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Improvements for M2/R2

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Hi Guys, how are you?
I'm working on some improvements for M2... I've adopted an idea of Maky who suggest to use three cycle for the nasty cases where two M edges follow. In his guide he uses commutators. I do instead do that with M.

As you can see with x or x' cube rotations you just need to memo 8-10 algs... wich is not that easy 'cause they are all plenty of M moves. But is not also that hard...most of them are quite short.

Any way the problem is that I would like to find better, more finger friendly algs for UF DB, UB BD and DB UF (shooting form FD) do you know some R based commutator who works for that three cases....that would be great!

Have a nice evaning!

Federico Soldati



UF  DB (U' M2) (R U' R' U) M U') (R U R') (M U)
BU  DB x (U' M2) (R U' R' U) M U') (R U R') (M U)x '
UF ® BU x' (U' M2) (R U' R' U) M U') (R U R') (M U)x

DB  UF U'M'RU'R'UM'U'RUR'M2U
DB  BU x U'M'RU'R'UM'U'RUR'M2Ux'
BU  UF x' U'M'RU'R'UM'U'RUR'M2Ux

BD  UF (U M' U' M) U2 (M U M' U)
DB  UB x (U M' U' M) U2 (M U M' U) x'
UB  FU x' (U M' U' M) U2 (M U M' U) x

UF  BD (U' M U' M') U2 (M' U M U')
UB  DB x (U' M U' M') U2 (M' U M U') x'
FU ® UB x' (U' M U' M') U2 (M' U M U') x

UB  UF (U M U M) U2 (M' U M' U')
DB  FU x' (U M U M) U2 (M' U M' U') x

UF  UB (U M U' M) U2 (M' U' M' U')
FU  DB x (U M U' M) U2 (M' U' M' U') x'

BU  FU (M' U2 M U2)
BD  FU x (M' U2 M U2) x'

FU ® BU (U2 M' U2 M)
FU  BD x (U2 M' U2 M) x'

UB  BD (U' M U M') U2 (M' U' M U')
BD  UB (U M' U M) U2 (M U' M' U)
BD  BU (M U2 M U2) M2
BU  BD M2 (U2 M' U2 M')
 

macky

Premium Member
Joined
Apr 4, 2006
Messages
402
Location
Stanford, CA
WCA
2003MAKI01
Hey Frederico, let me reply to you here. This definitely goes along with my letter-pair-directly-to-alg philosophy. (For people who haven't seen it, here.)

For the cases you mentioned, you could always do something like

UF DB: U'l'x [U'R'U, M] x'LU or r'Ur' [URU', M] rU'r

Eliminating all thinking is the way to go.

[edit] I guess the freestyle people disagree with this. =)
 
Last edited:

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Yeah....I'm still searching good algs for UF->DB (shooting from FD),

For the moment I've decided to change BD-> UB and inverse with the following:

UB  BD U2 (D M' D M') U2 (M' D M' D)
BD  UB (D' M D' M) U2 (M D' M D') U2

Looks good eh? :)

Have a great day.....and come on, propose!
 

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Yeah...I don't know if it is better to do a X or X' cube rotation ora a M or M' move...I think I would prefer the hole cube rotation...anyway what I meant is that If I find a simple UF -> DB alg I then can use it wor the following algs too with just a cube rotation (or M/ M' move):

BU -> DB x A x '
UF -> BU x' A x

Because of that I'm searching a good alg (short and fast) for that case. The problem is that there are few cube solver programs with works with M slice turn also. Maybe Stefan or Somebody with good knowlege of Acube could give it a try and find the best solution for that case...including M slice turns....

