Improvements for M2/R2

Discussion in 'Blindsolving Discussion' started by Stefan, Oct 23, 2007.

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  1. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Hi Guys, how are you?
    I'm working on some improvements for M2... I've adopted an idea of Maky who suggest to use three cycle for the nasty cases where two M edges follow. In his guide he uses commutators. I do instead do that with M.

    As you can see with x or x' cube rotations you just need to memo 8-10 algs... wich is not that easy 'cause they are all plenty of M moves. But is not also that hard...most of them are quite short.

    Any way the problem is that I would like to find better, more finger friendly algs for UF DB, UB BD and DB UF (shooting form FD) do you know some R based commutator who works for that three cases....that would be great!

    Have a nice evaning!

    Federico Soldati



    UF  DB (U' M2) (R U' R' U) M U') (R U R') (M U)
    BU  DB x (U' M2) (R U' R' U) M U') (R U R') (M U)x '
    UF ® BU x' (U' M2) (R U' R' U) M U') (R U R') (M U)x

    DB  UF U'M'RU'R'UM'U'RUR'M2U
    DB  BU x U'M'RU'R'UM'U'RUR'M2Ux'
    BU  UF x' U'M'RU'R'UM'U'RUR'M2Ux

    BD  UF (U M' U' M) U2 (M U M' U)
    DB  UB x (U M' U' M) U2 (M U M' U) x'
    UB  FU x' (U M' U' M) U2 (M U M' U) x

    UF  BD (U' M U' M') U2 (M' U M U')
    UB  DB x (U' M U' M') U2 (M' U M U') x'
    FU ® UB x' (U' M U' M') U2 (M' U M U') x

    UB  UF (U M U M) U2 (M' U M' U')
    DB  FU x' (U M U M) U2 (M' U M' U') x

    UF  UB (U M U' M) U2 (M' U' M' U')
    FU  DB x (U M U' M) U2 (M' U' M' U') x'

    BU  FU (M' U2 M U2)
    BD  FU x (M' U2 M U2) x'

    FU ® BU (U2 M' U2 M)
    FU  BD x (U2 M' U2 M) x'

    UB  BD (U' M U M') U2 (M' U' M U')
    BD  UB (U M' U M) U2 (M U' M' U)
    BD  BU (M U2 M U2) M2
    BU  BD M2 (U2 M' U2 M')
     
  2. KJiptner

    KJiptner Member

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    Nov 17, 2006
    Görlitz, Germany
    WCA:
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    YouTube:
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    Thanks Frederico, I will definitely memorize that stuff :) Nice you've joined the forum
     
  3. macky

    macky Premium Member

    402
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    Apr 4, 2006
    Stanford, CA
    WCA:
    2003MAKI01
    Hey Frederico, let me reply to you here. This definitely goes along with my letter-pair-directly-to-alg philosophy. (For people who haven't seen it, here.)

    For the cases you mentioned, you could always do something like

    UF DB: U'l'x [U'R'U, M] x'LU or r'Ur' [URU', M] rU'r

    Eliminating all thinking is the way to go.

    [edit] I guess the freestyle people disagree with this. =)
     
    Last edited: Nov 17, 2008
  4. Lucas Garron

    Lucas Garron Super-Duper Moderator Staff Member

    Yeah. Which only, like, includes the WR-holder. :p
     
  5. joey

    joey Member

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    Apr 8, 2007
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    Nah, us freestylers are braindead too.
     
  6. deadalnix

    deadalnix Member

    560
    2
    Apr 6, 2007
    WCA:
    2008SECH01
    Why don't you use DR'UR'U'M'URU'r'R2D' ?
     
  7. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Yeah....I'm still searching good algs for UF->DB (shooting from FD),

    For the moment I've decided to change BD-> UB and inverse with the following:

    UB  BD U2 (D M' D M') U2 (M' D M' D)
    BD  UB (D' M D' M) U2 (M D' M D') U2

    Looks good eh? :)

    Have a great day.....and come on, propose!
     
  8. deadalnix

    deadalnix Member

    560
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    Apr 6, 2007
    WCA:
    2008SECH01
    UF -> DB can be done like xDM'R'UR'U'Rr'URU'RD'x'
     
  9. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    yeah....but I want a non-cube turns alg.....cause the moves are gonna be the x turns of that algs...
     
  10. deadalnix

    deadalnix Member

    560
    2
    Apr 6, 2007
    WCA:
    2008SECH01
    You can set up by M' if you want to turn the cube !
     
  11. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Yeah...I don't know if it is better to do a X or X' cube rotation ora a M or M' move...I think I would prefer the hole cube rotation...anyway what I meant is that If I find a simple UF -> DB alg I then can use it wor the following algs too with just a cube rotation (or M/ M' move):

    BU -> DB x A x '
    UF -> BU x' A x

    Because of that I'm searching a good alg (short and fast) for that case. The problem is that there are few cube solver programs with works with M slice turn also. Maybe Stefan or Somebody with good knowlege of Acube could give it a try and find the best solution for that case...including M slice turns....

