GuRoux
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- May 6, 2013
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Wojciech Knott got a 6.56 clock average with a counting 5.39 and 7.72... ><
http://cubecomps.com/live.php?cid=831&cat=7&rnd=1
I think it would take a decent amount of practise - the possibility of an F2L edge being in the D layer would hinder lookahead quite a bit, I think...
that's not what he means. i think what he is saying is place two opposite cross edges and put any bottom or top edge in any orientation into the remaining cross slots. then solve 4 f2l pairs.