Random Blindfold Cubing Discussion

[Noahaha]

I think he's asking what would you do if one of your always solved edges belongs in DFr, and another of your solved edges belongs in DFl. What then?

That would be a huge problem lol.

[Jaycee]

For UBL -> FRD -> RUB :

f d R2 U' r' F R2 F' y

Probably no good, I just randomly found it by hand xD Yes, I'm aware this must be just another form of a well known alg.

EDIT : I'm just going to use y U L' U' R' U L U' R even though I really like the one I found.

[jonlin]

That would be a huge problem lol.

Shoot to a new cycle.

[Noahaha]

Shoot to a new cycle.

Wouldn't work either, since those edges are supposed to stay foxes so they'll never be paired.

[Jaycee]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

[Noahaha]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

Definitely.

[RyanReese09]

Well half the time, A9 is the fastest one.

[drewsopchak]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

Most of the time, I just perform "A10s"

[Ickathu]

Most of the time, I just perform "A10s"

A10s are almost my favorite. I really like the 14 movers... Yeah...
ULB>RFD>LDF
z2 F R2 U R2 U' R2 D' R2 U R2 U' R2 D F' z2

ULB>RFD>DBL
y2 B D' R2 U R2 U' R2 D R2 U R2 U' R2 B' y2

Better algs por favor?

[Jaycee]

ULB>RFD>LDF
z2 F R2 U R2 U' R2 D' R2 U R2 U' R2 D F' z2

ULB>RFD>DBL
y2 B D' R2 U R2 U' R2 D R2 U R2 U' R2 B' y2

Better algs por favor?

x' [R: [R U' R', D2]] x = x' R2 U' R' D2 R U R' D2 l'

[D: [L2, U R' U']] = D L2 U R' U' L2 U R U' D'