View Poll Results: What is the hardest math you learned?

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  • Calculus (specify in comments)

    38 36.19%
  • Trigonometry

    11 10.48%
  • (Enriched) Geometry

    11 10.48%
  • Equations (specify)

    4 3.81%
  • Graphing Equations (specify)

    2 1.90%
  • Basic Algebra (specify)

    7 6.67%
  • I can do better!

    24 22.86%
  • What kind of math is that?!

    8 7.62%
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Thread: Calculator/Math Thread

  1. #101
    Member ben1996123's Avatar
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    I'm bored. Someone give me a random derivative to do please. No weird functions like Li(x), x!, W(x).
    sim is gay
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  2. #102
    Member tozies24's Avatar
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    Quote Originally Posted by ben1996123 View Post
    I'm bored. Someone give me a random derivative to do please. No weird functions like Li(x), x!, W(x).
    x*sinx*e^x*lnx*cosx
    3x3 - Single: 9.91 5/12/100: 12.67/13.96/14.92

  3. #103
    brah blah's Avatar
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    Quote Originally Posted by Hyrtsi View Post
    I love maths. I've been doing research on my own on various problems and theorems, even came up with something on my own.

    I'd like to see different ways to solve this:

    Proof that

    Quote Originally Posted by y235 View Post
    It's pretty easy.
    Spoiler:
    Quote Originally Posted by Sa967St View Post
    Spoiler:
    I had the same solution as y235 (ninja'd ), but just for lols I'll sub in an x somewhere else.

    x=1+\frac{1}{2+{\frac{1}{1+x}}}

    x=\frac{3x+4}{2x+3}

    2x^2+3x=3x+4

    x^2=2

    x={\sqrt2}
    or
    x=-{\sqrt2}

    assumed convergence fail?

    x = 1 - 1 + 1 - 1 + \cdots \Rightarrow x = 1 - x \Rightarrow x = \frac12 \Rightarrow \text{lololololol}

    moral of the story: you can't just "set some infinite thingy equal to x" without first proving that such an x exists
    Last edited by blah; 03-04-2012 at 05:20 PM.
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  4. #104
    Member vcuber13's Avatar
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    how do you get that?
    Official 3x3 Personal Bests: 11.72, 13.88
    Official Square-1 Personal Bests: 13.15 NR, 15.31

  5. #105
    Member AustinReed's Avatar
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    Hardest for me was basic algebra. Why? I had the teacher that couldn't teach. I suck at math because of him.
    Είμαι λέφτερος.

  6. #106
    Member ben1996123's Avatar
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    'Extended' product rule:

    If y = f(x)g(x)h(x)\cdots with n functions, and where n(x) is the nth function, \frac{dy}{dx}=\sum_{r=1}^{n}\frac{r'(x)y}{r(x)}. It's probably known, but I found it myself today so I thought I'd post it.

    Quote Originally Posted by tozies24 View Post
    y=xsin(x)cos(x)ln(x)e^x
    Spoiler:
    y=abcdf Not using e because e^x
    a=x
    b=sin(x)
    c=e^x
    d=ln(x)
    f=cos(x)
    \frac{dy}{dx}=abcd\frac{df}{dx}+abcf\frac{dd}{dx}+abdf\frac{dc}{dx}+acdf\frac{db}{dx}+bcdf\frac{da}{dx} extended product rule
    \frac{da}{dx}=1
    \frac{db}{dx}=cos(x)
    \frac{dc}{dx}=e^x
    \frac{dd}{dx}=\frac{1}{x}
    \frac{df}{dx}=-sin(x)
    bcdf\frac{da}{dx}=sin(x)cos(x)ln(x)e^x
    acdf\frac{db}{dx}=xcos^2(x)ln(x)e^x
    abdf\frac{dc}{dx}=xsin(x)ln(x)cos(x)e^x
    abcf\frac{dd}{dx}=\frac{xsin(x)cos(x)e^x}{x}=sin(x)cos(x)e^x
    abcd\frac{df}{dx}=-xsin^2(x)ln(x)e^x
    \frac{dy}{dx}=sin(x)cos(x)ln(x)e^x+xcos^2(x)ln(x)e^x+xsin(x)ln(x)cos(x)e^x+sin(x)cos(x)e^x-xsin^2(x)ln(x)e^x
    \frac{dy}{dx}=e^x(sin(x)cos(x)ln(x)+xcos^2(x)ln(x)+xsin(x)ln(x)cos(x) +sin(x)cos(x)-xsin^2(x)ln(x))

    Here's a derivative for someone to do:

    x^{sinh(x+y)}=\frac{2^{ln(xy)}}{y^{csc(x)}}

    Hint: \frac{d}{dx}(sinh(x))=cosh(x), \frac{d}{dx}(cosh(x))=sinh(x)
    Last edited by ben1996123; 03-05-2012 at 12:21 PM.
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  7. #107
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    Pretty good example ben its all simple calculus just lots and lots of it. Will post a solution tomorrow, its 2:54 am atm and ive got lectures tomorrow morning, been teaching some friends how to cube

    Also someone can try \int_{-\infty}^{\infty} \! \frac{x\sin x}{x^2+a^2} \, \mathrm{d} x, a > 0 i.e. the area enclosed by y=\frac{x\sin x}{x^2+a^2} and y=0
    Last edited by samehsameh; 03-05-2012 at 07:01 PM.
    Single/Ao5/Ao12/Ao100 2x2x2: 5.15/8.54/9.46/10.86 3x3x3: 15.32/20.82/22.06/23.27 4x4x4: 2:30.xx/3:4x.xx/??/?? 5x5x5: 5:5x.xx/??/??/??

  8. #108
    Member Sahid Velji's Avatar
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    Twenty people are to travel in a bus from the airport to the hotel at the resort. The bus is designed for use in a tropical climate; it can carry twelve passengers outside and eight inside. If four of the passengers refuse to travel outside and five will not travel inside, in how many ways can the passengers be seated if the combinations of passengers inside or outside is not considered except to take into account these wishes?

    Answer:
    Spoiler:
    330
    Last edited by Sahid Velji; 03-05-2012 at 08:22 PM.
    The wiki! read the FAQ and forum rules. Very useful resources. Post your efforts. Solve blindfolded. Introduce yourself! BB code - Compete! - Ask a question!

  9. #109
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    How can a branch of math be the "hardest" if everything connects to each other? It's like you have a million puzzles pieces, and just as you learn a new branch of math you manage to put together a hundred pieces.... only to find out a thousand more are missing. What's difficult for someone depends on which puzzle pieces are already assembled.
    Spoiler:
    sais the man who hasn't even taken calculus yet :P
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  10. #110
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    Quote Originally Posted by Sahid Velji View Post
    Twenty people are to travel in a bus from the airport to the hotel at the resort. The bus is designed for use in a tropical climate; it can carry twelve passengers outside and eight inside. If four of the passengers refuse to travel outside and five will not travel inside, in how many ways can the passengers be seated if the combinations of passengers inside or outside is not considered except to take into account these wishes?

    Answer:
    Spoiler:
    330
    The answer seems low, and it's not even close to what I thought it was.
    How did you arrive at that?
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