1. Is it boomerang?
I used it for a while after you taught me

2. Originally Posted by Phlippieskezer
- When is a good time to transition into 3-cycle methods? As, in "earlier the better," or should I focus more on my memo at the moment (which still takes 3 - 5 minutes on its own), and learn 3-cycle methods (I'm thinking BH/TuRBo) later, once I can memo a lot faster? (I currently use M2/OP, if that changes anything)
I think your times will drop faster if you focus on your memo before transitioning into a better execution method. Whatever area you think has the most room for improvement, focus on that.

- How does one usually deal with parity when solving the cube BLD using 3-cycles?
If solving corners first: Finish solving the corners (except leave 2 corners swapped), then solve the edges (and the final edge and 2 corners are solved simultaneously with a PLL).

If solving edges first: Pretty much the same thing as above, finish solving the edges (except leave 2 edges swapped), then solve the corners (and the final corners and 2 edges are solved simultaneously with a PLL).

3. For 5x5 (solving with fixed centers and fixed buffers), what is the average number of x-centers and +-centers you need to solve? And about how many if it was pretty bad?

Thanks.

4. Originally Posted by 5BLD
Is it boomerang?
I used it for a while after you taught me
Yes. I have the description wrote you; now I'm re-writing it and adding some nice images.

5. Originally Posted by Julian
For 5x5 (solving with fixed centers and fixed buffers), what is the average number of x-centers and +-centers you need to solve? And about how many if it was pretty bad?
Usually there will be be around 18 centers (either + or x-centers) to solve, this number varies considerably though. Even with a really bad scramble, it's rare to cycle ~24 +/-centers, unless you break into a few cycles. I haven't done 5x5 BLD in a while, so my numbers might be off a bit.

6. Big cubes - wings

Can anyone offer an improvement on this algorithm for the cycle DFl -> BUl -> FDr? Currently using (U R' l2 x') [r' U2 r : D2] (x l2 R U') which is 14 moves long.

Something with an easier set up would be nice.

7. the alg you listed solve DFl -> FDl -> BDl, anyway, if that's the case you mean, i'll probable use [l' : D F' R D' F]

8. the alg you listed solve DFl -> FDl -> BDl
Apologies, should read DFr (usual buffer) -> BUl -> FDl

9. I do U2 r' D2 r' U2 r D2 r' U2 r2 U2

10. Originally Posted by DrKorbin
I do U2 r' D2 r' U2 r D2 r' U2 r2 U2
Interesting still, thanks