Ollie
Member
With no members?Could someone compile a list of ID with no members? Probably need to spoiler it though.
With no members?Could someone compile a list of ID with no members? Probably need to spoiler it though.
I assume he means list of 4 letter strings with no corresponding WCA ID's, AAAA would be one of them.With no members?
I assume he means list of 4 letter strings with no corresponding WCA ID's, AAAA would be one of them.
library(data.table)
## calculate all possible ID combinations
test <- expand.grid(letters, letters, letters, letters)
test <- paste0(test$Var1, test$Var2, test$Var3, test$Var4)
length(test) # 456976
# used IDs
df <- fread("WCA_export_persons.tsv", select = 1)
df <- unique(substr(df$id, 5,8))
length(df) # 16235
# unused IDs
length(test) - length(df) # 440741
Used to be Nicolas Naing since he only did mega and had a WROut of the people with no nemesis, who has the highest sum of ranks?
HAs there ever been a mbld rank in competition decided by number of cubes missed (ie points and time were the same)?
Out of the people with no nemesis, who has the highest sum of ranks?
Would it suffice to only check the people with 1 nemesis?Or, the other way around:
Out of the people with at least one nemesis, who has the lowest sum of ranks?
Yes, it would.Would it suffice to only check the people with 1 nemesis?
At German Open 2015 I first got a 4/6 mbld and then later the day my first official 3bld, but I think you're asking to have it done in different comps But technically I did so lolHas anyone ever got an official MBLD result before they've had an official BLD solve?
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Has anyone ever got an official MBLD result before they've had an official BLD solve?
After I rethought about this, the answer is no:Would it suffice to only check the people with 1 nemesis?
Me!Has anyone ever got an official MBLD result before they've had an official BLD solve?
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Or, the other way around:
Out of the people with at least one nemesis, who has the lowest sum of ranks?
I thought that if you don't have a rank in an event, for SoR the event is number of participants in that event+1?Isn't this just the slowest 3x3 solver?
I thought that if you don't have a rank in an event, for SoR the event is number of participants in that event+1?