Jbacboy
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Yeah I was so friggin annoyed, the average could of been really nice. RIP sub-50LOL I heard you complaining about that
Yeah I was so friggin annoyed, the average could of been really nice. RIP sub-50LOL I heard you complaining about that
Has anyone made a chart showing the probabilities of solve times? So you would for example combine the TPS of the best cubers, the number of official solves they do in a year and the probability of certain skips. From this you could calculate the rough probabilities of specific times occurring during the next year.
How many last slot cases are there when all edges and corners are permuted?
How do you account for the (several) rotational symmetries?
What are the probabilities to get 5 PLL skips in a row, doesn't matter the AUF?
Is it 1/440? 22 PLL cases including solved, 4 angles, thus 88, 88*5 is 440. Then why don't I get it so often? Actually I never got that.
Where is my fail?
In 3 solves 2/3 OLLs were the least common OLL (1/216 chance). What is the probability of getting that in 3 solves?
So, let's assume I have solved all of F2L, except for a single edge, which I place in its position, but flipped. What are the chances that all of the remaining pieces are, save for one edge, correctly oriented?
How likely is it to get an all edges oriented OLL? I am not using any sort of edge control or other such tricks.
Given a random state scramble, what is the probability that at least one edge of the CFOP white cross is already solved? By "solved" I mean it has to be next to the white center and oriented correctly, but not necessarily matched up with its corresponding center.
For any individual edge, the probability would be 1/6. 1/3 = probability the edge is in the cross layer, 1/2 = probability the edge is oriented correctly, 1/3 x 1/2 = 1/6. So the probability that at least one of the edges is solved would be 1/6 + 1/6 + 1/6 + 1/6 = 2/3. That seems a bit high. Am I missing something?
Sorry if this question has already been answered but I did a search and couldn't find anything.
It wouldn't matter where the other cross edges were, all that matters is that there is at least one correctly oriented edge in that layer. There could be more than one and they don't have to be correctly permuted relative to each other.What you're looking for is the odds of the first edge being 'solved' plus the odds of the second cross edge being 'solved', etc etc. However, you run up against the problem that the second, third, and fourth cross edges actually have to be really 'solved' relative to the first cross edge.
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