    Regards,

    Federico
     
  12. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Hi Guys, I'm back again.....
    So, I've worked out the missing solution...now my algs looks like that:

    UF  DB (U' M2) (R U' R' U) (M U') (R U r' U)
    BU  DB x (U' M2) (R U' R' U) (M U') (R U r' U) x '
    UF ® BU x' (U' M2) (R U' R' U) (M U') (R U r' U) x

    DB  UF (U' r U' R' U) (M' U') (R U R') (M2 U)
    DB  BU x (U' r U' R' U) (M' U') (R U R') (M2 U) x'
    BU  UF x' (U' r U' R' U) (M' U') (R U R') (M2 U) x

    BD  UF (U M' U' M) U2 (M U M' U)
    DB  UB x (U M' U' M) U2 (M U M' U) x'
    UB  FU x' (U M' U' M) U2 (M U M' U) x

    UF  BD (U' M U' M') U2 (M' U M U')
    UB  DB x (U' M U' M') U2 (M' U M U') x'
    FU ® UB x' (U' M U' M') U2 (M' U M U') x

    UB  UF (U M U M) U2 (M' U M' U')
    DB  FU x' (U M U M) U2 (M' U M' U') x

    UF  UB (U M U' M) U2 (M' U' M' U')
    FU  DB x (U M U' M) U2 (M' U' M' U') x'

    BU  FU (M' U2 M U2)
    BD  FU x (M' U2 M U2) x'

    FU ® BU (U2 M' U2 M)
    FU  BD x (U2 M' U2 M) x'

    UB  BD U2 (D M' D M') U2 (M' D M' D)
    BD  UB (D' M D' M) U2 (M D' M D') U2
    BD  BU (M U2 M U2) M2
    BU  BD M2 (U2 M' U2 M')

    And of course:

    UB s U2 M2 (s) M (s)' M U2 Switch RU and LU
    s UB U2 M' (s) M' (s)' M2 U2

    UF s M2 (s) M (s)' M
    s UF M' (s) M' (s)' M2
    s FU (s) M2 (s)' M U2 M U2

    DB s M2 (s) M' (s)' M'
    s DB M (s) M (s)' M2
    s BD (s) M2 (s)' U2 M' U2 M'

    The two main algs for UF-> DB and Inverse seems quite long but are actually pretty fast...

    I also had another Idea...that could be useful for somebody who whants to keep algs memorisation at the minimum:

    For UF-> DB (and Inverse) you could also do "F2 then Alg of UF-> BD and thatn F2 again....

    That means that the actual memorization of algs, would become of..about five? If you don'consider the really easy 4 moves one... of course.

    I hope that can be useful for you...I don't know if that is gonna be faster than Maky's commutators way...I think so though.....

    Have a grat Day!

    Federico
     
  13. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Ah, and remember that Instead fo X rotation you can also do M or M'....
    What do you think it's better?

    Regards,

    Federico
     
  14. deadalnix

    deadalnix Member

    560
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    Apr 6, 2007
    WCA:
    2008SECH01
    It seems great ! I will adopt these algs.
     
  15. Jgig1991

    Jgig1991 Member

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    Nov 24, 2008
    Thank you for posting this Stefan. :)
     
  16. Freddy88

    Freddy88 Member

    31
    0
    Oct 30, 2008
    Switzerland
    Hi everybody,

    so what follow is the last change I did to my special M layer algs...the algs to be learnt are now only 4, yes, just 4!

    I still have difficulties during the UB or UF and DB couples with non M layer edges.....like UB RU or LU UB......that seems to be quite time expensive at the moment....some suggestions?

    Regards,

    Federico

    Ah, that's the list:

    UF  DB F2 (U M' U' M) U2 (M U M' U) F2
    BU  DB M' F2 A F2 M
    UF ® BU M F2 A F2 M'

    DB  UF F2 (U' M U' M') U2 (M' U M U') F2
    DB  BU M' F2 A F2 M
    BU  UF M F2 A F2 M'

    BD  UF (U M' U' M) U2 (M U M' U)
    DB  UB M' A M
    UB  FU M A M'

    UF  BD (U' M U' M') U2 (M' U M U')
    UB  DB M' A M
    FU ® UB M A M'

    UB  UF (U M U M) U2 (M' U M' U')
    DB  FU M A M'
    BD  UB M2 A M 2

    UF  UB (U M U' M) U2 (M' U' M' U')
    FU  DB M' A M
    UB  BD M2 A M2

    BU  FU (M' U2 M U2)
    BD  FU M' A M

    FU ® BU (U2 M' U2 M)
    FU  BD M' A M

    BD  BU (M U2 M U2) M2
    BU  BD M2 (U2 M' U2 M')


    A stands for the first alg of the triple or couple...I did it with colors.....
     
  17. martijn_cube

    martijn_cube Member

    467
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    Feb 26, 2008
    netherlands, Lisse
    WCA:
    2007BAKK02
    YouTube:
    kadettv8
    These are the two algs i have for BU (buffer DF) when using M2.
    But i still don't really like them, i'm currently trying to use the first one.
    But is there someone who has a better one?

    1) (UR'U') l (U'RU) M2 (U'R'U) l' (URU')

    2) (F’ D) R’ (F D’) M2 (D F’) R (D’ F)
     
  18. Ville Seppänen

    Ville Seppänen Member

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    Jan 27, 2008
    Finland
    WCA:
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    (U'M')*3 U'M (U'M')*4 (I like MU :))
     
  19. martijn_cube

    martijn_cube Member

    467
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    Feb 26, 2008
    netherlands, Lisse
    WCA:
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    YouTube:
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    wow, thats a really nice one. alot faster then my other two. I like M'U' too.
     
  20. DonQuixote

    DonQuixote Member

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    Jun 1, 2008
    Wels, Austria
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    BU: (0292718) 1-1- (7281019)

    Kind Regards
    Martin
     

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