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Thread: The One Answer Question Thread

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    Quote Originally Posted by drewsopchak View Post
    thanks, that helped. I was doing commutators multiple times fro the last 1x5 outer block but the rest I was doing as shown in the video. Any help for the other centers (first four)? Do I do them 1x5 block style or is 3x3x3 block and extending with tredges faster? Also, for 1x1x5 blocks for the first four centers, should I build them in order of innermost, adjacent, outer, other adjacent and then last outer or innermost, both adjacents and then outer? thanks
    3x3 1/5/12/50/100-7.94, 9.70, 10.78, 11.69, 11.91/ 3x3 OH 1/5/12- 12.34, 15.92, 17.21/ 4x4 33.11!!!/ 5x5 1:19/ 6x6 2:55/ 7x7 4:55/sq1- 26/mega 1:13

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    Quote Originally Posted by sa11297 View Post
    Also, for 1x1x5 blocks for the first four centers, should I build them in order of innermost, adjacent, outer, other adjacent and then last outer or innermost, both adjacents and then outer? thanks
    Depends. Just build stuff in whatever order you find to be most efficient based on where pieces are, what pieces have already been paired up, etc.
    3x3: (1/5/12/25/50/100) || 7.08 / 10.18 / 11.21 / 11.65 / 11.81 / 11.95
    4x4: (1/5/12/25/50) || 32.32 / 37.58 / 38.93 / 39.82 / 40.97

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    Member drewsopchak's Avatar
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    Quote Originally Posted by sa11297 View Post
    thanks, that helped. I was doing commutators multiple times fro the last 1x5 outer block but the rest I was doing as shown in the video. Any help for the other centers (first four)? Do I do them 1x5 block style or is 3x3x3 block and extending with tredges faster? Also, for 1x1x5 blocks for the first four centers, should I build them in order of innermost, adjacent, outer, other adjacent and then last outer or innermost, both adjacents and then outer? thanks
    That's up to you. I do middle to outer

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    Can I compete with a magic that has a blank panel? (lost the top left corner paper thingy)

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    check the WCA regulations
    3x3=5.28 single/11.33 of 5/13.75 of 12/14.34 of 50/14.76 of 100

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    Quote Originally Posted by angham View Post
    Step 1: Cross
    Step 2: F2L
    (Both of these steps are exactly the same as Fridrich)
    Step 3: CLL
    Step 4: ELL
    Thanks! But,these algs look hard because the grid is a 4x4 and Its kinda confusinghttp://www.speedsolving.com/wiki/ind...rithms_(3x3x3)I really want to learn this method; I think this method is just like the Snyder method except you don't start with the 2x2 block and then 2x3x3 block
    Last edited by Tj2OY; 07-11-2012 at 09:13 PM.
    3x3: single:16.44;AO5: 21.83;AO12:23.98

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    Quote Originally Posted by CJF2L 1 View Post
    check the WCA regulations
    Doesn't say :\

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    Quote Originally Posted by Samania View Post
    Doesn't say :\
    As long as you show the judge/delegate what the start and end points of your magic solve are, then I'm pretty sure it's ok.
    Mega is mega :3 K4 :D
    Proud Holder of Megaminx UKNR's

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    Quote Originally Posted by Tj2OY View Post
    Thanks! But,these algs look hard because the grid is a 4x4 and Its kinda confusinghttp://www.speedsolving.com/wiki/ind...rithms_(3x3x3)I really want to learn this method; I think this method is just like the Snyder method except you don't start with the 2x2 block and then 2x3x3 block
    The pics show you just the corners, the centre 4 are the top layer then the outer ones are the sides. This isn't how Snyder does it though. He ends on L3C (last 3 corners) which is the opposite way around.
    3X3 Warp 2: (Snl/5/12) 15.26, 18.77, 20.78.

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    penalty if the cube lands on the timer when you stop it? I do this fairly often on pyra because its so short my hands never get far from the timer, and I often drop it and it is sort of half-propped-up on the timer, but I'm not touching it.
    "A mathematician, like a painter or poet, is a maker of patterns." ~G. H. Hardy
    Pyra PBs (1/3/5/12/100): 2.13, 4.08, 4.42, 5.23, 5.91

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