Regards,

Federico
 

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Hi Guys, I'm back again.....
So, I've worked out the missing solution...now my algs looks like that:

UF  DB (U' M2) (R U' R' U) (M U') (R U r' U)
BU  DB x (U' M2) (R U' R' U) (M U') (R U r' U) x '
UF ® BU x' (U' M2) (R U' R' U) (M U') (R U r' U) x

DB  UF (U' r U' R' U) (M' U') (R U R') (M2 U)
DB  BU x (U' r U' R' U) (M' U') (R U R') (M2 U) x'
BU  UF x' (U' r U' R' U) (M' U') (R U R') (M2 U) x

BD  UF (U M' U' M) U2 (M U M' U)
DB  UB x (U M' U' M) U2 (M U M' U) x'
UB  FU x' (U M' U' M) U2 (M U M' U) x

UF  BD (U' M U' M') U2 (M' U M U')
UB  DB x (U' M U' M') U2 (M' U M U') x'
FU ® UB x' (U' M U' M') U2 (M' U M U') x

UB  UF (U M U M) U2 (M' U M' U')
DB  FU x' (U M U M) U2 (M' U M' U') x

UF  UB (U M U' M) U2 (M' U' M' U')
FU  DB x (U M U' M) U2 (M' U' M' U') x'

BU  FU (M' U2 M U2)
BD  FU x (M' U2 M U2) x'

FU ® BU (U2 M' U2 M)
FU  BD x (U2 M' U2 M) x'

UB  BD U2 (D M' D M') U2 (M' D M' D)
BD  UB (D' M D' M) U2 (M D' M D') U2
BD  BU (M U2 M U2) M2
BU  BD M2 (U2 M' U2 M')

And of course:

UB s U2 M2 (s) M (s)' M U2 Switch RU and LU
s UB U2 M' (s) M' (s)' M2 U2

UF s M2 (s) M (s)' M
s UF M' (s) M' (s)' M2
s FU (s) M2 (s)' M U2 M U2

DB s M2 (s) M' (s)' M'
s DB M (s) M (s)' M2
s BD (s) M2 (s)' U2 M' U2 M'

The two main algs for UF-> DB and Inverse seems quite long but are actually pretty fast...

I also had another Idea...that could be useful for somebody who whants to keep algs memorisation at the minimum:

For UF-> DB (and Inverse) you could also do "F2 then Alg of UF-> BD and thatn F2 again....

That means that the actual memorization of algs, would become of..about five? If you don'consider the really easy 4 moves one... of course.

I hope that can be useful for you...I don't know if that is gonna be faster than Maky's commutators way...I think so though.....

Have a grat Day!

Federico
 

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Ah, and remember that Instead fo X rotation you can also do M or M'....
What do you think it's better?

Regards,

Federico
 

Freddy88

Member
Joined
Oct 30, 2008
Messages
31
Location
Switzerland
Hi everybody,

so what follow is the last change I did to my special M layer algs...the algs to be learnt are now only 4, yes, just 4!

I still have difficulties during the UB or UF and DB couples with non M layer edges.....like UB RU or LU UB......that seems to be quite time expensive at the moment....some suggestions?

Regards,

Federico

Ah, that's the list:

UF  DB F2 (U M' U' M) U2 (M U M' U) F2
BU  DB M' F2 A F2 M
UF ® BU M F2 A F2 M'

DB  UF F2 (U' M U' M') U2 (M' U M U') F2
DB  BU M' F2 A F2 M
BU  UF M F2 A F2 M'

BD  UF (U M' U' M) U2 (M U M' U)
DB  UB M' A M
UB  FU M A M'

UF  BD (U' M U' M') U2 (M' U M U')
UB  DB M' A M
FU ® UB M A M'

UB  UF (U M U M) U2 (M' U M' U')
DB  FU M A M'
BD  UB M2 A M 2

UF  UB (U M U' M) U2 (M' U' M' U')
FU  DB M' A M
UB  BD M2 A M2

BU  FU (M' U2 M U2)
BD  FU M' A M

FU ® BU (U2 M' U2 M)
FU  BD M' A M

BD  BU (M U2 M U2) M2
BU  BD M2 (U2 M' U2 M')


A stands for the first alg of the triple or couple...I did it with colors.....
 

martijn_cube

Member
Joined
Feb 26, 2008
Messages
467
Location
netherlands, Lisse
WCA
2007BAKK02
YouTube
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These are the two algs i have for BU (buffer DF) when using M2.
But i still don't really like them, i'm currently trying to use the first one.
But is there someone who has a better one?

1) (UR'U') l (U'RU) M2 (U'R'U) l' (URU')

2) (F’ D) R’ (F D’) M2 (D F’) R (D’ F)
 
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