CxLL T R
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T R
The four cases, T R, T L, L R and L B are mirrors and inverses of each other so the same algorithm (8 move commutator) can be used to solve them all.
| As for all T cases you look at two "bars" of stickers, one at Fur-Ful and one at Urb-Ulb, perpendicular to the bars there are two stickers of the same colour and the other two has got opposite colours. |
COLL
- (y') r' U' R U L U' R' U (x)
CLL
- ...
CMLL
- ...
CLLEF
- M' U' R' U' R U r' R2 B' R' B
CF / 2x2x2 (Waterman)
- ...
EG
EG 2 --> 2x2x2
EG 1
- ...
EG 0
- (y) F R' U2 R' U' R U2 F'
Navigator
| CxLL edit |  U |  D |  R |  L |  F |  B |
 U |  U U |  U D |  U R |  U L |  U F |  U B |
 T |  T U |  T D | T R |  T L |  T F |  T B |
 L |  L U |  L D |  L R |  L L |  L F |  L B |
 S |  S U |  S D |  S R |  S L |  S F |  S B |
 -S |  -S U |  -S D |  -S R |  -S L |  -S F |  -S B |
 Pi |  Pi U |  Pi D |  Pi R |  Pi L |  Pi F |  Pi B |
 H |  H U |  H D |  H R |  H L |  H F |  H B |
| Hyper CLL edit | U | D | R | L | F | B |
 U |  U U |  U D |  U R |  U L |  U F |  U B |
 T |  T U |  T D |  T R |  T L |  T F |  T B |
 L |  L U |  L D |  L R |  L L |  L F |  L B |
 S |  S U |  S D |  S R |  S L |  S F |  S B |
 -S |  -S U |  -S D |  -S R |  -S L |  -S F |  -S B |
 Pi |  Pi U |  Pi D |  Pi R |  Pi L |  Pi F |  Pi B |
 H |  H U |  H D |  H R |  H L |  H F |  H B |
