PoHos1
Member
what the **** so its wery big lucky
hele půjdeš na facebook můžeme pokecat
hele půjdeš na facebook můžeme pokecat
OMG so lucky, that's almost as lucky as solving a 2x2 by only doing random moves!
How so?This is by far easier to "achieve".
Thanks, that was interesting. Just wondering where you got the number 3 x 10^8 for the number of 20 move optimal cases from?Probablilty of Getting God's Number for an Optimal Solution etc
Thanks, that was interesting. Just wondering where you got the number 3 x 10^8 for the number of 20 move optimal cases from?
What's the probability of taking your cube apart, putting the pieces back in completely randomly, and having the cube be solvable?
Is there some reason this thread was moved (to Speedcubing Help/Questions)?
1/6Probably because people are commonly asking many questions here; like the one I am about to ask.
After OLL/OCLL/WV etc., what is the chance of the corners being solved (counting H-perm as cornered solves, and discounting AUF's)?
1/6
Think of it like this:
1. Pick any corner. Doesn't matter where it is because you're allowing AUFs (at least that's how I'm interpreting your question)
2. The corner to the right of it needs to be a specific piece out of the 3 corners left. So that's 1/3 chance.
3. The next corner needs to be a specific piece out of the the 2 corners last. So that 1/2 chance.
4. Both steps 2 and 3 need to happen for corners to be solved so it's 1/3*1/2=1/6
And people like me will probably ignore this thread from now on.Probably because people are commonly asking many questions here; like the one I am about to ask.
What is the probability of all edges being oriented in a ZZ solve before starting...
with a fully fixed colour scheme?
being fully colour neutral?
I got a 3 move cross on white with all the edges oriented (qqtimer scramble). I wasn't doing ZZ, but it was interesting that I never turned F or B during the solve.
4 of them have a 1/108 probability.
i counted 5. and with 51 having 1/54 probability it should turn out correctly.
on calculating these: one OLL with a certain AUF has 3^3 possibilities for CO (every corner has 3 and the last one is fixed) and 2^3 possibilities for EO (same). that turns out to be 216 OLL cases with a certain AUF. however we dont mind AUF and consider one OLL "equal" with another if U,U',U2 makes them exact same cases. most OLLs look different when doing U,U',U2 so they actually have a chance of 4/216=1/54. (because all 4 possibilities of {(none),U,U',U2} were counted as different cases before) then again there are some that look identical after U2 and therefore have a chance of 2/216=1/108. and even some cases look identical after U,U' and U2 so they have a chance of 1/216.