 U B2 R2 D2 B2 U
7. 13.78 F2 B R' D L' B2 R B' U L' R2 U2 R2 U' R2 B2 D R2 F2 D L2
8. 15.18 F' L2 R2 U R2 U' L2 U' F2 D' B2 D' L B2 D2 B F' U2 L' R2 D'
9. 14.62 R' F L2 F U' L' U2 F D' F2 U' R2 B2 L2 U2 L2 D' L
10. 15.93 D2 F2 L2 R U2 L2 F2 L B2 R' U2 D' R' D F' L B L B D2
11. 17.28 L F2 L2 U B2 U' F2 U' R2 B2 L2 D R F L D' R B D F' U'
12. 15.56 D F2 L' B' U F2 D2 R2 L B D L2 D' F2 U F2 L2 F2 R2 D' F2
 
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What are the odds of a single, Ao5 and Ao12 all being the same time? I was just doing a little 3x3 and trying to practice it again, and I got a 15.56 single which helped lead to the Ao5 and Ao12 being the same.

Generated By csTimer on 2019-4-12
avg of 5: 15.56

Time List:
1. 15.18 F' L2 R2 U R2 U' L2 U' F2 D' B2 D' L B2 D2 B F' U2 L' R2 D'
2. (14.62) R' F L2 F U' L' U2 F D' F2 U' R2 B2 L2 U2 L2 D' L
3. 15.93 D2 F2 L2 R U2 L2 F2 L B2 R' U2 D' R' D F' L B L B D2
4. (17.28) L F2 L2 U B2 U' F2 U' R2 B2 L2 D R F L D' R B D F' U'
5. 15.56 D F2 L' B' U F2 D2 R2 L B D L2 D' F2 U F2 L2 F2 R2 D' F2


Generated By csTimer on 2019-4-12
avg of 12: 15.56

Time List:
1. 15.52 F2 L2 F2 R2 D2 F2 R2 D' L2 F2 U2 R' B2 F' L F' D F2 D2 U'
2. (19.56) U' L2 D2 U' L2 U F2 U' F2 L2 U' R' U' B2 L F2 U B' D' U2
3. 17.51 U2 R2 D2 R2 B D2 U2 L' U' B U R B D' L' U' F'
4. 16.58 L2 D2 R' D2 U2 L' R D2 R' D B2 F2 D B2 R F D' B' U'
5. (13.28) L2 F' L2 D2 B2 F' D2 F L2 D2 L' B D F2 R U B' F' L
6. 13.62 U' L2 D' F2 D' B2 R D F' B2 U2 R2 D' F2 U B2 R2 D2 B2 U
7. 13.78 F2 B R' D L' B2 R B' U L' R2 U2 R2 U' R2 B2 D R2 F2 D L2
8. 15.18 F' L2 R2 U R2 U' L2 U' F2 D' B2 D' L B2 D2 B F' U2 L' R2 D'
9. 14.62 R' F L2 F U' L' U2 F D' F2 U' R2 B2 L2 U2 L2 D' L
10. 15.93 D2 F2 L2 R U2 L2 F2 L B2 R' U2 D' R' D F' L B L B D2
11. 17.28 L F2 L2 U B2 U' F2 U' R2 B2 L2 D R F L D' R B D F' U'
12. 15.56 D F2 L' B' U F2 D2 R2 L B D L2 D' F2 U F2 L2 F2 R2 D' F2
is it even possible to get odds on that? that seems incalculable as someone could just solve before the end and wait till the timer hit a certain number
 
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is it even possible to get odds on that? that seems incalculable as someone could just solve before the end and wait till the timer hit a certain number
That is true that someone could do that (although I am not sure why someone would purposely do that, unless they were bored), but that is not what happened from me and I was just checking to see if there is a way to calculate my questions above. Does anyone have any idea what the probability is (if there is a way to find out)?
 
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That is true that someone could do that (although I am not sure why someone would purposely do that, unless they were bored), but that is not what happened from me and I was just checking to see if there is a way to calculate my questions above. Does anyone have any idea what the probability is (if there is a way to find out)?
Obviously information about the probability distribution of your times is necessary. If each time is 12.00 with probability 1, then obviously all your averages will also be 12.00. If you somehow know your distribution, a Monte Carlo simulation would probably be the best way to compute the probability.
 
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