"A good solve is a work of art that people can look at and be affected in as many ways they're capable of understanding."
-Ubr and Dbr can become interchangeable if you apply the setup move D', therefore the interchanging move will be r2.
-Now you need to find an insertion that will preserve the interchanging layer (r slice in this case). Ubl can be inserted at Dfr by doing [D' l2 D].
-We already know that the interchanging move is r2, so the commutator can now be applied: [ABA'B'] = [D' l2 D] r2 [D' l2 D] r2
The full algorithm including the setup move would be: D' [ABA'B'] D = D' [D' l2 D] r2 [D' l2 D] r2 D
I need some help with my letter pair list, it's almost done.
If you want to help fill in my missing letter pairs, please post them here (you can't edit the document anyway).
Also, what is the best way to go about memorizing letter pairs?
Any help is appreciated.
1 | 5 | 12 | 100 - 6.78 | 10.21 | 11.11 | 11.98
07:35:01 < eddie> dude that 7 year old is so annoying
Has anybody done a 3x3x3 blindfolded with feet before?
In Multi-Blind if you are off by a U turn on 2 different cubes, is it a DNF or something else?
3x3: 9.05/12.54/12.99/14.63. 4x4: 44.23/53.50/55.32/59:45. 3BLD: 1:21.72[35.53].
The most effective way to punish trolls. WARNING: Do not click if epileptic.
How do twisted/flipped pieces fit into your inspection/memorizing process? I'm particularly curious what fast people have to say. I usually take a few seconds at the beginning to look for any of them, but that seems inefficient. (This is for 3cycle types of solving, not that it necessarily matters).
I put this in the one question thread because I know it's been answered here before, and would be satisfied if anyone knows where the earlier discussion went.