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Thread: Gifts

  1. #1

    Default Gifts

    If you're not allowed to cut the paper, what's the smallest piece of wrapping paper (by area) that you can use to wrap a standard Rubik's cube that is 57mm on a side?

  2. #2
    Member qqwref's Avatar
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    We're assuming it just has to cover the surface, right? I know how to do it with a square of side length 2 sqrt(2) * 57mm.
    Computer cube PB averages of 12: [Clock: 5.72] [Pyraminx: 3.44] [Megaminx: 49.52]
    [2x2: 2.66] [3x3: 8.71] [4x4: 29.06] [5x5: 52.69] [6x6: 1:34.78] [7x7: 2:20.34]

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    Member guzman's Avatar
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    Quote Originally Posted by qqwref View Post
    We're assuming it just has to cover the surface, right? I know how to do it with a square of side length 2 sqrt(2) * 57mm.
    I also found your solution and a different one that uses a rectangle
    2*57mm x 4*57mm
    and has therefore the same area as yours.
    I've been trying for a while but I couldn't fing anything better.
    I thought this video with very interesting cube unfoldings could be useful ... but I didn't reach any new solutions.

    guzman.
    Last edited by guzman; 08-24-2010 at 01:17 AM.

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    Premium Member Cride5's Avatar
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    It's possible to completely cover the cube with a rectangular strip of paper with dimensions: 7*57mm x 57mm (area of 22743 mm²)

    Spoiler:
    To do it, place the D-face over the centre of the paper strip, wrap each end round the F/B faces, so that they meet on the U-face. Where they meet on the U-face, make a 45° diagonal fold on each end, so that one end folds over towards the L-face, and the other folds over towards the R-face.

    5/6 of the faces are covered with just 1 layer of wrapping paper, and the U-face, is covered with 2 layers.
    3x3(ZZ): a12 16.73, pb 11.22 nl | 2x2(Guimond): a12 5.27, pb 3.40 nl | FM a12 30.1, pb 21
    Or you can just use the Wiki .. or cTimer .. or VisualCube

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    Mm, good point.
    Computer cube PB averages of 12: [Clock: 5.72] [Pyraminx: 3.44] [Megaminx: 49.52]
    [2x2: 2.66] [3x3: 8.71] [4x4: 29.06] [5x5: 52.69] [6x6: 1:34.78] [7x7: 2:20.34]

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    Make sure the person is interested in cubes first, I got my brother an Edison cube, and he gave it away to a friend!
    To wrap it up though, its basically what Cride5 said.
    A rectangle about 400mm x 220mm should do the trick though. (About that size anyways)

  7. #7

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    Very nice solutions so far!

    I think there are some additional solutions not yet considered.

    Cride5's solution is definitely new to me; I had not thought that was possible. I may use as a puzzle in the future.

    I intentionally left the definition of the problem a little vague to see how people riff on it.

  8. #8

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    Quote Originally Posted by qqwref View Post
    We're assuming it just has to cover the surface, right? I know how to do it with a square of side length 2 sqrt(2) * 57mm.
    This solution I came up with quite by surprise about a month ago when trying to wrap a birthday gift for a nephew. My paper was not large enough to wrap it the normal rectangular way. I was very happy when I discovered this trick, and was able to wrap the gift completely and nicely without needing to go to the store and buy new wrapping paper.

  9. #9

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    Using a rectangle, I can get as close to the cube surface area as I want. For example, I can wrap a 10x10x10 using a strip one piece wide and 646 pieces long, that's less than half a side "wasted". In general, for an NxNxN, a strip one piece wide and 6*N*N + 5*N-4 pieces long suffices. For large N, this approaches the cube surface area.
    Last edited by Stefan; 08-28-2010 at 04:22 PM.

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    Member guzman's Avatar
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    Quote Originally Posted by StefanPochmann View Post
    Using a rectangle, I can get as close to the cube surface area as I want. For example, I can wrap a 10x10x10 using a strip one piece wide and 646 pieces long, that's less than half a side "wasted". In general, for an NxNxN, a strip one piece wide and 6*N*N + 5*N-4 pieces long suffices. For large N, this approaches the cube surface area.
    Nice solution !!

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