MEKEX
Member
Yeah that one was already answered 10 years ago lol
oh well
Yeah that one was already answered 10 years ago lol
I'd just rotate twice, actually. You can also try something like (U) Fw R Fw' to set up the pair then U' R' U R to insert; this is equivalent to B U B' but executed differently.What is the best way to solve green orange pair in the back right slot from here?
I am now finding that I tend to just do a R’URU’R’URU2 to just set it up asap, otherwise it seems to be one of those rotate first, set it up then rotate again to insert cases...View attachment 10010
aprende fridrich completo, e treina para que f2l tenha um f2l eficiente, cruze o rosto para baixo e tente tirar muito pouco de oll e pllHelp I'm sub-20 and since I got to sub-25 I can not do less than 20 what I would recommend
okaprende fridrich completo, e treina para que f2l tenha um f2l eficiente, cruze o rosto para baixo e tente tirar muito pouco de oll e pll
I'd solve the orange-blue pair first, because I don't know efficient solutions for most misslotted-F2L cases. I'd probably use one of the following two solutions:What would you do next and how?
Two left slots are done, you can deduce which pieces are the green-orange and blue-orange.
ThanksView attachment 10158
I'd solve the orange-blue pair first, because I don't know efficient solutions for most misslotted-F2L cases. I'd probably use one of the following two solutions:
(ii) R2 U2 R' U2 R2 to insert orange-blue, then U2 F' U' F for orange-green. (This happens to be the optimal solution for solving both slots.)
(i) D R' U2 R D' to insert orange-blue, then y' U' R' U R U' R' U R for orange-green.
R U2 R D' to finish the cross, L' U' L to insert. The pair isn't "fully" preserved by R U2 R D', but it'll still be a three-move insert (which is all that really matters).To complete the cross here, I just need to do R2 then realign.
Is there an easy way to preserve the green orange pair (I know nothing about making x cross)
View attachment 10256
That removes the white-green edge.What about F', R2, F, D'?
R U2 R D' to finish the cross, L' U' L to insert. The pair isn't "fully" preserved by R U2 R D', but it'll still be a three-move insert (which is all that really matters).
That removes the white-green edge.