My python one-liner scramble generator

[joey]

Odder.. edit your post =D

[Stefan]

Because of this line:
if n != o
you claim o=0 in the beginning, so n cannot be 0 for the first run, therefore you'll never get position 0 (R move) for the first move

Is that some weird Ruby stuff I don't know? I'd say n=m.at(rand(6)) never gets you n=0, just n="R". So that shouldn't be a problem.

[Owen]

I think so, because my original code generated scrambles beginning with R on multiple occasions.

[Odder]

Is that some weird Ruby stuff I don't know? I'd say n=m.at(rand(6)) never gets you n=0, just n="R". So that shouldn't be a problem.

I think so, because my original code generated scrambles beginning with R on multiple occasions.

I'm no good at Ruby Ruby is retarded xD I'was god damn sure that rand(6) generated 0-5 -.-' (I generated like 30 scrambles without a leading R move :O )


EDIT:

Chen Shuang:
Your distribution is wrong..

U->L=25%
D->L=20%

[Stefan]

I'was god damn sure that rand(6) generated 0-5

And it probably does. But the code says n=m.at(rand(6)), not n=rand(6).

[Odder]

And it probably does. But the code says n=m.at(rand(6)), not n=rand(6).

Ohh ****... Can you tell me the best place to hide? (I had already changed his code inside my head when I commented his code... stupid Odder)

[qq280833822]

Its algorithm can be describe as:
generate random moves
and then check it, let RR->R, LL->L, RL->LR, and UD, FB as well
is it really wrong?

[Odder]

Its algorithm can be describe as:
generate random moves
and then check it, let RR->R, LL->L, RL->LR, and UD, FB as well
is it really wrong?

I'm pretty confident that I'm right. But I'm already looking for a place to hide when you prove me wrong.

(a=rand 6)!=b&&a!=b+3

same as:
a!=b and a!=b+3

well, a!=b is obvious..

a!=b+3 can be described like this:
setA=[U,R,F], setB=[D,L,B]
then we have: setA[x]+3=setB[x], where x is the position.
but setB[x]+3 != setA[x].... (as 5+3 != 2)
this means that for any moves in setA, there is 4 valid next-moves, but for setB we have 5.

The goal for the scrambles is to have:
5 valid moves, unless we have just had two opposite moves in a row, then it should be 4

[qq280833822]

why should valid moves of setA be the same as of setB
if we only allow "LR" but disallow "RL", of course setA is difference to setB...

[Odder]

Imagine you have the move R

R doesn't allow the next move to be L, therefore you can't get RL.. (RL is not converted to LR) (which leaves 4 valid moves only)

now take L

L does allow the next move to be R... (5 valid moves, YAY!! )